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  • 1 answers

Aditya Chauhan 5 years, 8 months ago

??
  • 2 answers

Tamanna Sharma 5 years, 8 months ago

I mean you proved it

Tamanna Sharma 5 years, 8 months ago

You ,thought that we are able to prove it ,in chatbox. Chain rule apply karo y' and y" nikalo value put karo Then definitely you get the answer?
  • 2 answers

Tamanna Sharma 5 years, 8 months ago

Iog|sec x| + C ( it's basic integral for 12 class students)

Shikha Maurya 5 years, 8 months ago

Ans=-log cosx Or Ans= Log secx
  • 4 answers

Achyut Singh 5 years, 8 months ago

Abhi party band kar dunga.?

Aditya Chauhan 5 years, 8 months ago

Good yaar i am waiting for your message on whtsapp

Tamanna Sharma 5 years, 8 months ago

Abhi to party suru hoi he

Tamanna Sharma 5 years, 8 months ago

Ok
  • 1 answers

Ritika Kumar 5 years, 8 months ago

Bhai apna number dedo Mai WhatsApp par answer send kar dunga Yha par mujhe smjh nhi aa rha ki mai integration aur upper and lower limit kaise likhu
  • 4 answers

Tapan Pandey ?? 5 years, 8 months ago

Tamanna u also don't have any doubt?

Aditya Chauhan 5 years, 8 months ago

I m tension free as my 12th is next year

Aditya Chauhan 5 years, 8 months ago

My doubt is nothing because i am in class 11 and doing private so i doing class 11 and 12 both at the same time

Tamanna Sharma 5 years, 8 months ago

Dude tumhare kabhi doubts nahi hote he kya,bas sabke answer dete rhte ho, Best of luck to you also.
  • 3 answers

Sakshay Aggarwal 5 years, 8 months ago

4root2

Aditya Chauhan 5 years, 8 months ago

Sorry 4 root 2

Aditya Chauhan 5 years, 8 months ago

4
  • 2 answers

Ritika Kumar 5 years, 8 months ago

Kyoki itna bara solution likhne me bahut dikkat hoti hai

Ritika Kumar 5 years, 8 months ago

Let the radius of circle be r and length of one side of square be a. Circumference of circle =2πr Circumference of square=4a According to question, 2πr+4a=28 ...(2) 4a^2=(28-2πr)^2/4 .... (1) For minimum area, dy/dr>0 πr^2 + 4a^2=dy/dr Putting the value of equation (1) πr^2 + (28-2πr)^2/4=dy/dr 2πr - 2.(28-2πr).2π/4=dy/dr 2πr-28π+2rπ^2 =dy/dr For area dy/dr=0 r-14+πr=0 r=14/(π+1) Since dy/dr>0, so it will give minimum area Putting the value of r in equation (2) We get a=7/(π+1) Length of wire used in making circle=28π/(π+1) Length of wire used in making square=28/(π+1) I hope this will help you Agar solution me dikkat ho to whatsapp pe contact kar lena
  • 1 answers

Aditya Chauhan 5 years, 8 months ago

Install spplication 12th maths Ncert soln Because ot is too much time consuming to write these soln here by keboard....
  • 2 answers

Ritika Kumar 5 years, 8 months ago

Bhai apna whatsapp number do Mai ussi pe solution de dunga

Nishant Deshwal 5 years, 8 months ago

Sry not farmt it is fast
  • 0 answers
  • 1 answers

Tapan Pandey ?? 5 years, 8 months ago

Go through NCERT solutions
  • 0 answers
  • 1 answers

Aditya Chauhan 5 years, 8 months ago

Rolle's theorem states that if a function f is continuous on the closed interval [a, b] and differentiable on the open interval (a, b) such that f(a) = f(b), then f′(x) = 0 for some x with a ≤ x ≤ b.
  • 0 answers
  • 1 answers

Tamanna Sharma 5 years, 8 months ago

Given in examidea
  • 2 answers

Santosh Kumar 5 years, 8 months ago

Let the direction cosine of the line which make an angle à with each of the coordinates axes and direction cosines be l,m,n. l=cosà, m= cosà and n=cosà l^2+m^2+n^2=1 Cos^2à+cos^2à+cos^2à=1 3 cos^2à=1 Cos^2à=1/3 Cosà=+_1/root3

Tamanna Sharma 5 years, 8 months ago

(1/root3 ,1/root3 ,1/root3)

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