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Install NowNCERT Solutions class 12 Maths Miscellaneous Class 12 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 12 Maths chapter wise NCERT solution for Maths part 1 and Maths part 2 for all the chapters can be downloaded from our website and myCBSEguide mobile app for free.
Download NCERT solutions for Relations and Functions as PDF.
NCERT Solutions class 12 Maths Relations and Functions
1. Let be defined as Find the function such that
Ans. Given:
Now and
2. Let be defined as if is odd and if is even. Show that is invertible. Find the inverse of Here, W is the set of all whole numbers.
Ans. Given: defined as
Injectivity: Let be any two odd real numbers, then
Again, let be any two even whole numbers, then
Is is even and is odd, then
Also, if odd and is even, then
Hence,
is an injective mapping.
Surjectivity: Let be an arbitrary whole number.
If is an odd number, then there exists an even whole number such that
If is an even number, then there exists an odd whole number such that
Therefore, every W has its pre-image in W.
So, is a surjective. Thus is invertible and exists.
For :
and
Hence,
NCERT Solutions class 12 Maths Miscellaneous
3. If is defined by find
Ans. Given:
=
NCERT Solutions class 12 Maths Miscellaneous
4. Show that the function defined by R is one-one and onto function.
Ans. is one-one: For any R – {+1}, we have
Therefore, is one-one function.
If is one-one, let R – {1}, then
It is cleat that R for all R – {1}, also
Because
which is not possible.
Thus for each R – {1} there exists R – {1} such that
Therefore is onto function.
NCERT Solutions class 12 Maths Miscellaneous
5. Show that the function given by is injective.
Ans. Let R be such that
Therefore, is one-one function, hence is injective.
NCERT Solutions class 12 Maths Miscellaneous
6. Give examples of two functions and such that is injective but is not injective.
(Hint: Consider and )
Ans. Given: two functions and
Let and
Therefore, is injective but is not injective.
NCERT Solutions class 12 Maths Miscellaneous
7. Give examples of two functions and such that is onto but is not onto.
(Hint: Consider and )
Ans. Let
These are two examples in which is onto but is not onto.
NCERT Solutions class 12 Maths Miscellaneous
8. Given a non empty set X, consider P (X) which is the set of all subsets of X.
Define the relation AR in P (X) as follows:
For subsets A, B in P (X), ARB if and only if AB. Is R an equivalence relation on P (X)? Justify your answer.
Ans. (i) A A R is reflexive.
(ii) A B B A R is not commutative.
(iii) If A B, B C, then A C R is transitive.
Therefore, R is not equivalent relation.
9. Given a non-empty set X, consider the binary operation * : P (X) x P (X) P (X) given by A * B = A B A, B in P (X), where P (X) is the power set of X. Show that X is the identity element for this operation and X is the only invertible element in P (X) with respect to the operation *.
Ans. Let S be a non-empty set and P(S) be its power set. Let any two subsets A and B of S.
A B S
A B P(S)
Therefore, is an binary operation on P(S).
Similarly, if A, B P(S) and A – B P(S), then the intersection of sets and difference of sets are also binary operation on P(S) and A S = A = S A for every subset A of sets
A S = A = S A for all A P(S)
S is the identity element for intersection on P(S).
10. Find the number of all onto functions from the set {1, 2, 3, ……., } to itself.
Ans. The number of onto functions that can be defined from a finite set A containing elements onto a finite set B containing elements =
NCERT Solutions class 12 Maths Miscellaneous
11. Let S = and T = {1, 2, 3}. Find of the following functions F from S to T, if it exists.
(i) F =
(ii) F =
Ans. S = and T = {1, 2, 3}
(i) F =
(ii)
F is not one-one function, since element and have the same image 1.
Therefore, F is not one-one function.
NCERT Solutions class 12 Maths Miscellaneous
12. Consider the binary operation * : R x R R and o = R x R R defined as and R. Show that * is commutative but not associative, o is associative but not commutative. Further, show that R, [If it is so, we say that the operation * distributes over the operation o]. Does o distribute over *? Justify your answer.
Ans. Part I: also operation * is commutative.
Now,
And
Here, operation * is not associative.
Part II: R
And,
operation is not commutative.
Now and
Here operation is associative.
Part III: L.H.S. =
R.H.S. = = L.H.S. Proved.
Now, another distribution law:
L.H.S.
R.H.S.
As L.H.S. R.H.S.
Therefore, the operation does not distribute over.
NCERT Solutions class 12 Maths Miscellaneous
13. Given a non-empty set X, let * : P (X) x P (X) P (X) be defined as A * B = (A – B) (B – A), A, B P (X). Show that the empty set is the identity for the operation * and all the elements A of P (X) are invertible with A-1 = A. (Hint: and )
Ans. For every A P(X), we have
=
And =
is the identity element for the operation * on P(X).
Also A * A = (A – A) (A – A) =
Every element A of P(X) is invertible with = A.
NCERT Solutions class 12 Maths Miscellaneous
14. Define binary operation * on the set {0, 1, 2, 3, 4, 5} as
Show that zero is the identity for this operation and each element of the set is invertible with being the inverse of
Ans. A binary operation (or composition) * on a (non-empty) set is a function * : A x A A. We denote by for every ordered pair A x A.
A binary operation on a no-empty set A is a rule that associates with every ordered pair of elements (distinct or equal) of A some unique element of A.
* | 0 | 1 | 2 | 3 | 4 | 5 |
0 | 0 | 1 | 2 | 3 | 4 | 5 |
1 | 1 | 2 | 3 | 4 | 5 | 0 |
2 | 2 | 3 | 4 | 5 | 0 | 1 |
3 | 3 | 4 | 5 | 0 | 1 | 2 |
4 | 4 | 5 | 0 | 1 | 2 | 3 |
5 | 5 | 0 | 1 | 2 | 3 | 4 |
For all A, we have (mod 6) = 0
And and
0 is the identity element for the operation.
Also on 0 = 0 – 0 = 0 *
2 * 1 = 3 = 1 * 2
NCERT Solutions class 12 Maths Miscellaneous
15. Let A = {–1, 0, 1, 2}, B = {–4, –2, 0, 2} and be the functions defined by A and A. Are and equal? Justify your answer.
(Hint: One may note that two functions and such that A, are called equal functions).
Ans. When then and
At and
At and
At and
Thus for each A,
Therefore, and are equal function.
NCERT Solutions class 12 Maths Miscellaneous
16. Let A = {1, 2, 3}. Then number of relations containing (1, 2) and (1, 3) which are reflexive and symmetric but not transitive is:
(A) 1
(B) 2
(C) 3
(D) 4
Ans. It is clear that 1 is reflexive and symmetric but not transitive.
Therefore, option (A) is correct.
17. Let A = {1, 2, 3}. Then number of equivalence relations containing (1, 2) is:
(A) 1
(B) 2
(C) 3
(D) 4
Ans. 2
Therefore, option (B) is correct.
NCERT Solutions class 12 Maths Miscellaneous
18. Let be the Signum Function defined as and be the Greatest Function given by where is greatest integer less than or equal to Then, does and coincide in (0, 1)?
Ans. It is clear that and
Consider which lie on (0, # 1)
Now,
And
in (0, 1]
Therefore, option (B) is correct.
NCERT Solutions class 12 Maths Miscellaneous
19. Number of binary operation on the set are:
(A) 10
(b) 16
(C) 20
(D) 8
Ans. A =
A x A =
= 4
Number of subsets = = 16
Hence number of binary operation is 16.
Therefore, option (B) is correct.
NCERT Solutions class 12 Maths Miscellaneous
NCERT Solutions Class 12 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 12 Maths includes text book solutions from both part 1 and part 2. NCERT Solutions for CBSE Class 12 Maths have total 13 chapters. 12 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 12 solutions PDF and Maths ncert class 12 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide
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