No products in the cart.

Ask questions which are clear, concise and easy to understand.

Ask Question
  • 0 answers
  • 1 answers

Siddharth Basu 7 years, 10 months ago

Apply binomial combination for probability distribution of x=01234...without taking Bernoulli's trials(as BT is only for with replacement)
  • 6 answers

Mimansha Rawat 7 years, 10 months ago

Doing RD sharma would bring best results then only relying on NCERT

Ayush Gupta 7 years, 10 months ago

50 no pkka aa jayenge aage koi guarantee N h

Aditya Raj 7 years, 10 months ago

Why not??? Swati singh

Singh Singh 7 years, 10 months ago

Yes….....

Anjali Tamboli 7 years, 10 months ago

yes

Lekha Raj 7 years, 10 months ago

Nooo
  • 1 answers

Lekha Raj 7 years, 10 months ago

Let sin2x = t..................2cos2x dx=dt.................then partial fraction slve it
  • 0 answers
  • 1 answers

Lekha Raj 7 years, 10 months ago

Convert it into sinx and cosx form and apply partial fraction after multiplying and dividing it with cosx.
  • 0 answers
  • 0 answers
  • 1 answers

Vish Al 7 years, 10 months ago

Acche se toh likh
  • 0 answers
  • 0 answers
  • 1 answers

Yogesh Kumar 7 years, 10 months ago

Taking common √tanx It become √tanx (1+1/tan^2) And then put tanx = t or t^2 And then, evaluate.
  • 3 answers

Gaurab Kumar 7 years, 10 months ago

Ayush Gupta Tu apna no. De to jara

Ayush Gupta 7 years, 10 months ago

Bc padte padte teko 15 saal se jada ho gye aur ab tak y na pta chala ki padna kase h??

Lekha Raj 7 years, 10 months ago

Jst to wrk hrd
  • 0 answers
  • 2 answers

Abcd Abcd 7 years, 10 months ago

No ....I think not above 50 marks

Singh Singh 7 years, 10 months ago

Approximately hoti 80 marks as Told by seniors.
  • 0 answers
  • 4 answers

Ayush Gupta 7 years, 10 months ago

Koi ans to bta na rha sab bakchodi mar rhe h... .

Esha Modi 7 years, 10 months ago

Because I didn't have an other option at that point of time .....

Lekha Raj 7 years, 10 months ago

If u r weak in maths......then why had u opted it?

Prateek Tongar 7 years, 10 months ago

Same problem
  • 2 answers

Harish Harish 7 years, 10 months ago

1.take a,b,c common from C1,C2,C3 respectively. 2.R1-> R1-R2-R3 3.take (-2b) common from R1 4.C1-> C1-C2 5.expanding along R1

Lekha Raj 7 years, 10 months ago

It's veryyyyyy lengthy.
  • 0 answers
  • 1 answers

Anvita Chotani 7 years, 10 months ago

Take log both sides
  • 0 answers
  • 1 answers

Arka Ghosal 7 years, 10 months ago

Y=x^x Taking log on both sides log y=log x^x log y=x logx (1/y)(dy/dx)=(x*1/x)+logx (dy/dx)=y(1+log x) d/dx(dy/dx)=d/dx(y(1+logx)) d^2y/dx^2=(1+log x)(dy/dx)+y/x Now, 1/y(dy/dx)^2=(1/y)*y^2(1+logx)^2 Therefore d^2y/dx^2-1/y(dy/dx)^2-y/x=(1+log x)dy/dx - y(1+log x)^2 +y/x - y/x = (1+log x)(1+log x) * y - y(1+log x)^2 =y(1+log x)^2 - y(1+log x)^2 =0=RHS[PROVED]

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App