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Install NowNCERT Solutions class 12 Maths Miscellaneous Class 12 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 12 Maths chapter wise NCERT solution for Maths part 1 and Maths part 2 for all the chapters can be downloaded from our website and myCBSEguide mobile app for free.
Download NCERT solutions for Relations and Functions as PDF.
NCERT Solutions class 12 Maths Relations and Functions
1. Let be defined as
Find the function
such that
Ans. Given:
Now and
2. Let be defined as
if
is odd and
if
is even. Show that
is invertible. Find the inverse of
Here, W is the set of all whole numbers.
Ans. Given: defined as
Injectivity: Let be any two odd real numbers, then
Again, let be any two even whole numbers, then
Is is even and
is odd, then
Also, if odd and
is even, then
Hence,
is an injective mapping.
Surjectivity: Let be an arbitrary whole number.
If is an odd number, then there exists an even whole number
such that
If is an even number, then there exists an odd whole number
such that
Therefore, every W has its pre-image in W.
So, is a surjective. Thus
is invertible and
exists.
For :
and
Hence,
NCERT Solutions class 12 Maths Miscellaneous
3. If
is defined by
find
Ans. Given:
=
NCERT Solutions class 12 Maths Miscellaneous
4. Show that the function
defined by
R is one-one and onto function.
Ans. is one-one: For any
R – {+1}, we have
Therefore, is one-one function.
If is one-one, let
R – {1}, then
It is cleat that R for all
R – {1}, also
Because
which is not possible.
Thus for each R – {1} there exists R – {1} such that
Therefore is onto function.
NCERT Solutions class 12 Maths Miscellaneous
5. Show that the function
given by
is injective.
Ans. Let R be such that
Therefore, is one-one function, hence
is injective.
NCERT Solutions class 12 Maths Miscellaneous
6. Give examples of two functions
and
such that
is injective but
is not injective.
(Hint: Consider and
)
Ans. Given: two functions and
Let and
Therefore, is injective but
is not injective.
NCERT Solutions class 12 Maths Miscellaneous
7. Give examples of two functions
and
such that
is onto but
is not onto.
(Hint: Consider and
)
Ans. Let
These are two examples in which is onto but
is not onto.
NCERT Solutions class 12 Maths Miscellaneous
8. Given a non empty set X, consider P (X) which is the set of all subsets of X.
Define the relation AR in P (X) as follows:
For subsets A, B in P (X), ARB if and only if AB. Is R an equivalence relation on P (X)? Justify your answer.
Ans. (i) A A
R is reflexive.
(ii) A B
B
A
R is not commutative.
(iii) If A B, B
C, then A
C
R is transitive.
Therefore, R is not equivalent relation.
9. Given a non-empty set X, consider the binary operation * : P (X) x P (X) P (X) given by A * B = A
B
A, B in P (X), where P (X) is the power set of X. Show that X is the identity element for this operation and X is the only invertible element in P (X) with respect to the operation *.
Ans. Let S be a non-empty set and P(S) be its power set. Let any two subsets A and B of S.
A
B
S
A
B
P(S)
Therefore, is an binary operation on P(S).
Similarly, if A, B P(S) and A – B
P(S), then the intersection of sets
and difference of sets are also binary operation on P(S) and A
S = A = S
A for every subset A of sets
A
S = A = S
A for all A
P(S)
S is the identity element for intersection
on P(S).
10. Find the number of all onto functions from the set {1, 2, 3, ……., } to itself.
Ans. The number of onto functions that can be defined from a finite set A containing elements onto a finite set B containing
elements =
NCERT Solutions class 12 Maths Miscellaneous
11. Let S =
and T = {1, 2, 3}. Find
of the following functions F from S to T, if it exists.
(i) F =
(ii) F =
Ans. S = and T = {1, 2, 3}
(i) F =
(ii)
F is not one-one function, since element and
have the same image 1.
Therefore, F is not one-one function.
NCERT Solutions class 12 Maths Miscellaneous
12. Consider the binary operation * : R x R
R and o = R x R
R defined as
and
R. Show that * is commutative but not associative, o is associative but not commutative. Further, show that
R,
[If it is so, we say that the operation * distributes over the operation o]. Does o distribute over *? Justify your answer.
Ans. Part I: also
operation * is commutative.
Now,
And
Here,
operation * is not associative.
Part II: R
And,
operation
is not commutative.
Now and
Here
operation
is associative.
Part III: L.H.S. =
R.H.S. =
= L.H.S. Proved.
Now, another distribution law:
L.H.S.
R.H.S.
As L.H.S. R.H.S.
Therefore, the operation does not distribute over.
NCERT Solutions class 12 Maths Miscellaneous
13. Given a non-empty set X, let * : P (X) x P (X)
P (X) be defined as A * B = (A – B)
(B – A),
A, B
P (X). Show that the empty set
is the identity for the operation * and all the elements A of P (X) are invertible with A-1 = A. (Hint:
and
)
Ans. For every A P(X), we have
=
And =
is the identity element for the operation * on P(X).
Also A * A = (A – A) (A – A) =
Every element A of P(X) is invertible with
= A.
NCERT Solutions class 12 Maths Miscellaneous
14. Define binary operation * on the set {0, 1, 2, 3, 4, 5} as
Show that zero is the identity for this operation and each element of the set is invertible with
being the inverse of
Ans. A binary operation (or composition) * on a (non-empty) set is a function * : A x A A. We denote
by
for every ordered pair
A x A.
A binary operation on a no-empty set A is a rule that associates with every ordered pair of elements
(distinct or equal) of A some unique element
of A.
* | 0 | 1 | 2 | 3 | 4 | 5 |
0 | 0 | 1 | 2 | 3 | 4 | 5 |
1 | 1 | 2 | 3 | 4 | 5 | 0 |
2 | 2 | 3 | 4 | 5 | 0 | 1 |
3 | 3 | 4 | 5 | 0 | 1 | 2 |
4 | 4 | 5 | 0 | 1 | 2 | 3 |
5 | 5 | 0 | 1 | 2 | 3 | 4 |
For all A, we have
(mod 6) = 0
And and
0 is the identity element for the operation.
Also on 0 = 0 – 0 = 0 *
2 * 1 = 3 = 1 * 2
NCERT Solutions class 12 Maths Miscellaneous
15. Let A = {–1, 0, 1, 2}, B = {–4, –2, 0, 2} and
be the functions defined by
A and
A. Are
and
equal? Justify your answer.
(Hint: One may note that two functions and
such that
A, are called equal functions).
Ans. When then
and
At
and
At
and
At
and
Thus for each A,
Therefore, and
are equal function.
NCERT Solutions class 12 Maths Miscellaneous
16. Let A = {1, 2, 3}. Then number of relations containing (1, 2) and (1, 3) which are reflexive and symmetric but not transitive is:
(A) 1
(B) 2
(C) 3
(D) 4
Ans. It is clear that 1 is reflexive and symmetric but not transitive.
Therefore, option (A) is correct.
17. Let A = {1, 2, 3}. Then number of equivalence relations containing (1, 2) is:
(A) 1
(B) 2
(C) 3
(D) 4
Ans. 2
Therefore, option (B) is correct.
NCERT Solutions class 12 Maths Miscellaneous
18. Let
be the Signum Function defined as
and
be the Greatest Function given by
where
is greatest integer less than or equal to
Then, does
and
coincide in (0, 1)?
Ans. It is clear that and
Consider which lie on (0, # 1)
Now,
And
in (0, 1]
Therefore, option (B) is correct.
NCERT Solutions class 12 Maths Miscellaneous
19. Number of binary operation on the set
are:
(A) 10
(b) 16
(C) 20
(D) 8
Ans. A =
A x A =
= 4
Number of subsets = = 16
Hence number of binary operation is 16.
Therefore, option (B) is correct.
NCERT Solutions class 12 Maths Miscellaneous
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