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  • 1 answers

Rigved Tripathi 6 years, 7 months ago

Polarity which define the charge is +ve or -ve question is pending...
  • 1 answers

Yogita Ingle 6 years, 7 months ago

Faraday’s constant is defined as the amount of charge required to liberate a gram equivalent of a substance during the process of electrolysis.
It is total charge on 1 mole of electrons. It is unit of charge.
1 F = 6.023 × 1023 × 1.6023 ×  10-19 C = 96500 C

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Pulkit Bansal 6 years, 7 months ago

circular motion is a movement of an object along the circumference of a circle or rotation along a circular path. It can be uniform, with constant angular rate of rotation and constant speed, or non-uniform with a changing rate of rotation.

Ajeet Kumar 6 years, 7 months ago

When a body movies in circular path that motion is called circular motion
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Pulkit Bansal 6 years, 6 months ago

Answer is 3 nd -1.

Rigved Tripathi 6 years, 7 months ago

Aman Kumar 2 vector is given Aur triple product... Naaaa

Aman Kumar 6 years, 7 months ago

Use scalar triple product.A=2
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Manu Maurya 6 years, 6 months ago

For chemistry it is 50 percent sufgicient but for others it may be 5 percent sufficient approx

Pulkit Bansal 5 years, 6 months ago

No

Khalid Saifullah 6 years, 7 months ago

Yes
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Manu Maurya 6 years, 6 months ago

velocity is ratio of displacement to time not distance to time distance and displacemaent have a difference it is this difference which make spped and velocity differ

Raj Kushwaha 6 years, 7 months ago

The ratio of distance and time taken is called velocity
  • 1 answers

Sourabh Sheokand 6 years, 6 months ago

Cosec^2r.sec^2r +1
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Abhay Gupta 6 years, 7 months ago

5√5

Anil Dalal 6 years, 7 months ago

5

Prajesh Shelke 6 years, 7 months ago

1

Yogita Ingle 6 years, 7 months ago

√45- 3√20+ 4√5
= √9×5 - 3√5×4 + 4√5
= 3√5 - 6√5 + 4 √5
= (3 - 6 + 4) √5
= √

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Javis Kumar 5 years, 6 months ago

Justis
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Pulkit Bansal 6 years, 7 months ago

There r many different values of x nd y that satisfies 3x-y=12.
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Pulkit Bansal 6 years, 7 months ago

a^3 + b^3 + c^3 + 3(a+b)(b+c)(a+c)
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Septima Ravenclaw 6 years, 7 months ago

(secx )^2

Ashu Tyagi 6 years, 7 months ago

secxtanx
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Pulkit Bansal 6 years, 7 months ago

Diameter of sphere=d New sphere=D So, D=d-20% of d D=d-20d/100 D=d-4d/20 D=4d/5 S.A. of old sphere= 4π(d/2)^2 = πd^2 S.A of new sphere= 4π[(4d/5)/2]^2 = (16πd^2)/25 % of area decrease = 【{πd^2 - (16πd^2)/25}/πd^2】×100 = 36%
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Gaurav Seth 6 years, 8 months ago

  • Yeasts

A unicellular fungus which includes baker's yeast. Yeast can also be found in pharmacies as probiotic which can help prevent diarrhea. There is also yeast that can be damaging to the human body. When present in the mouth, esophagus, bowel and ******, it can cause yeast infections in people with low immune systems. If it invades the blood yeast can be fatal

  • Mushrooms

    A fleshy, spore-bearing fruiting body of a fungus, typically produced above ground on soil or on its food source. It typically consists of a stem, cap and gills. Some are harmful and some are not. Some mushrooms are edible and have successfully been cultivated for human consumption. A mushroom develops from a nodule, or pinhead, less than two millimeters in diameter. Many species of mushrooms seemingly appear overnight, growing or expanding rapidly. In reality all species of mushrooms take several days to form primordial mushroom fruit bodies, though they do expand rapidly by the absorption of fluids.

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Ayush Mishra 6 years, 4 months ago

1 Gram atomic Mass

Pulkit Bansal 6 years, 7 months ago

6.022×10^23
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Abhay Gupta 6 years, 7 months ago

99.85

Jaswant Mehta 6 years, 8 months ago

your percentile does not depends on your Mark's It depends on that how much student got marks more than you
  • 1 answers

Kundan Kumar 6 years, 7 months ago

O p tandon for physical and ms chauhan for oraganic and j d lee for inorganic
  • 1 answers

Jaswant Mehta 6 years, 8 months ago

Joint Entrance Examination (JEE) is an engineering entrance examination conducted for admission to various engineering colleges in India. It is constituted by two different examinations - JEE Main and the JEE Advanced. The exams are of the objective pattern. JEE Advanced is regarded internationally as one of the most challenging undergraduate admission tests. In 2012, the government-run Central Board of Secondary Education (CBSE) that earlier conducted the AIEEE, announced the JEE that replaced the AIEEE and IIT-JEE. The JEE-Main, which replaces AIEEE, is for admission to the National Institutes of Technology (NITs), Indian Institutes of Information Technology (IIITs), and some other colleges designated as "centrally funded technical institutes" (CFTIs) The JEE-Advanced, which replaces IIT-JEE, is for admission to the Indian Institutes of Technology (IITs). Only the students selected in JEE Mains are eligible for appearing in JEE Advanced. About 224,000 students will be selected from 2018. There are some institutes like the Indian Institutes of Science Education and Research (IISERs), Rajiv Gandhi Institute of Petroleum Technology, and the Indian Institute of Science which use the score obtained in JEE Advanced as the basis for admission. These are not participating institutes of central IIT JEE Advanced counseling of which all IITs are members. Any student who takes admission to IITs cannot appear for the JEE-Advanced exam in the next year, but the same is not the case with IISc, IISER, RGIPT and other institutes as these institutes only use JEE Advanced score for admission. In September 2013, the IIT Council approved the decision of the Joint Admission Board to continue with the two-phase JEE pattern ("Main" followed by "Advanced") for IITs in 2014. Joint Seat Allocation Authority (JoSAA) conducted the joint admission process for a total of 23 IITs, ISM, 32 NITs, 18 IIITs and 19 other Government Funded Technical Institutes (GFTIs). As per the reports from Ministry of Human Resource Development (MHRD) of Government of India, the government is considering to conduct only one common engineering entrance test based on the lines of NEET for all engineering colleges, including private institutions, across India. JEE Main Edit Main article: Joint Entrance Examination – Main JEE Main has two papers, Paper-1 and Paper-2. Candidates may opt for either or both of them. Both papers contain multiple choice questions. Paper 1 is for admission to B.E./B.Tech courses and is conducted only online. Paper-2 is for admission in B.Arch and B.Planning courses and is conducted offline only. JEE Main, unlike JEE Advanced, has a fixed exam structure and is not subject to change every year. Paper-1 is of three hours duration and consists of thirty multiple-choice (single-correct) questions in each of the three subjects (physics, chemistry, and maths). There is negative marking for incorrect answers. 4 marks are awarded for correct answers and 1 mark is deducted for incorrect answers. From 2013 to 2016, the marks obtained in the class XII school board examination used to be accorded a 40% weightage in deciding the JEE Main all India ranks. From 2017, CBSE made Aadhar card mandatory for students applying for JEE. Students not having the card were asked to register for it before applying for JEE. From 2019, JEE Main will be conducted two times in a year and it will be conducted by National Testing Agency (NTA). Number of applicants by year Edit The number of applicants taking the JEE Main has varied over the years. In 2016, fewer aspirants registered as compared to the previous three years as shown in the table below.1.3 million candidates appeared for JEE Main in 2014. Year No. of Students 2017 1,186,454 Decrease 2016 1,194,938 Decrease 2015 1,304,495Decrease 2014 1,356,805Increase 2013 1,282,000Increase 2012 479,651 JEE Advanced Edit Main article: Joint Entrance Examination – Advanced Students who qualify JEE-Main can appear for the JEE-Advanced examination. In 2018, 224,000 students were allowed to appear for JEE-Advanced,[15] a number that had gone up from 220,000 in 2017 and 200,000 in 2016. JEE Advanced 2019 Edit JEE Advanced 2019 will be held on 19 May 2019 by IIT Roorkee and will be completely online. JEE Advanced 2018 Edit JEE Advanced 2018 was held on 20 May by IIT Kanpur and was completely online. JEE Advanced 2017 Edit JEE Advanced 2017 was conducted on 21 May 2017 by IIT Madras. JEE Advanced 2016 Edit In 2016, the JEE Advanced exam was held on May 22, 2016. The exam carried a total of 372 marks with each paper carrying 186 marks. The level of difficulty of questions was increased to a larger extent. Moreover, number of integer type questions (having no negative marking) were reduced. The paper was set up in collaboration of different IITs with the principal organiser being the IIT Guwahati. The Physics paper was set by IIT Madras, Mathematics by IIT Guwahati and the Chemistry portion was jointly set by IIT Bombay and IIT Delhi. These features made this paper the toughest ever JEE Paper until date. The paper had a huge surprise of partial marking in multiple correct choices where if a student marked some but not all correct answers without marking the wrong ones, he/she would be awarded one mark for each correct option. JEE Advanced 2015 Edit JEE Advanced 2015 was held on May 24, 2015. The two papers were of 504 marks overall, a sharp increase from the regular trend of about 360 marks. Changes in examination pattern surprised students nationwide. There were no single correct multiple choice questions at all; all of them were multi-correct. The level of negative marking was also increased. According to the statistics released by IIT Bombay, which conducted the exam, 26,456 out of the 1,17,238 candidates who appeared in the test were shortlisted for admission to IITs. 23,407 male candidates qualified, outnumbering 3,049 female candidates
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Rishu Kumar 6 years, 8 months ago

CO+H2O

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