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Ek Kamre Ki lambai 5 metre 4 metre aur unchai 3 metre kramank 74 50 Prati metre per kidhar se is Kamre Ki diwaron per chhat par Safed karane ka Vyakhya kijiye
Sol: Pi ka maan 3.14 ya 22/7 hota hai.
Length = l = 5 m
Breadth = b = 4 m
Height = h = 3 m

Kamray ka prishthiya kshetrafal =

{tex}\huge {=> \ 2\times(l\times b + b\times h+l\times h)}\\ \huge {=> \ 2\times(5\times 4 + 4\times 3+5\times 3)}\\ \huge {=> \ 2\times(20 + 12+15)}\\ \huge {=> \ 2\times47}\\ \huge {=> \ 94 \ m^2}\\{/tex}

Chhat ka kshetrafal =

{tex}\huge {=> \ l\times b}\\ \huge {=> \ 5\times 4}\\ \huge {=> \ 20 \ m^2}\\{/tex}
Safed rang karne ka kul kshetrafal = 94 + 20 = 114 m².

Safed rang karwane ka kul mulya ya kharcha = 114 x 74.50 Rs. = {tex}\Large {\boxed{8493 Rs.}}{/tex}

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Ajeet Bainsla Gurjar 4 years, 2 months ago

Ek Kamre Ki lambai 5 metre 4 metre aur unchai 3 metre kramank 74 50 Prati metre per kidhar se is Kamre Ki diwaron per chhat par Safed karane ka Vyakhya kijiye

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ANSWER

Mathka 13.5 ka saval

Posted by Vivek Sharma 4 years, 2 months ago

UP Board > Class 09 > गणित

0 answers

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X+1

Posted by Jhubar Ram 4 years, 2 months ago

UP Board > Class 09 > गणित

0 answers

ANSWER

2+4

Posted by Himanshu Yadav 4 years, 3 months ago

UP Board > Class 09 > गणित

2 answers

Rohit Maurya 4 years, 3 months ago

2Thank You

Vivek G.S. 4 years, 3 months ago

Add 6 and 4 7. 7

3Thank You

ANSWER

The cost of notebook is twice the cost of pen. Write a linear equation in two variables to represent this statement

Posted by Royãl Goldy 4 years, 3 months ago

UP Board > Class 09 > गणित

1 answers

Rajan Kumar Pasi 3 years, 11 months ago

Sol: Let the cost of a notebook = x Rs.
Let the cost of a pen = y Rs.
Thus, according to the question:

Cost of notebook = twice the cost of pen
x = 2 x y
Ans => {tex}\huge \boxed {x = 2y }{/tex}

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ANSWER

Maths Hindi

Posted by Lakhan Singh 4 years, 4 months ago

UP Board > Class 09 > गणित

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15*(_16)

Posted by Aman Varya 4 years, 6 months ago

UP Board > Class 09 > गणित

1 answers

Abhishek Yadav 4 years, 6 months ago

Chaturburj abcd me ac ,ad hai or ab kod a ko

3Thank You

ANSWER

3x-2x=6

Posted by Zaid Turki 4 years, 6 months ago

UP Board > Class 09 > गणित

3 answers

Atish Yadav 4 days, 9 hours ago

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0Thank You

Kanhaiyabhaiyakingstar Yadavji 4 years, 6 months ago

Hai

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Yogita Ingle 4 years, 6 months ago

3x - 2x = 6
x = 6

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ANSWER

Right angle

Posted by Krishna Kaithwas 4 years, 6 months ago

UP Board > Class 09 > गणित

0 answers

ANSWER

what is the value of (sin theta+cos teta /si^theta

Posted by Lima Unni 4 years, 6 months ago

UP Board > Class 09 > गणित

0 answers

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How do polynomial

Posted by Lucky Chaudhary 4 years, 6 months ago

UP Board > Class 09 > गणित

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ACCORDING TO THE WATER CHARGE RATE , MINIMUM CHARGE UP TO 27 UNITS IS RS 1910 AND 71 PER UNIT EXCEEDING 27 UNITS. Nikhil PAID THE WATER BILL OF BHADRA MONTH RS 28,363.20 INCLUDING 20 percent fine. if THE PRESENT READING ON THE BILL IS 4,777 THEN FIND THE FORMER READING.

Posted by Un Known 4 years, 6 months ago

UP Board > Class 09 > गणित

2 answers

Rajan Kumar Pasi 3 years, 11 months ago

Sol: Let the no. of extra units = x
Thus,

{tex}\text {Let the original bill = y Rs.}\\ \text {Therefore, Original amount+ 20% fine = 28363.20}\\ \text {=> y + 20% of y = 28363.20}\\ \text {=> y + }{\frac{20}{100}}\times \text{ y = 28363.20}\\ \text {=> }{\frac{120}{100}}\times \text{ y = 28363.20}\\ \text {=> }{\frac{6}{5}}\times \text{ y = 28363.20}\\ \text {=> }\text{ y = }{28363.20\times {\frac{6}{5}}}\\ \text {=> y = }\boxed{23636 Rs.}\\ Now, {=> \ 1910 + 71\times x = 23636}\\ {=> \ 71\times x = 23636-1910}\\ {=> \ 71\times x = 21726}\\ {=> \ x = \frac{21726}{71}}\\ {=> \ x = \boxed{306}}\\{/tex}

So, the Former reading of the meter was = 4777 - 306 = {tex}\huge {\boxed{4471} \ units.} \\ All \ the\ best\ :-)...{/tex}

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Arpita Dixit Dixit 4 years, 6 months ago

Yy8

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ANSWER

25553÷ 17622

Posted by Md Zafar Husain 4 years, 7 months ago

UP Board > Class 09 > गणित