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Arpit Airen 3 years, 6 months ago
I guess you want to find the Particular Solution of the equation {tex}x(x^2-1) {dx \over dy} = 1 \ at\ y =0, x=2{/tex}
{tex}It \ can \ be\ written \ as => x(x^2-1) dx = dy{/tex}
=> {tex}(x^3-x) dx =dy{/tex}
On Integrating both side
{tex}{x^4 \over 4 }- {x^2 \over 2} = y{/tex} + c ....................1
Put x=2 & y=0 in equation 1
c = 2
Now put value of c in 1
{tex}{x^4 \over 4 }- {x^2 \over 2} = y + 2{/tex}
This is the Particular Solution of given differential equation.
Equation 1 is the General Solution of given differential equation.
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Sia ? 3 years, 7 months ago
https://mycbseguide.com/dashboard/textbook/ch/1288/t/1/q/1/m/0/s/0
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Management is a distinct process of planning, organizing, actuating and controlling, performed to determine and accomplish stated objectives with the use of human beings and other resources.
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Sia ? 3 years, 7 months ago
Management is the process by which a co-operative group directs actions of others toward common goals
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