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Kaushik Yadav 4 months, 1 week ago

कविता में किस दौर की बात है? कविता से उस समय के माहौल के बारे में क्या पता चलता है

Akshita Panwar 1 year, 11 months ago

इतवार की सुबह लेखिका अपने मोजे धोने और जूते पॉलिश करने का काम किया करती थी
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Rohit Kumar 2 years, 1 month ago

Caputer ch 9 fill in the balkss
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Krishna 6A 2 years, 2 months ago

dill in the chart giveh below with the terms huhter-those who taxes
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Jgwjdg

Sakshee Mandal 2 years, 1 month ago

How did Ray communicate with him
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Kirti Shukla 5 months ago

Exercise exercise 10.2 class 6 math question number 1 ka answer

Pranav Patil 1 year, 3 months ago

1 1

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30+500

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Exercise 1.1
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Vigyan ki book ka pehla lesson
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Jonyduggal Jonyduggal 2 years, 4 months ago

Math and 7:3ans
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Exercise 11.3 6 question and answer

Akshit Akshit. 2 years, 5 months ago

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Laxman Bisht 3 years, 1 month ago

1chapter

Laxmi Devi 3 years, 2 months ago

Juthe chaturth path Sanskrit Mahotsav ke prashn answer

Laxmi Devi 3 years, 2 months ago

Sanskrit
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Pawan Singh Gaira 3 years, 2 months ago

Why mean in hindi
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Sia ? 2 years, 10 months ago

17

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Shri Ram 3 years, 3 months ago

Good

Gaurav Seth 3 years, 4 months ago

The result of a Mathematics test is as follows:
80, 90, 70, 80, 80, 60, 80, 70, 90, 65, 100, 60, 70, 60, 70, 85, 65, 70, 70, 85, 90, 60, 65, 80, 60
Make a frequency table for the above data and answer the following questions:
(a) What is the maximum marks obtained?
(b) How many students score less than 75 marks?
(c) How many students scored 80 marks or above?
(d) How many students appeared in the test?
Solution:
From the above information, we have the following table.

(a) Maximum marks obtained by a student = 100
(b) 5 + 3 + 6 = 14 students obtained marks less than 75.
(c) 5 + 2 + 3 + 1 = 11 students scored marks 80 or above 80.
(d) Total 25 students were appeared in the test.

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R.A.Nimalan R.A 3 years, 3 months ago

Hi shiram

Gaurav Seth 3 years, 4 months ago

What must be added to 203 to get a number whose digits are reversed of the given number?
Solution:
The number obtained by reversing the digits of 203 = 302.
∴ Difference = 302 – 203 = 99
Hence, the required number is 99.

  • 1 answers

Yogita Ingle 3 years, 4 months ago

 75 cm

1.5 m = 1.5 × 100 = 150 cm

75 : 150 = 75/150 = 3/6 = 1/2

  • 2 answers

Yogita Ingle 3 years, 4 months ago

Yogita Ingle 3 years, 4 months ago

100 paise = 1 Rs

(a) 7 paise = 7 ÷ 100 = 0.07

(b) 625 paise = 625 ÷  100 = 6.25

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