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Preeti Dabral 2 years, 1 month ago
Let the initial amount with them be Rs. x and Rs. y respectively.
Then according to the question:
x+100=2(y−100)
x+100=2y−200
x−2y=−300…(1)
And,
6(x−10)=(y+10)
6x−60=y+10
6x−y=70…(2)
Multiplying equation (2) by 2, we get:
12x−2y=140…(3)
Subtracting equation (1) from equation (3), we get:
11x=140+300
11x=440
x=40
Substitute the vale of x in equation (1), we get:
40−2y=−300
40+300=2y
2y=340
{tex}y=\frac{340}{2}=170{/tex}
∴ The friends had Rs. 40 and Rs. 170 with them respectively.
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Muktaram Kole 10 months, 1 week ago
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