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Yogita Ingle 5 years, 6 months ago
The odd integers from 1 to 2001 are 1, 3, 5, …1999, 2001.
This sequence forms an A.P.
Here, first term, a = 1 Common difference, d = 2
Here, a+(n−1)d = 2001
=> 1+(n−1)(2) = 2001
=> 2n−2 = 2000
=> n = 1001
Sn = n/2[2a+(n−1)d]
∴ Sn = 1001/2[2×1+(1001−1)×2]
=1001/2[2+1000×2]
=1001/2×2002 =
1001×1001 =1002001
Hence, the sum of odd numbers from 1 to 2001 is 1002001.
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