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  • 1 answers

Ayush Vishwakarma?? 5 years, 5 months ago

1/y^2-cos(x+y).
  • 1 answers

Yash Srivastava 5 years, 5 months ago

RD is best
  • 0 answers
  • 1 answers

Madhu B 5 years, 5 months ago

By dividing by cosx in both num. and deno. And then by using formula of tanA-tanB you can get the answer
  • 2 answers

Tamanna Dhanda 5 years, 5 months ago

Cbse guide.com is best

Madhu B 5 years, 5 months ago

Vedantu and unacademy
  • 1 answers

Madhu B 5 years, 5 months ago

Of course khulne chahiye
  • 1 answers

Shyam Kumar 5 years, 5 months ago

Just learn the concept quickly
  • 1 answers

Madhu B 5 years, 5 months ago

You can check from cbse maths ncert solution
  • 1 answers

Tanvi Sharma 5 years, 5 months ago

Yess
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  • 1 answers

Madhu B 5 years, 6 months ago

X=1 and y=7 2x-3=-1 and 2(5)-3=y 2x=2. y=10-3 x=2. y=7
  • 1 answers

Madhu B 5 years, 6 months ago

It is equal to 1/cosecA-cotA You can prove it by taking cosecA=1/sinA and cotA=cosA/sinA
  • 1 answers

Student Of The Year 5 years, 6 months ago

Approx 1/6
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  • 0 answers
  • 1 answers

Madhu B 5 years, 6 months ago

Ab school jakr kya kroge college ki tyari kro
  • 2 answers

Sakshi Priya 5 years, 5 months ago

Thank u ?

Kumar Ankit 5 years, 6 months ago

Real valued function is the function whose values are real numbers It is a function that assigns a real number to each members of its domain
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  • 2 answers

Madhu B 5 years, 6 months ago

Cos105°=cos(45°+60°) Now, cos(a+b)=cosAcosB-sinAsinB And putting values cos45=1/√2 cos60=1/2 Sin45=1/√2. Sin60=√3/2 And we can get the ans

Ayush Vishwakarma?? 5 years, 6 months ago

Cos(60+45) and apply the formula cos(a+b) that is cosa×cosb-sina×sinb .. let a=60degree and b=45 degree an its value is 60=1/2 and 45=1/root2.
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  • 1 answers

Ayush Vishwakarma?? 5 years, 6 months ago

The value of both means fog(x) and gof(x) is same....the value is Fog(x)=5x^2-9....and gof(x) is 5x^2-9.
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  • 4 answers

Nishihoney Lodha 5 years, 6 months ago

Ques. Sin(2sin^-1[3/5]) --sol. Let sin^-1[3/5]=A.... Sin2A=2sinAcosA.... As sin^-1[3/5]=A.... SinA=3/5 CosA=4/5 Cos^-1[4/5]=A Putting the values : 2sin[sin^-1(3/5)]cos[cos^-1(4/5)].... 2.(3/5).(4/5)=24/25

Ayush Vishwakarma?? 5 years, 6 months ago

Not 5he it is the

Ayush Vishwakarma?? 5 years, 6 months ago

The answer is 24/25. Firstly you have to solve 2sin^-1 3/5 in tan^-1 and apply 5he formula 2tan^-1.

Apratim Sarkar 5 years, 6 months ago

I think 6/5
  • 2 answers

Apratim Sarkar 5 years, 6 months ago

1.4949(approximately)

Manan Gupta 5 years, 6 months ago

log5^3 - log2^2 3log5-2log2 Or log125/4 log31.25

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