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  • 2 answers

Utkarsha Nayak 7 years, 3 months ago

Assuming 0.1 gf to be 0.1 N answer is 0.548 * 10^(-5) C each

Utkarsha Nayak 7 years, 3 months ago

The unit of Coulombian force is wrong
  • 2 answers

Utkarsha Nayak 7 years, 3 months ago

1.72*10^14 C

Utkarsha Nayak 7 years, 3 months ago

1.72*10^14
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Suvaneel Biswas 7 years, 3 months ago

Consider an equipotential surface with electric field lines that are not perpendicular to the surface. These field lines could then be resolved into two components, one perpendicular to the surface and one along the surface. The field line along the surface means that the charges would move along the surface in the direction of the field lines. This means that there would be potential difference along the surface as the charges only move when there is a difference in potential. But that is not possible since the surface was said to be equipotential with equal potential across the surface. Thus there cannot be any field component along the surface which leaves the field lines no option other than to be perpendicular to the surface.
  • 3 answers

Manan Bedi 7 years, 3 months ago

It is applicable for only electric charges at rest.

Shubhi Jain 7 years, 3 months ago

Limitations of coloumbs law is that it is applicable only for point charges

Vishal Thakur 7 years, 3 months ago

The E.F move a +ve to -ve charge
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  • 1 answers

Chaudhary Yogesh 7 years, 3 months ago

Hii
  • 2 answers

Deepika Sharma 7 years, 3 months ago

Formula is l P l= q ^ 2l

Deepika Sharma 7 years, 3 months ago

Product of either charge and separation between two charges of dipole is called dipole moment. P= q ^ its direction is negative charge of dipole.
  • 2 answers

Deepika Sharma 7 years, 3 months ago

Where q= net charge enclosed by surface.

Deepika Sharma 7 years, 3 months ago

According to this law, total electric flux associated with closed surface is equal to 1/Eo times with net charge enclosed by surface. Mathematically, {E. Ds= q/Eo
  • 1 answers

Manan Bedi 7 years, 3 months ago

To and fro movements of a particle about a fixed point
  • 2 answers

Saloni S 7 years, 3 months ago

E=-dV/dr

Manan Bedi 7 years, 3 months ago

E=V/d
  • 3 answers

Vivek Raj Puri 7 years, 3 months ago

In inside the solid sphere the graph will be a straight line and at the surface of the sphere the value of electric field is maximum and outside the sphere the the graph of the electric field decreases .

Shubham Patel 7 years, 3 months ago

.

Shubham Patel 7 years, 3 months ago

^ | | :\ ^ | : \e directly proportional to1/r2 E | | : \ | : \ | : ╰ ------------------- |__________:________________> r=R. r->
  • 1 answers

Hariram Yadav 7 years, 3 months ago

In series resistance is directly sum up so high resistance whereas in parallel resistance is sum up in reciprocal so less resistance
  • 1 answers

Hrithik Mittal 7 years, 3 months ago

it is uncharge

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