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Naveen Sharma 8 years, 2 months ago
Let Number of orange originally = x
% of orange sells = 40 %
% of orange remainging = 60 %
Number of orange remaining = {tex} {x\times 60\over 100 }= {3x\over 5}{/tex}
According to question,
{tex}{3x\over 5} = 420 \\ => x = {420\times 5\over 3} \\ => x= 140\times 5 = 700{/tex}
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Naveen Sharma 8 years, 2 months ago
{tex}\int {x^3\over x-1} dx \\{/tex}
{tex}= \int (x^2+x+1)dx + {1\over x- 1}dx{/tex}
{tex}= {x^3\over 3}+{x^2\over 2} + x + log (x-1) + C{/tex}
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