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Ask QuestionPosted by Varun Verma 6 years, 11 months ago
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Posted by Bedmin Rh 6 years, 11 months ago
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Gaurav Seth 6 years, 11 months ago
Consider a thin infinitely long straight charged wire of linear charge density λ.
Let P be the point at a distance ‘a’ from the line. To find electric field at point P, draw a cylindrical surface of radius ‘a’ and length l.
If E is the magnitude of electric field at point P, then electric flux through the Gaussian surface is given by,
<dl> <dd>|
Φ = E × Area of the curved surface of a cylinder of radius r and length l |
Because electric lines of force are parallel to end faces (circular caps) of the cylinder, there is no component of field along the normal to the end faces. |
Φ = E × 2πal … (i)
According to Gauss theorem, we have
From equations (i) and (ii), we obtain
Posted by Rahul Rahul 6 years, 11 months ago
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Posted by Yakshi Baliyan 6 years, 11 months ago
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???. Pragati 6 years, 11 months ago
Waqquar Khan 6 years, 11 months ago
Posted by Shiva Singh 6 years, 11 months ago
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Gaurav Seth 6 years, 11 months ago
Principle:
Its working is based on the fact that when a current carrying coil is placed in a magnetic field, it experiences a torque.
Working:
Suppose the coil <i>PQRS</i> is suspended freely in the magnetic field.
Let
<i>l</i> = Length <i>PQ</i> or <i>RS</i> of the coil
<i>b</i> = Breadth <i>QR</i> or <i>SP</i> of the coil
<i>n</i> = Number of turns in the coil
Area of each turn of the coil, <i>A</i> = <i>l</i> × <i>b</i>
Let <i>B</i> = Strength of the magnetic field in which coil is suspended
<i>I </i>= Current passing through the coil in the direction <i>PQRS</i>
Let, at any instant, α be the angle which the normal drawn on the plane of the coil makes with the direction of magnetic field.
The rectangular coil carrying current when placed in the magnetic field experiences a torque whose magnitude is given by,
τ = <i>nIBA</i> sin<i>α</i>
Due to deflecting torque, the coil rotates and suspension wire gets twisted. A restoring torque is set up in the suspension wire.
Let <i>θ</i>be the twist produced in the phosphor bronze strip due to rotation of the coil and <i>K</i> be the restoring torque per unit twist of the phosphor bronze strip. Then,
Total restoring torque produced =<i> k</i><i>θ</i>
In equilibrium position of the coil,
Deflecting torque = Restoring torque
∴ <i>NIBA = k</i><i>θ</i>
Or, 
Where, 
[constant for a galvanometer]
It is known as galvanometer constant.
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Current sensitivity of the galvanometer is the deflection per unit current.
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Voltage sensitivity is the deflection per unit voltage.
Posted by Sunny यदुवंशी 6 years, 11 months ago
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Posted by Sunny यदुवंशी 6 years, 11 months ago
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Posted by Sataybir Sataybir 6 years, 11 months ago
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▪▪Amrit▪▪ ❤ 6 years, 11 months ago
Posted by Om Prakash Mishra 6 years, 11 months ago
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Kanishka Sharma 6 years, 11 months ago
Posted by Harish Sirvi 6 years, 11 months ago
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Posted by Amit Pandey 6 years, 11 months ago
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Yogita Ingle 6 years, 11 months ago
Electric Flux is defined as a number of electric field lines, passing per unit area. It is another physical quantity to measure the strength of electric field and frame the basics of electrostatics. It is also defined as the product of electric field and surface area projected in a direction perpendicular to the electric field.
Posted by Gauri 123 6 years, 11 months ago
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Posted by Grashy Gupta 6 years, 11 months ago
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Posted by Priti Kimari 6 years, 11 months ago
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Arjun Saxena 6 years, 11 months ago
Posted by Čůťê Ğīřł ? ? 5 years, 10 months ago
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Čůťê Ğīřł ? ? 6 years, 11 months ago
Čůťê Ğīřł ? ? 6 years, 11 months ago
Posted by Hritik Kumar 6 years, 11 months ago
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Arjun Saxena 6 years, 11 months ago
Posted by Amit Maurya 6 years, 11 months ago
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Aman Kumar 6 years, 11 months ago
Yakshi Baliyan 6 years, 11 months ago
Posted by Hritik Kumar 6 years, 11 months ago
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Priyanshu Saini 6 years, 11 months ago
Yogita Ingle 6 years, 11 months ago
this is because there is no potential gradient along any direction parallel to the surface , and so no electric field parallel to the surface. This means that the electric lines of force are always at right angle to the equipotential surface.
Posted by Čůťê Ğīřł ? ? 6 years, 11 months ago
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Posted by Kiran Dhusiya 6 years, 11 months ago
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Posted by Aatish Kumar 6 years, 11 months ago
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Yogita Ingle 6 years, 11 months ago
Let, electron of hydrogen atom at ground state n1=1
v1=e2/n14πε0(h/2π)= e2/2ε0h
where, e = 1.6 x 10-19C, ε0= 8.85 x 10-12 /NC2/m2, h = 6.62 x 10-34 Js
then,
v1=e2/2ε0h
= (1.6 x 10-19)2/ 2x2x8.85 x 10-12 x 6.62 x 10-34
= 1.09 x 106 m/s
for n3 = 3,
then,
v1=e2/ n32ε0h
= (1.6 x 10-19)2/ 3x2x8.85 x 10-12 x 6.62 x 10-34
= 7.27 x 106 m/s
Posted by Nirbhay Singh 6 years, 11 months ago
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Posted by Jeetu Vyas 6 years, 11 months ago
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Yogita Ingle 6 years, 11 months ago
The physical quantity whose SI unit is VOLT PER METRE is "electric field" An E field of 1 V/m is represented by a potential difference of 1 Volt existing between two points that are 1 m apart. And its a vector quantity.
Posted by Arpit Shukla 6 years, 11 months ago
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Mansi Sharma 6 years, 11 months ago
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