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Ask QuestionPosted by Priyanka (Unknown) 3 years, 11 months ago
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Posted by Aseem Mahajan 3 years, 11 months ago
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Aseem Mahajan 3 years, 11 months ago
Aseem Mahajan 3 years, 11 months ago
Aseem Mahajan 3 years, 11 months ago
Posted by Sanket ... 3 years, 11 months ago
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Sia ? 3 years, 11 months ago
Sensex: It is Index of Bombay stock exchange It has total 30 shares. Its recent index above 20000 however, it keeps fluctuating day to day.
Nifty: It is Index of National stock exchange. It has total 50 shares. Present index above 5000
Posted by 🤟Royal Thakur 🤟 3 years, 11 months ago
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Aisha Nousheen 3 years, 11 months ago
</a>Posted by 🤟Royal Thakur 🤟 3 years, 11 months ago
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Aseem Mahajan 3 years, 11 months ago
Aseem Mahajan 3 years, 11 months ago
I = $$\dfrac{q}{T}=qf$$
Thus, B = $$\dfrac{\mu_0qf}{2R}$$
Posted by Sanket ... 3 years, 11 months ago
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Posted by Gembali Harsha Vardhan 3 years, 11 months ago
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Posted by Anshul Choudhary 3 years, 11 months ago
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Posted by Manish Ji 3 years, 11 months ago
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Sia ? 3 years, 11 months ago
Or, E = [M1 L1 T-2] × [I1 T1]-1 = [M1 L1 T-3 I-1]. Therefore, the Electric Field is dimensionally represented as [M1 L1 I-1 T-3].
Posted by Govind Yadav 3 years, 11 months ago
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Posted by ᵐꜞᔆᔆ᭄ Qᴜᴇᴇɴ✿࿐꧂ : ꨄ︎•, 3 years, 11 months ago
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Posted by ᵐꜞᔆᔆ᭄ Qᴜᴇᴇɴ✿࿐꧂ : ꨄ︎•, 3 years, 11 months ago
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Yash Gupta 3 years, 11 months ago
Aseem Mahajan 3 years, 11 months ago
Moreover, gravitational force also obeys inverse square law
Posted by Aryan Chandra 3 years, 11 months ago
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Posted by Priya Kumari 4 years ago
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Posted by Happy Rajput 4 years ago
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Sia ? 4 years ago
The relation between electric field, E and potential, V at a point is {tex}\mathbf{E}=-\frac{\mathbf{d} \mathbf{V}}{\mathbf{d r}}{/tex}.
Posted by Gaurav Gaurav 4 years ago
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Kajal Kumari 4 years ago
Posted by Gautam Kumar 4 years ago
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Aseem Mahajan 4 years ago
Posted by 🤟Royal Thakur 🤟 4 years ago
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Posted by Aseem Mahajan 4 years ago
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🤟Royal Thakur 🤟 4 years ago
Posted by Deltan Beshra 4 years ago
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Aseem Mahajan 4 years ago
Posted by Neeraj Rawat 4 years ago
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Aseem Mahajan 4 years ago
$$4\pi r^2$$ = 4.4/0.084
Initial charge = 0.076 × $$4 \pi r^2$$
R = 2.04 cm
Initial charge = 0.076 × 4.4/0.084 = 3.98 C
Capacitance = $$4 \pi \epsilon_0 r$$ = 2.26 × 10-14 F
Harsh Shandilya 4 years ago
Posted by Aseem Mahajan 4 years ago
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Aseem Mahajan 3 years, 10 months ago
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Sia ? 3 years, 11 months ago
The relation between electric field, E and potential, V at a point is {tex}\mathbf{E}=-\frac{\mathbf{d} \mathbf{V}}{\mathbf{d r}}{/tex}.
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