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Naveen Sharma 8 years, 2 months ago
{tex}\sqrt {x+15}+\sqrt x = 15 {/tex}
{tex}=> \sqrt {x+15} = 15- \sqrt x {/tex}
squaring both sides, we get
{tex}=> x+15 = 225 + x + 30\sqrt x{/tex}
{tex}=> 30\sqrt x = 210{/tex}
{tex}=> \sqrt x = 7{/tex}
squaring both sides, we get
{tex}=> x = 49 {/tex}
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Bantu Mahesh 8 years, 2 months ago
not homogeneous
there is a term independent of function y
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