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Ask QuestionPosted by Uday Gowda M 3 years, 9 months ago

- 2 answers

Gaurav Seth 3 years, 9 months ago

The degree measure of 1 radian (taking π = (22 / 7)) is **57°16’22” (approx.)**

π = radian = 180°

∴ 1 radian = | <center>180°</center> | |

π |

= | <center>180 × 7°</center> | |

22 |

= | <center>630</center> | = 57 | <center>3</center> | ° | |

11 | 11 |

= 57° | <center>3</center> | × 60" = 57° | <center>180'</center> | ||

11 | 11 |

= 57°16' | <center>4</center> | × 60" = 57°16'22" |

Posted by Dhiya Praveena 3 years, 10 months ago

- 2 answers

Posted by Srikant Khuntia 3 years, 10 months ago

- 1 answers

Yogita Ingle 3 years, 10 months ago

Newton’s laws of motion imply the relationship between an object’s motion and the forces acting on it. In the first law, we come to understand that an object will not change its motion unless a force acts on it. The second law states that the force on an object is equal to its mass times its acceleration. And, finally, the third law states that for every action, there is an equal and opposite reaction.

**What are some daily life examples of Newton’s 1st, 2nd and 3rd laws of motion?**

Riding a bicycle is a good example of Newton’s 2nd law. In this example, the bicycle is the mass. The leg muscles pushing on the pedals of the bicycle is the force.

- The motion of a ball falling through the atmosphere, or a model rocket being launched up into the atmosphere are both excellent examples of Newton’s 1st law.
- You hit a wall with a certain amount of force, and the wall returns that same amount of force. This is an example of Newton’s 3rd law.

Posted by Khan Khan 3 years, 11 months ago

- 3 answers

Nishant Sharma 3 years, 4 months ago

Yogita Ingle 3 years, 11 months ago

- Velocity: Velocity is the speed of an object moving in a definite direction.
- The SI unit of velocity is also metre per second.
- Velocity is a vector quantity; it has both magnitude and direction.

Posted by Tanu Kamble 3 years, 11 months ago

- 2 answers

Shivam Yadav 3 years, 11 months ago

Gaurav Seth 3 years, 11 months ago

Consider a parallel plate capacitor without any dielectric medium (vacuum) between the plates. Let A be the area of the plates and d be the plate separation. The two plates have charges Q and – Q. Since d is much smaller than the linear dimension of the plates (d^{2} << A),

Plate 1 has surface charge density σ = Q/A and plate 2 has a surface charge density – σ. Using earlier result of the electric field in different regions is: Outer region I (region above the plate 1),

Outer region II (region below the plate 2),

In the inner region between the plates 1 and 2, the electric fields due to the two charged plates add up, giving

The direction of electric field is from the positive to the negative plate. Thus, the electric field is localised between the two plates and is uniform throughout. For plates with finite area, this will not be true near the outer boundaries of the plates. The field lines bend outward at the edges – an effect called **‘fringing of the field’**. Hence σ will not be strictly uniform on the entire plate.

However, for d^{2} << A, these effects can be ignored in the regions sufficiently far from the edges, and the field there is given by Eq. (1). Now for uniform electric field, potential difference is simply the electric field times the distance between the plates, that is,

The capacitance C of the parallel plate capacitor is then

which, as expected, depends only on the geometry of the system.

Posted by Gulshan Kumar 4 years ago

- 4 answers

Ziya Rehaman 3 years, 8 months ago

Paritosh Dansena 3 years, 11 months ago

Gaurav Seth 4 years ago

**Dimensions** of a physical quantity are powers (exponents) to which base quantities are raised to represent that quantity. They are **represented by square brackets** around the quantity.

- Dimensions of the 7 base quantities are – Length [L], Mass [M], time [T], electric current [A], thermodynamic temperature [K], luminous intensity [cd] and amount of substance [mol].

Force = Mass x Acceleration = [M][L]/[T]^{2} = [MLT^{-2}]

Posted by Arru Sinha 4 years ago

- 1 answers

Sia ? 3 years, 5 months ago

Posted by Deeksha Dev.J 4 years, 1 month ago

- 3 answers

Posted by David ......... 4 years, 1 month ago

- 1 answers

Nishant Sharma 3 years, 4 months ago

Posted by Yogitha Cr 4 years, 3 months ago

- 5 answers

Posted by Sai Gujar 4 years, 3 months ago

- 4 answers

Venkatesh Gorkals 2 years, 7 months ago

Raghavendra Illale 4 years, 1 month ago

Yogita Ingle 4 years, 3 months ago

**Ohm’s Law**

- Ohm’s law is named after the scientist Ohm who gave this law.
- According to the Ohm’s law current flowing through a conductor is directly ∝ to the potential difference applied between the ends of the conductor.
- This means if the potential difference applied at the ends increases then the current flowing through the conductor also increases and vice-versa.
- Mathematically
- Current flowing through the conductor I ∝ V where V is the potential difference applied at the ends of the conductor.
- Or I=(constant) V where constant = 1/R where R =resistance of the conductor
- => I=(1/R)V
- =>
**V=IR**

Posted by Pappu Yadav 4 years, 4 months ago

- 1 answers

Posted by Pragnya Saswati 4 years, 5 months ago

- 5 answers

Posted by Uday Jha 4 years, 6 months ago

- 5 answers

Manav Malhotra 4 years, 5 months ago

Posted by Shraddha Jha 4 years, 7 months ago

- 2 answers

Prikshit Bishnoi 4 years, 6 months ago

Rishita Punia 4 years, 6 months ago

Posted by Zikra Raza 4 years, 7 months ago

- 0 answers

Posted by Seema Devi 4 years, 8 months ago

- 1 answers

Yogita Ingle 4 years, 8 months ago

Relative error is defined as the ratio of the absolute error of the measurement to the actual measurement. Using this method we can determine the magnitude of the absolute error in terms of the actual size of the measurement. If the true measurement of the object is not known, then the relative error can be found using the measured value. Relative error gives an indication of how good a measurement is relative to the size of the object being measured.

If x is the actual value of a quantity, x_{0} is the measured value of the quantity and Δx is the absolute error, then the relative error can be measured using the below formula.

Relative error = (x_{0}-x)/x = (Δx)/x

An important note that relative errors are dimensionless. When writing relative errors it is usual to multiply the fractional error by 100 and express it as a percentage.

Posted by Pratibha Yadav 4 years, 9 months ago

- 1 answers

D Bulliyya 4 years, 8 months ago

Y=a sinkx coswt a is the amplitude k is the propagation constant x is the displacement w is the angular frequency t is the time

Posted by Sakharam Wayal 4 years, 9 months ago

- 5 answers

Jayesh Sharma 4 years, 8 months ago

Posted by Rumi Roy 4 years, 10 months ago

- 0 answers

Posted by Ragavan Rengamannar 4 years, 10 months ago

- 1 answers

Posted by Anita Kumari 4 years, 10 months ago

- 2 answers

Kurai Dodiya Gohil 4 years, 5 months ago

Posted by Rahul Kumar 4 years, 11 months ago

- 0 answers

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Aditiya Kumar 3 years, 9 months ago

1Thank You