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Eight identical cubes are required so that the given charge q appears at the centre of the bigger cube. Thus the electric flux passing through the given cube is, ϕ=1/8(q/ε0)=q/8ε0 Hence, (b) is the correct answer

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Sign convention for two mirrors placed some distance apart

Posted by Dishu Dahiya 1 year, 8 months ago

CBSE > Class 12 > Physics

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A cell is connected to across a resistance to form an electrical circuit.on adding 5 ohm to the resistance the current is reduced to 5/6th of the original value find the original value of resistance.

Posted by Tushar Dulloo 1 year, 8 months ago

CBSE > Class 12 > Physics

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While rubbing 2 appropriate body postive charge is produced or negative

Posted by Nidhi Patel 1 year, 8 months ago

CBSE > Class 12 > Physics

3 answers

Divanshu Negi 1 year, 7 months ago

It depends on which material are you using

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Priyanshi Varshney 1 year, 8 months ago

Bcozz it happens

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Priya . 1 year, 8 months ago

The body that loses electrons gains a positive charge, while the body that gains electrons gains a negative charge.

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Difference between series combination of resistance and parallel combination of resistance

Posted by Dhruv Thakur Thakur 1 year, 8 months ago

CBSE > Class 12 > Physics

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Priya . 1 year, 8 months ago

The most important difference between resistances in series and resistances in parallel is that the series connection of resistances increases the effective resistance of whole circuit. Whereas, the parallel connection of resistances reduces the effective resistance of the circuit.

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Prepare an investigatory project provide by CBSE board ?

Posted by Farhan Haidar 1 year, 8 months ago

CBSE > Class 12 > Physics

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A straight line plot showing terminal potential difference of a cell as a function of current Using the plot determine the emf and internal resistance

Posted by Tushar Dulloo 1 year, 8 months ago

CBSE > Class 12 > Physics

1 answers

Dhruv Thakur Thakur 1 year, 8 months ago

2.8 ohms is the correct answer 👍😊

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Find the electric field intensity due to a conducting sphere and a non conducting solid sphere also plot the graph between electric field and distance of point from the centre

Posted by Ayan Ahmad 1 year, 8 months ago

CBSE > Class 12 > Physics

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Two point charges of 12ûC and 8ûC are 10cm apart. The work done in bringing them 4cm close is=?

Posted by Arun Singh 1 year, 8 months ago

CBSE > Class 12 > Physics

1 answers

Deepak Meena 1 year, 8 months ago

We can use the formula for electrostatic potential energy to calculate the work done in bringing the two point charges closer. The formula for electrostatic potential energy is: U = k*q1*q2/r where U is the electrostatic potential energy, k is Coulomb's constant (= 9 x 10^9 Nm^2/C^2), q1 and q2 are the magnitudes of the charges in Coulombs, and r is the distance between the charges in meters. Initially, the charges are 10 cm = 0.1 m apart, so the initial distance r1 is 0.1 m. The final distance r2 when the charges are 4 cm = 0.04m apart. The magnitudes of the charges are q1 = 12 uC = 12 x 10^-6 C, and q2 = 8 uC = 8 x 10^-6 C. Using the formula and plugging in the values, we get: U1 = k*q1*q2/r1 = (9 x 10^9 Nm^2/C^2)(12 x 10^-6 C)(8 x 10^-6 C)/(0.1 m) ≈ 8.64 x 10^-5 J U2 = k*q1*q2/r2 = (9 x 10^9 Nm^2/C^2)(12 x 10^-6 C)(8 x 10^-6 C)/(0.04 m) ≈ 3.456 x 10^-4 J The change in electric potential energy ΔU is U2 - U1 = 2.594 x 10^-4 J. Therefore, the work done in bringing the charges 4cm closer is 2.594 x 10^-4 Joules.

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is curent density scalar or vector

Posted by Nitesh Kumar 1 year, 8 months ago

CBSE > Class 12 > Physics

5 answers

Anshul Pratap Singh 1 year, 7 months ago

It is tensor quantity

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Amarjeet Sharma 1 year, 8 months ago

Current is scalar because it is not obey law of vector addition, it is obey KRICHOPS law.

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Sneha Mamodia 1 year, 8 months ago

Sometimes it work as scalar and sometimes as vector

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Kirpa Gupta 1 year, 8 months ago

No it's vector quantity

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Kirpa Gupta 1 year, 8 months ago

Scaler

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a free proton and a free electron are placed in a unifrom field which of the two experince greater force and greator accelartion

Posted by Bunty Chauhan 1 year, 8 months ago

CBSE > Class 12 > Physics

1 answers

Divanshu Negi 1 year, 7 months ago

The mgn of Electric force will be equal

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a dipole is formed by point charge -q and + q each of mass m ,and both the point charges are connected by a rod of length l and mass m . this dipole is placed in uniform electric field E . if the dipole is disturbed by a small angle x from stable equilibrium position, prove that it's motion will be almost SHM. Also find its time period.

Posted by Priya . 1 year, 9 months ago

CBSE > Class 12 > Physics

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Fine talk on a dipole when it place in form uniform electric field making a angle 60 degree man having dipole moment SC micro coulom electric field 10

Posted by Nadeem Qureshi 1 year, 9 months ago

CBSE > Class 12 > Physics

1 answers

..... ..... 1 year, 9 months ago

Bhaiya question sahi se bhejiye ?????

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A current of 10 A in primary coil of circuit is reduced to zero at uniform rate in 10^-³. IF coefficient of mutual inductance is 3H. What is the induces emf in secondary

Posted by Avishek Chettri 1 year, 9 months ago

CBSE > Class 12 > Physics

1 answers

Priya . 1 year, 8 months ago

If a current of 3A, flowing in the primary coil is reduced to zero in 10−3s, the induced e.m.f. in the secondary coil is 15000V

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Determine the current in each branch of the network show in figure

Posted by Soni Sharma 1 year, 9 months ago

CBSE > Class 12 > Physics

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Ncert ,lesson 1 exercise Q 1.26

Posted by Rani Bose 1 year, 9 months ago

CBSE > Class 12 > Physics

3 answers

..... ..... 1 year, 9 months ago

देखिए भैया जी इस question me ye poochh raha hai ki kaun sa curve sahi nhi hai for electric field lines ke liye --- उत्तर--- aap jante hai ki positive charge wali electric field line hamesa outward direction jati hai aur negative field lines hamesha inward aati इस question me yahi lagega toda sa sochna hai pata chal jayega kaun sa sahi hai । Esme kewal c sahi direction flow kar Raha hai aur koi nhi sahi direction me flow kar Raha hai ।bhaiya i guess aap samajh Gaye honge 😔 । Thank you ।।

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..... ..... 1 year, 9 months ago

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Ashish Kumar 1 year, 9 months ago

;;+,. Izw 9

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A positively charged particle is released from rest in a uniform electric field. The electric potential energy of the charge a) decreases because the charge moves along the electric field. b) remains constant because the electric field is uniform. c) increases because the charge moves along the electric field. d) decreases because the charge moves opposite to the electric field.

Posted by Arpit Agnihotri 1 year, 9 months ago

CBSE > Class 12 > Physics