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  • 1 answers

Mohit Ojha 8 years, 1 month ago

x+y=t Differentiating wrt x 1+dy/dx=dt/dx dy/dx=dt/dx-1 dt/dx-1=sint dt/dx=1+sint dx=dt/(1+sint) Integrate and substitute value of t
  • 1 answers

Mohd Adnan 8 years, 1 month ago

Ab
  • 2 answers

Vinay Kumar 8 years, 1 month ago

Job settlement

Mohd Adnan 8 years, 1 month ago

What do you want ?
  • 0 answers
S
  • 0 answers
  • 1 answers

Venky Venkatesh 8 years, 1 month ago

Wrong question
  • 1 answers

Mohit Ojha 8 years, 1 month ago

(xcosxe^x+xsinxe^x-e^xcosx)/2 Use byparts
  • 1 answers

Sarthak Shinde 4 years, 6 months ago

Study hard and practice questions related to that topic
  • 2 answers

Aman Mishra 8 years, 1 month ago

Find f'(c) where c is a constant

Aman Mishra 8 years, 1 month ago

h'(x) is constant
  • 1 answers

Vinay Kumar 8 years, 1 month ago

Work as, sin(a+b)+ sin(a-b)=2sina.cosb
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  • 1 answers

Neelaksi Saini 8 years, 1 month ago

1.414
  • 0 answers
  • 1 answers

Neelaksi Saini 8 years, 1 month ago

x^2 + y^2=r^2 => 2x+2ydy/dx =O =>x+ydy/dx = 0
  • 1 answers

Aryan Singh 8 years, 1 month ago

-78cosx
  • 2 answers

Nishant Singh 8 years, 1 month ago

Hi Manav the concept of mathematical symbols came long before the charges get discovered. So your answer is not a proper explanation of my question.

Manav Trikha 8 years, 1 month ago

Because two same end like ++ or-- never attracts hence gives positive valie
  • 1 answers

Faizan Raza 8 years, 1 month ago

If u can not do 0÷0 then how can u do sin0÷sin0 Is it not undefined?
  • 4 answers

Faizan Raza 8 years, 1 month ago

Sorry P is on X axes and Q is on Y axes

Faizan Raza 8 years, 1 month ago

Log 0= not defined As If Log p=q then it implies that p=e to the power q And, e must be greater than 1 (i.e., e>1) And if e>1 then how p can be zero? Also the graph drawn between the value of p(Y axes) and q(X axes) for logarithmic function the curve obtained can't touch the Y axes then how it can be 0?

Neha Kumari 8 years, 1 month ago

Log 0=0

Monika Banerjee 8 years, 1 month ago

It may be 1
  • 0 answers

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