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Install NowNCERT Solutions class 12 Maths Exercise 6.2 Class 12 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 12 Maths chapter wise NCERT solution for Maths part 1 and Maths part 2 for all the chapters can be downloaded from our website and myCBSEguide mobile app for free.
Download NCERT solutions for Applications of Derivatives as PDF.
NCERT Solutions for Class 12 Maths Application of Derivatives
1. Show that the function given by is strictly increasing on R.
Ans. Given:
i.e., positive for all
R
Therefore, is strictly increasing on R.
NCERT Solutions class 12 Maths Exercise 6.2
2. Show that the function given by
is strictly increasing on R.
Ans. Given:
=
> 0 i.e., positive for all
R
Therefore, is strictly increasing on R.
NCERT Solutions class 12 Maths Exercise 6.2
3. Show that the function given by
is (a) strictly increasing
(b) strictly decreasing in
(c) neither increasing nor decreasing in
Ans. Given:
(a) Since, > 0, i.e., positive in first quadrant, i.e., in
Therefore, is strictly increasing in
(b) Since, < 0, i.e., negative in second quadrant, i.e., in
Therefore, is strictly decreasing in
(c) Since > 0, i.e., positive in first quadrant, i.e., in
and
< 0, i.e., negative in second quadrant, i.e., in
and
.
does not have the same sign in the interval
Therefore, is neither increasing nor decreasing in
NCERT Solutions class 12 Maths Exercise 6.2
4. Find the intervals in which the function
given by
is (a) strictly increasing, (b) strictly decreasing.
Ans. Given:
……….(i)
Now
Therefore, we have two intervals and
(a) For interval taking
(say), then from eq. (i),
> 0.
Therefore, is strictly increasing in
(b) For interval taking
(say), then from eq. (i),
< 0.
Therefore, is strictly decreasing in
NCERT Solutions class 12 Maths Exercise 6.2
5. Find the intervals in which the function
given by
is (a) strictly increasing, (b) strictly decreasing.
Ans. (a) Given:
=
……….(i)
Now
or
or
Therefore, we have sub-intervals are and
For interval taking
(say), from eq. (i),
> 0
Therefore, is strictly increasing in
For interval taking
(say), from eq. (i),
< 0
Therefore, is strictly decreasing in
For interval taking
(say), from eq. (i),
> 0
Therefore, is strictly increasing in
Hence, (a) is strictly increasing in
and
(b) is strictly decreasing in
NCERT Solutions class 12 Maths Exercise 6.2
6. Find the intervals in which the following functions are strictly increasing or decreasing:
(a)
(b)
(c)
(d)
(e)
Ans. (a) Given:
……….(i)
Now
Therefore, we have two sub-intervals and
For interval taking
(say), from eq. (i),
< 0
Therefore, is strictly decreasing.
For interval taking
(say), from eq. (i),
> 0
Therefore, is strictly increasing.
(b) Given:
=
……….(i)
Now
Therefore, we have two sub-intervals and
For interval taking
(say), from eq. (i),
> 0
Therefore, is strictly increasing.
For interval taking
(say), from eq. (i),
< 0
Therefore, is strictly decreasing.
(c) Given:
= ……….(i)
Now = 0
or
Therefore, we have three disjoint intervals and
For interval , from eq. (i),
=
< 0
Therefore, is strictly decreasing.
For interval , from eq. (i),
=
> 0
Therefore, is strictly increasing.
For interval , from eq. (i),
=
< 0
Therefore, is strictly decreasing.
(d) Given:
Now
Therefore, we have three disjoint intervals and
For interval ,
Therefore, is strictly increasing.
For interval ,
Therefore, is strictly decreasing.
(e) Given:
Here, factors and
are non-negative for all
Therefore, is strictly increasing if
And is strictly decreasing if
Hence, is strictly increasing in
and
is strictly decreasing in
7. Show that
is an increasing function of
throughout its domain.
Ans. Given:
=
=
=
= ……….(i)
Domain of the given function is given to be
Also and
From eq. (i),
for all
in domain
and
is an increasing function.
8. Find the value of
for which
is an increasing function.
Ans. Given:
[Applying Product Rule]
=
= ……….(i)
Therefore, we have
For taking
(say),
is decreasing.
For taking
(say),
is increasing.
For taking
(say),
is decreasing.
For taking
(say),
is increasing.
9. Prove that
is an increasing function of
in
Ans. Given:
=
=
=
=
Since and we have
, therefore
for
Hence, is an increasing function of
in
10. Prove that the logarithmic function is strictly increasing on
Ans. Given:
for all
in
Therefore, is strictly increasing on
11. Prove that the function
given by
is neither strictly increasing nor strictly decreasing on
Ans. Given:
is strictly increasing if
i.e., increasing on the interval
is strictly decreasing if
i.e., decreasing on the interval
hence, is neither strictly increasing nor decreasing on the interval
12. Which of the following functions are strictly decreasing on
Ans. (A)
Since in
therefore
Therefore, is strictly decreasing on
(B)
Since
therefore
Therefore, is strictly decreasing on
(C)
Since
For
Therefore, is strictly decreasing on
For
Therefore, is strictly increasing on
Hence, is neither strictly increasing not strictly decreasing on
(D)
> 0
Therefore, is strictly increasing on
13. On which of the following intervals is the function
given by
is strictly decreasing:
(A) (0, 1)
(B)
(C)
(D) None of these
Ans. Given:
(A) On (0, 1), therefore
And for
(0, 1 radian) =
> 0
Therefore, is strictly increasing on (0, 1).
(B) For
= = (1.5, 3.1) > 1 and hence
> 100
For
is in second quadrant and hence
is negative and between
and 0.
Therefore, is strictly increasing on
.
(C) On = (0, 1.5) both terms of given function are positive.
Therefore, is strictly increasing on
.
(D) Option (D) is the correct answer.
14. Find the least value of
such that the function
given by
strictly increasing on (1, 2).
Ans.
Since is strictly increasing on (1, 2), therefore
> 0 for all
in (1, 2)
On (1, 2)
Minimum value of
is
and maximum value is
Since > 0 for all
in (1, 2)
and
and
Therefore least value of is
15. Let I be any interval disjoint from
Prove that the function
given by
is strictly increasing on I.
Ans. Given:
……….(i)
Here for every either
or
for
,
(say),
> 0
And for ,
(say),
> 0
> 0 for all
, hence
is strictly increasing on I.
16. Prove that the function
given by
is strictly increasing on
and strictly decreasing on
Ans. Given:
On the interval i.e., in first quadrant,
> 0
Therefore, is strictly increasing on
.
On the interval i.e., in second quadrant,
< 0
Therefore, is strictly decreasing on
.
17. Prove that the function
given by
is strictly decreasing on
and strictly decreasing on 
Ans. Given:
On the interval i.e., in first quadrant,
is positive, thus
< 0
Therefore, is strictly decreasing on
.
On the interval i.e., in second quadrant,
is negative thus
> 0
Therefore, is strictly increasing on
.
18. Prove that the function given by
is increasing in R.
Ans. Given:
for all
in R.
Therefore, is increasing on R.
19. The interval in which
is increasing in:
(A)
(B)
(C)
(D) (0, 2)
Ans. Given:
=
=
In option (D), for all
in the interval (0, 2).
Therefore, option (D) is correct.
NCERT Solutions class 12 Maths Exercise 6.2
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The answers solved by this site is not matching with the NCERT textbook answers. I’m confused which ans, method or procedure I should follow.
Pls sort this problem.
Ans14. -4
Solution is good but try to solve little typically to know question easily