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Install NowNCERT Solutions class 12 Maths Exercise 10.3 Class 12 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 12 Maths chapter wise NCERT solution for Maths part 1 and Maths part 2 for all the chapters can be downloaded from our website and myCBSEguide mobile app for free.
Download NCERT solutions for Vector Algebra as PDF.
NCERT Solutions class 12 Maths Vector Algebra
1. Find the angle between two vectors and
with magnitude
and 2 respectively having
Ans. Given: and
Let be the angle between the vector
and
We know that
= =
2. Find the angle between the vectors and
Ans. Given: Let and
and
Also
= Product of coefficients of + Product of coefficients of
+ Product of coefficients
=
Let be the angle between the vector
and
We know that
= =
3. Find the projection of the vector on the vector
Ans. Let and
Projection of vector and
=
=
=
If projection of vector and
is zero, then vector
is perpendicular to
4. Find the projection of the vector on the vector
Ans. Let and
Projection of vector and
=
=
=
5. Show that each of the given three vectors is a unit vector:
Also show that they are mutually perpendicular to each other.
Ans. Let ……….(i)
……….(ii)
……….(iii)
Each of the three given vectors
is a unit vector.
From eq. (i) and (ii),
=
and
are perpendicular to each other.
From eq. (ii) and eq. (iii),
=
and
are perpendicular to each other.
From eq. (i) and (iii),
=
and
are perpendicular to each other.
Hence, are mutually perpendicular vectors.
6. Find and
if
and
Ans. Given: and
……….(i)
……….(ii)
Putting in eq. (ii),
Putting in eq (i),
7. Evaluate the product
Ans. Given: =
=
=
=
NCERT Solutions class 12 Maths Exercise 10.3
8. Find the magnitude of two vectors
and
having the same magnitude such that the angle between them is
and their scalar product is
Ans. Given: , angle
(say) between
and
is
and their scalar (i.e., dot) product =
Putting and
we have
=
and
NCERT Solutions class 12 Maths Exercise 10.3
9. Find
if for a unit vector
Ans. Given: is a unit vector
……….(i)
Putting from eq. (i),
NCERT Solutions class 12 Maths Exercise 10.3
10. If
and
are such that
is perpendicular to
then find the value of
Ans. Given: ,
and
Now =
Again, =
Since, is perpendicular to
therefore,
.
NCERT Solutions class 12 Maths Exercise 10.3
11. Show that
is perpendicular to
for any two non-zero vectors
and
Ans. Let , where
and
Let
Now
=
=
=
Putting, and
,
= = 0
Therefore, vectors and
are perpendicular ot each other.
NCERT Solutions class 12 Maths Exercise 10.3
12. If
and
, then what can be concluded about the vector
Ans. Given:
Again
0 = 0 for all (any vector
)
Therefore, can be any vector.
NCERT Solutions class 12 Maths Exercise 10.3
13. If
are unit vectors such that
find the value of 
Ans. Since, are unit vectors.
Therefore, and
……….(i)
Also given
Putting the values from eq. (i), we get
NCERT Solutions class 12 Maths Exercise 10.3
14. If either vector
or
then
. But the converse need not be true. Justify your answer with an example.
Ans. Case I: Vector . Therefore by definition of zero vector,
……….(i)
= [From eq. (i)]
Case II: Vector . Therefore by definition of zero vector,
……….(ii)
= [From eq. (ii)]
But the converse is not true.
Justification: Let
Therefore,
Therefore,
Again let
Therefore,
But
Hence, here , but
and
.
NCERT Solutions class 12 Maths Exercise 10.3
15. If the vertices A, B, C of a triangle ABC are
and (0, 1, 2) respectively, then find
Ans. Vertices A, B, C of a triangle are A (1, 2,3 ), B and C (0, 1, 2) respectively.
Position vector of point A =
Position vector of point B =
Position vector of point C =
Now = Position vector of point A – Position vector of point B
=
= ……….(i)
And = Position vector of point C – Position vector of point B
=
= ……….(ii)
Let be the angle between the vectors
and
.
= [Using eq. (i) and (ii)]
NCERT Solutions class 12 Maths Exercise 10.3
16. Show that the points A (1, 2, 7), B (2, 6, 3) and C
are collinear.
Ans. Vertices A, B, C of a triangle are A (1, 2, 7), B (2, 6, 3) and C respectively.
Position vector of point A =
Position vector of point B =
Position vector of point C =
Now = Position vector of point B – Position vector of point A
=
= ……….(i)
And = Position vector of point C – Position vector of point A
=
= ……….(ii)
= 2.
[Using eq. (i)]
Vectors
and
are collinear and parallel.
Thus, points A, B and C are collinear.
And also vectors and
have a common point A and hence can’t be parallel.
NCERT Solutions class 12 Maths Exercise 10.3
17. Show that the vectors
and
form the vertices of a right angled triangle.
Ans. Let the given position vectors be A, B, C.
Position vector of point A is
Position vector of point B is
and Position vector of point C is
= Position vector of B – Position vector of A
=
= =
……….(i)
= Position vector of C – Position vector of B
=
= =
……….(ii)
= Position vector of C – Position vector of A
=
= =
……….(iii)
Adding eq. (i) and (ii),
+
=
+
=
=
[Using eq. (iii)]
Therefore, by Triangle law of addition of vectors, points A, B, C are the vertices of a triangle ABC.
Now from eq. (i) and (ii),
.
=
=
Again from eq. (ii) and (iii),
.
=
= 2 + 3 – 5 = 0
is perpendicular to
.
Angle C is
Therefore
is a right angled at C.
Thus, A, B, C are the vertices of a right angled triangle.
NCERT Solutions class 12 Maths Exercise 10.3
18. If
is a non-zero vector of magnitude
and
is a non-zero scalar, then
is a unit vector if:
(A)
(B)
(C)
(D)
Ans. Given: is a non-zero vector of magnitude
Also given and
is a unit vector.
Therefore, option (D) is correct.
NCERT Solutions class 12 Maths Exercise 10.3
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Best for student
Explained in simple way
Very helpful for students
Easily can understand the method of solving the sums
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Nice it is very helpful for students