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Vinayak Airen 1 month ago

tan45=1 tan23 = 1/tan67 = cot23 tan42= 1/tan48 = cot 48 tan45 . tan23 . tan42 . tan48 . tan67 =1

Randheer Chauhan 1 month, 3 weeks ago

please check.. you missed a term.. either tan46° or cot42°
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Vinayak Airen 1 month ago

(5x^2 - 7x + 19) quotient (-35) reminder

Sugriv Yadav 4 months, 3 weeks ago

Answer
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Vinayak Airen 1 month ago

where is the fig.

Shemah Tussopi 5 months, 3 weeks ago

Give me correct answer

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Harshita Harshita 1 week, 6 days ago

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Aryan Preet 5 months ago

1/2 X 5/3 is 5/6 and 5/6 X -6/3 is -5/3

Uttam Bhatt 8 months, 3 weeks ago

-5/3
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Shemah Tussopi 9 months, 3 weeks ago

Give me answer
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Naman Sharma 8 months ago

x²-5x-4 x²-(7-2)x-14 x²-7x+2x-14 x(x-7)+2(x-7) x-7=0,x+2=0 x=7,x=-2 I think it will help u
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Preeti Dabral 1 year ago

Let the initial amount with them be Rs. x and Rs. y respectively. 

Then according to the question:

x+100=2(y−100)

x+100=2y−200

x−2y=−300…(1)

And,

6(x−10)=(y+10)

6x−60=y+10

6x−y=70…(2)

Multiplying equation (2) by 2, we get:

12x−2y=140…(3)

Subtracting equation (1) from equation (3), we get:

11x=140+300

11x=440

x=40

Substitute the vale of x in  equation (1), we get:

40−2y=−300

40+300=2y

2y=340

{tex}y=\frac{340}{2}=170{/tex}

∴ The  friends had Rs. 40 and Rs. 170 with them respectively.

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Punam Mahato Mahto 1 year, 5 months ago

5

Jyoti Yadav 1 year, 8 months ago

20/4=5

Account Deleted 1 year, 8 months ago

5

Jatin Grewal 1 year, 8 months ago

5

Ayush Negi 1 year, 8 months ago

5

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