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34.05 ml of phosphorus vapour weighting …

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34.05 ml of phosphorus vapour weighting 0.0625 g at 54.5degree celcius and 1bar pressure find the molar mass of phosphorus?

    • Posted by Alen Sunny 8 years ago

    CBSE > Class 11 > Chemistry
    • 1 answers

    Priyanshu Pandey 8 years ago

    124.8 g/L as the volume is given 34.05 ml=34.05×10^-3 L. Given mass =0.0625g. Given temperature =546celsius=546+273 Kelvin. Pressure= 1 bar. And R=0.083. Now we know that P×V=m/M×R×T Means M={m×R×T}÷PV M=124.8 g/L Thank you

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