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  • 1 answers

Satwik Dash 8 years ago

Complete NCERT and revise it another time its enough for even jee mains.
  • 1 answers

Satwik Dash 8 years ago

-2 cos (x)
  • 1 answers

Satwik Dash 8 years ago

x (log x)^2 - 3x log x +3x
  • 1 answers

Ujjwal Kumar 8 years ago

536372625728873292839293839264282267328727272737374747227
  • 2 answers

Satwik Dash 8 years ago

2222

Narendra Kumar 8 years ago

Gadha 44
  • 1 answers

Satwik Dash 8 years ago

(x-y)/[x (1+log x)]
  • 1 answers

You . 8 years ago

If two lines are perpendicular then product of their slope is -1.....if lines are parallel then their slopes are equal.....
  • 3 answers

You . 8 years ago

If we let x be atan^2α... Then a is common and cancel out.... Tan is out from root.... And 1-tan^2α=sec^2α...change dx to dα

Ashish Verma 8 years ago

I think doesn't

You . 8 years ago

Let your x be atan^2x
  • 1 answers

You . 8 years ago

When you intergrate this qsn.... Ur answr is 2√x+1 because integration of 1/√x = 2√x.... And ur denominator is linear so ur answer is 2√x+1
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  • 1 answers

Satwik Dash 8 years ago

Not possible.
  • 2 answers

Satwik Dash 8 years ago

cosec x - cot x

Anchal Sharma 8 years ago

Put 1+cosx=t
  • 1 answers

Vaibhav Mathur 8 years ago

X -tan invers x
  • 1 answers

Vaibhav Mathur 8 years ago

See. As it is given that f(x)= x square so F(2)=4 and F(-2) is also equal to 4 .so 2 belongs to codomain of but -2 doesn't belongs to codomain of F hence the function is not on to function
  • 0 answers
  • 1 answers

Vaibhav Mathur 8 years ago

convert to cos and sin u will get sinx/cosx(1+sinx) then rationalize with 1-sinx u will get sinx-sin2x/cos3x then separate 1.sec2xtanx will be easy 2.sin2x/cos3x will be solved sin to cos then separate ull getsec3x which can be solved by parts. good q.

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