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Preeti Dabral 6 months, 2 weeks ago

Let the initial amount with them be Rs. x and Rs. y respectively.

Then according to the question:

x+100=2(y−100)

x+100=2y−200

x−2y=−300…(1)

And,

6(x−10)=(y+10)

6x−60=y+10

6x−y=70…(2)

Multiplying equation (2) by 2, we get:

12x−2y=140…(3)

Subtracting equation (1) from equation (3), we get:

11x=140+300

11x=440

x=40

Substitute the vale of x in equation (1), we get:

40−2y=−300

40+300=2y

2y=340

{tex}y=\frac{340}{2}=170{/tex}

∴ The friends had Rs. 40 and Rs. 170 with them respectively.

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