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  • 1 answers

Somya Sharma 5 years, 8 months ago

Let y=x^1/3. For all x=27. (1) y+∆y=(x+∆x)^1/3. For all ∆x=0. (2) (2)-(1) ∆y=(x+∆x)^1/3-x^1/3 (x+∆x)^1/3=∆x × dy/dx +x^1/3 27^1/3= 0×dy/dx + 27^1/3 27^1/3=3
  • 1 answers

Avichal Yadav 5 years, 8 months ago

just use approximation bro.. and solving equations of contraints use fractional values
  • 1 answers

Shivansh Dubey 5 years, 8 months ago

Do by partial fraction
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  • 3 answers

Roshan Jha 5 years, 8 months ago

R.D Sharma. Cbse question is enough

Vemula Chowdary 5 years, 8 months ago

NCERT and oswal was more than enough for maths

Vinay Gautam 5 years, 8 months ago

Jst elements
  • 1 answers

Ritss ?? 5 years, 8 months ago

F(x)= x^2log x F'(x) = x( 1 + 2logx ) F''(x)= 3+2logx
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Ritss ?? 5 years, 8 months ago

If the point meets at x axis ; point will be (x,0) Now the putting the value of y =0 and the value of x comes to be 7 Point be (7,0) Equation of curve = y (x-1) (x-3) - x+7=0 y(x^2-4x+3)=7-x Now differentiate wrt x Dy/dx(x^2-4x+3) + y( 2x-4) = -1 Now,, dy/dx= 4y-1-2xy /x^2-4x+3 Dy/dx of pt (7,0) = the slope of tangent =-1/24 Therfore the slope of normal be 24 Now the equation of normal be (y-y')=slope (x-x') Y =24(x-7) 24x-y= 168
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Sakshi Mittal 5 years, 8 months ago

S=(111,112,113--------666)=216 E=(114,124------164,214,224------264, 314,324-----364,314,324---364,414,424-----464,514,524,564,614,624,----664)=36 F=(651,652,653,654,655,656)=6 Eintersectionf=(654)=1 Now, p(E/F)=p(EintersectionF)/p(F)------(1) and P(E)=36/216=1/6 P(F)=6/216=1/36 P(EintersectionF)=1/216 Then,(1) becomes ( 1/216)/(1/36)=1/6 which is required answer Thanks 4 watching
  • 1 answers

Agrim Kumar Dash 5 years, 8 months ago

bro focus on elementary transformation and theoretical part only bich ka zyada matter ni krta and please focus on determinants too
  • 2 answers

Jyoti Verma 5 years, 8 months ago

Zero

Dolly Sharma 5 years, 8 months ago

Product of its element
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Ritss ?? 5 years, 8 months ago

There are 4 equation total to plot -y=x-1;y=x-1 ;x=y-3; -x=y-3 Then find the closed area
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Ritss ?? 5 years, 8 months ago

Let t=1/√1-x^2 dt/dx= sin^-1(x) dt=sin^-1(x). dx Integration of t = t^2/2 Put value of t ,then = 1/2(1-x^2)
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Manish Bhandari 5 years, 8 months ago

Any link where I can find that paper...?
  • 1 answers

Subhash Jat 5 years, 8 months ago

Specify your question properly bro....
  • 2 answers

Manish Bhandari 5 years, 8 months ago

Bahut pehle se...

Sunayna Acharya 5 years, 8 months ago

In case of binomial distribution
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Ritss ?? 5 years, 8 months ago

Labour ≤30 Capital≤17 cost at Good X(a) 2 3 100 Good Y(b) 3 1 20 Let goodx be a and good y be b Therefore 2a +3b ≤30 .........eq1 3a+ b ≤17 .........eq2 Z = 100a +20b Solve eq 1 and 2 the make a graph the find the maximize pt and maximize value .............☺️☺️
  • 1 answers

Yogita Ingle 5 years, 8 months ago

Total number of elementary events =<nobr aria-hidden="true">50C5</nobr>

Given,third ticket =30

=> first and second should come from tickets numbered 1 to 29 =<nobr aria-hidden="true">29C2</nobr>

 ways and remaining two in<nobr aria-hidden="true">  20C2</nobr><nobr aria-hidden="true"></nobr>

 ways.

Therfore, favourable number of events = <nobr aria-hidden="true">29C2*20C2</nobr>

Hence,required probability = <nobr aria-hidden="true">29C2*20C2/50C5</nobr> =551 / 15134

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