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  • 2 answers

Vivek Singh 7 years, 8 months ago

Ask the teacher of shortcut method

Vivek Singh 7 years, 8 months ago

It's not so hard bro
  • 2 answers

Uday Pratap 7 years, 8 months ago

Right or wrong

Uday Pratap 7 years, 8 months ago

Answer is -pi/10
  • 2 answers

Harshit Jaiswal 7 years, 8 months ago

No given function is not transitive because (1,2) €R and (7,1) €R but (2,7)not €R . So, given is not transitive

Rishika Kumari 7 years, 8 months ago

No
  • 2 answers

Rahul Chauhan 7 years, 8 months ago

Yeah bro

Ashutosh Kumar 7 years, 8 months ago

You wanna do it ?????
  • 3 answers

Lakshya Jain 7 years, 8 months ago

Thank you

Nitin Vats 7 years, 8 months ago

F(a a) T1 is congruent to T1 because every triangle is congruent to itself hence it is reflexive F(a,b) T1 is congruent to T2 it means F(a,b) T2 is congruent to T1 hence it is symmetric F(a,b) T1 is congruent to T2 F(b,c)T2 is congruent to T3 F(a,c) T1 is also congruent to T3 hence it is reflexive Therefore R is an equivalence relation

Nitin Vats 7 years, 8 months ago

F(a,a) T1 is congruent to T1 because every triangle is congruent to itself
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Vinayak Vairat 7 years, 8 months ago

If (a,b) & (b,c) are in relation R then (a,c) must be there in relation R.
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Omkar Singh 7 years, 8 months ago

If you want to find out inverse of any matrix Then there was two type 1- by operation of matrics, it mean like AA'=indentity matrix where A' is inverse matrics 2- find out adj of A and diveded it by determinant of A then we find out A'( A inverse)
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Gagan Gupta 7 years, 8 months ago

A well defined collection of things is called set
  • 1 answers

Rishabh Sahu 7 years, 8 months ago

Please explain your question in detail. If you just want a good integration question for practice then seriously go to IIT JEE archive or best book for calculus which is most recommended is Sameer Bansal calculus by Ben publishers . And search there for one. Because other books have too many questions but selecting a good one in them is tougher.
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Pradum Yadav 7 years, 8 months ago

I think, that point where constituents particle are present.
  • 1 answers

Rishabh Sahu 7 years, 8 months ago

Every school has different syllabi for their periodic or unit tests.
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Sumit Tiwari 7 years, 8 months ago

0
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Harshita Harshita 7 years, 8 months ago

2sin(a+b)/2×cos(a-b)/2
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Anurag Kumar 7 years, 8 months ago

Cosec y=cosec (pie/6) Let cosec inverse (2)=y Cosec inverse (2)is pie/6

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