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Install NowNCERT Solutions class 12 Maths Exercise 10.3 Class 12 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 12 Maths chapter wise NCERT solution for Maths part 1 and Maths part 2 for all the chapters can be downloaded from our website and myCBSEguide mobile app for free.
Download NCERT solutions for Vector Algebra as PDF.
NCERT Solutions class 12 Maths Vector Algebra
1. Find the angle between two vectors and with magnitude and 2 respectively having
Ans. Given: and
Let be the angle between the vector and
We know that
= =
2. Find the angle between the vectors and
Ans. Given: Let and
and
Also
= Product of coefficients of + Product of coefficients of + Product of coefficients
=
Let be the angle between the vector and
We know that
= =
3. Find the projection of the vector on the vector
Ans. Let and
Projection of vector and =
=
=
If projection of vector and is zero, then vector is perpendicular to
4. Find the projection of the vector on the vector
Ans. Let and
Projection of vector and =
=
=
5. Show that each of the given three vectors is a unit vector:
Also show that they are mutually perpendicular to each other.
Ans. Let ……….(i)
……….(ii)
……….(iii)
Each of the three given vectors is a unit vector.
From eq. (i) and (ii),
=
and are perpendicular to each other.
From eq. (ii) and eq. (iii),
=
and are perpendicular to each other.
From eq. (i) and (iii),
=
and are perpendicular to each other.
Hence, are mutually perpendicular vectors.
6. Find and if and
Ans. Given: and ……….(i)
……….(ii)
Putting in eq. (ii),
Putting in eq (i),
7. Evaluate the product
Ans. Given: =
=
=
=
NCERT Solutions class 12 Maths Exercise 10.3
8. Find the magnitude of two vectors and having the same magnitude such that the angle between them is and their scalar product is
Ans. Given: , angle (say) between and is and their scalar (i.e., dot) product =
Putting and we have
=
and
NCERT Solutions class 12 Maths Exercise 10.3
9. Find if for a unit vector
Ans. Given: is a unit vector ……….(i)
Putting from eq. (i),
NCERT Solutions class 12 Maths Exercise 10.3
10. If and are such that is perpendicular to then find the value of
Ans. Given: , and
Now =
Again, =
Since, is perpendicular to therefore, .
NCERT Solutions class 12 Maths Exercise 10.3
11. Show that is perpendicular to for any two non-zero vectors and
Ans. Let , where and
Let
Now
=
=
=
Putting, and ,
= = 0
Therefore, vectors and are perpendicular ot each other.
NCERT Solutions class 12 Maths Exercise 10.3
12. If and , then what can be concluded about the vector
Ans. Given:
Again
0 = 0 for all (any vector )
Therefore, can be any vector.
NCERT Solutions class 12 Maths Exercise 10.3
13. If are unit vectors such that find the value of
Ans. Since, are unit vectors.
Therefore, and ……….(i)
Also given
Putting the values from eq. (i), we get
NCERT Solutions class 12 Maths Exercise 10.3
14. If either vector or then . But the converse need not be true. Justify your answer with an example.
Ans. Case I: Vector . Therefore by definition of zero vector, ……….(i)
= [From eq. (i)]
Case II: Vector . Therefore by definition of zero vector, ……….(ii)
= [From eq. (ii)]
But the converse is not true.
Justification: Let
Therefore,
Therefore,
Again let
Therefore,
But
Hence, here , but and .
NCERT Solutions class 12 Maths Exercise 10.3
15. If the vertices A, B, C of a triangle ABC are and (0, 1, 2) respectively, then find
Ans. Vertices A, B, C of a triangle are A (1, 2,3 ), B and C (0, 1, 2) respectively.
Position vector of point A =
Position vector of point B =
Position vector of point C =
Now = Position vector of point A – Position vector of point B
=
= ……….(i)
And = Position vector of point C – Position vector of point B
=
= ……….(ii)
Let be the angle between the vectors and .
= [Using eq. (i) and (ii)]
NCERT Solutions class 12 Maths Exercise 10.3
16. Show that the points A (1, 2, 7), B (2, 6, 3) and C are collinear.
Ans. Vertices A, B, C of a triangle are A (1, 2, 7), B (2, 6, 3) and C respectively.
Position vector of point A =
Position vector of point B =
Position vector of point C =
Now = Position vector of point B – Position vector of point A
=
= ……….(i)
And = Position vector of point C – Position vector of point A
=
= ……….(ii)
= 2. [Using eq. (i)]
Vectors and are collinear and parallel.
Thus, points A, B and C are collinear.
And also vectors and have a common point A and hence can’t be parallel.
NCERT Solutions class 12 Maths Exercise 10.3
17. Show that the vectors and form the vertices of a right angled triangle.
Ans. Let the given position vectors be A, B, C.
Position vector of point A is Position vector of point B is and Position vector of point C is
= Position vector of B – Position vector of A
=
= = ……….(i)
= Position vector of C – Position vector of B
=
= = ……….(ii)
= Position vector of C – Position vector of A
=
= = ……….(iii)
Adding eq. (i) and (ii),
+ = + = = [Using eq. (iii)]
Therefore, by Triangle law of addition of vectors, points A, B, C are the vertices of a triangle ABC.
Now from eq. (i) and (ii),
. = =
Again from eq. (ii) and (iii),
. = = 2 + 3 – 5 = 0
is perpendicular to .
Angle C is Therefore is a right angled at C.
Thus, A, B, C are the vertices of a right angled triangle.
NCERT Solutions class 12 Maths Exercise 10.3
18. If is a non-zero vector of magnitude and is a non-zero scalar, then is a unit vector if:
(A)
(B)
(C)
(D)
Ans. Given: is a non-zero vector of magnitude
Also given and is a unit vector.
Therefore, option (D) is correct.
NCERT Solutions class 12 Maths Exercise 10.3
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Best for student
Explained in simple way
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Nice it is very helpful for students