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  • 4 answers

Prakhar Gupta 3 years, 7 months ago

Oswal ke sample papers meh bhi nhi dikhaye gye.

Prakhar Gupta 3 years, 7 months ago

Yaar lakin koi bol rha h delete h or koi nhi h delete.

Rishab Jain 3 years, 7 months ago

Vaise to delete ho gye lekin krle bhai kya pta aa jaye kyuki hmare pre board me aaye the

Kapil Adhikari 3 years, 7 months ago

Yes, Word problem questions are deleted for session 2020-21

  • 2 answers

Aditya Chandel 3 years, 7 months ago

Let X=AB-BA Given A'=A and B'=B(as A and B are symmetric matrices) X'=(AB-BA)'=(AB)'-(BA)'=B'A'-A'B'=BA-AB=-(AB-BA)=-X Since X'=-X Therefore,X=AB-BA is a skew symmetric matrix if A and B are symmetric matrices

Educationjone Rk Yadav 3 years, 7 months ago

No
  • 3 answers

Ashutosh Tripathy 3 years, 7 months ago

Iintegrare dx/x^2 - 2x +1 =integration dx/(x-1)^2 =integration dt/t^2 =-1/t+c =-1/x-1+c

Vivek Chaurasia 3 years, 7 months ago

Agr glat hua ho tho sryy but asa hii solve hoga.. ????

Vivek Chaurasia 3 years, 7 months ago

Aree yrr..?‍♂️?‍♂️ Integrate 1/x^2-2x+1 = x^2 - 2x +1^ - 1^+2 =(x-1)^2 + root 5 pa whole square .. Abb yrr eska aaga solve kar loo espa humsa na ho paayega type karka???
  • 2 answers

Satyam Suman 3 years, 7 months ago

Matrix and determinant

Vivek Chaurasia 3 years, 7 months ago

Calculus ??
  • 1 answers

Kapil Adhikari 3 years, 7 months ago

Y=sin(logx)

dy/dx=cos(logx) .1/x)

Now,by quotient rule

d²y/dx²=[x(-sin(logx).1/x)- cos(logx).1]/x²

d²y/dx²=[-sin(logx)-cos(logx)] /x²

  • 1 answers

Diti Urvija 3 years, 7 months ago

(x-y)(x+y)
  • 3 answers

Vivek Chaurasia 3 years, 7 months ago

One shot dekh le bhai... ??

Queen Manisha 3 years, 7 months ago

Shashank vohara sir ne ye chapter bohot ache se kraya hain hain @ON YOU TUBE

Queen Manisha 3 years, 7 months ago

https://youtube.com/playlist?list=PLOB4Q52rs1U7rM52Ih7plGyi_RseuRCjz
  • 1 answers

Sia ? 3 years, 7 months ago

Let there be a natural number n,
We know that n divides n, which implies nRn.
So, Every natural number is related to itself in relation R.
Thus relation R is reflexive .
Let there be three natural numbers a,b,c and let aRb,bRc
aRb implies a divides b and bRc implies b divides c, which combinedly implies that a divides c i.e. aRc.
So, Relation R is also transitive .
Let there be two natural numbers a,b and let aRb,
aRb implies a divides b but it can't be assured that b necessarily divides a.
For ex, 2R4 as 2 divides 4 but 4 does not divide 2 .
Thus Relation R is not symmetric .

  • 2 answers

Nikhil Kumar 3 years, 7 months ago

40

Kush Nema 3 years, 7 months ago

4
  • 0 answers
  • 1 answers

Rajnish Yadav 3 years, 7 months ago

dy/dx=ycotx (separate variable both side) dy/y=cotx dx (Integration both side) logy=log(sinx)+c logy-log(sinx)=logc (loga-logb=loga/b) logy/sinx=logc y/sinx=c y=sinx(c)
  • 3 answers

Juber Khan 3 years, 7 months ago

Aap muja Instagram pa msg kar do ma vha bta dunga

Preeti Yadav 3 years, 7 months ago

Yhi*

Preeti Yadav 3 years, 7 months ago

Thi btao do
  • 2 answers

Satyam Suman 3 years, 7 months ago

y = -cosx + c

Juber Khan 3 years, 7 months ago

Cosx
  • 2 answers

Juber Khan 3 years, 7 months ago

Bhai cofactor square matrix ka hi nikalta h

Ajay Gupta 3 years, 7 months ago

.l.
  • 3 answers

Satyam Suman 3 years, 7 months ago

Lene ki zarurt nhi h but kuch chapters and kuch topics jo delete hue h unhe mark kr lena aur mat krna

Aarohi Singh 3 years, 7 months ago

No don't

Abhijeet Singh 3 years, 7 months ago

Na mat lo
  • 3 answers

Satyam Suman 3 years, 7 months ago

You will pass definitely but i don't think you will score more than 58-60 in board exams

Vivek Chaurasia 3 years, 7 months ago

DE, Vector, 3d,lp, probability are also important chapters. So i think it is not enough for u.. ?

Arpit Singh 3 years, 7 months ago

Not at all
  • 4 answers

Abhishek Soni 3 years, 5 months ago

Given a+b+c=0 Take dot product of this with itself (a+b+c).(a+b+c)=0 a.a+a.b+a.c+b.a+b.b+b.c+c.a+c.b+c.c=0 On solving this, we get 3 + 2(a.b+a.c+b.c)=0 Hence (a.b+b.c+c.a)=-3/2

Satyam Suman 3 years, 7 months ago

-3/2

Divyaman Pal 3 years, 7 months ago

0

Amit Yadav 3 years, 7 months ago

-3/2
  • 2 answers

Harsh Kankarwal 3 years, 7 months ago

Right mahima

Mahima Pattanayak 3 years, 8 months ago

Solve all your ncert book and ncert exampler questions and if time permits solve last year sample papers too. It will help you in board examination
  • 1 answers

Mahima Pattanayak 3 years, 8 months ago

Hope it helps. The base b raised to the power of n/m is equal to: bn/m = (m√b)n = m√(bn) Example: The base 2 raised to the power of 3/2 is equal to 1 divided by the base 2 raised to the power of 3: 23/2 = 2√(23) = 2.828
  • 1 answers

Ashish Sharma 3 years, 8 months ago

Let x=t Then , 2xdx=tt xdx=tt/2 - Eqn[i] =3/2{tt/1+2t2 = 3/2{1/2(tt/t2+1/2) =3/4{tt/t2+1/underoot2) =3/4[1/(underoot2)(tan-[t/underoot2]) =3/4 (underoot2) [tan-(underoot2 t)] =3/4 x 2/(underoot2) [tan-(underoot2x2)] =3/(2underoot2) [tan- (underoot2x2)+C.
  • 1 answers

Sia ? 3 years, 7 months ago

{tex}\text{Let 2 white ball be denoted by}~ w_1, w_{2}~ \& ~red~ ball~ by~ \mathrm{r}{/tex}
Then the sample space is
{tex}\mathrm{S}=\left\{\left(\mathrm{w}_{1}, \mathrm{w}_{1}\right),\left(\mathrm{w}_{2}, \mathrm{w}_{2}\right),\left(\mathrm{w}_{1}, \mathrm{w}_{2}\right)\right. \left(w_{2}, w_{1}\right),\left(r, w_{1}\right),\left(w_{1}, r\right) \left(r, w_{2}\right),\left(w_{2}, r\right) (r, r)\}{/tex}
Let X: Number of red balls in two draws
We can see there are 0 red, 1 red, and 2 red balls
{tex}So, X=0~ or ~X=1 ~or~ X=2{/tex}

  • 3 answers

Satyam Suman 3 years, 7 months ago

By the way this question is not in syllabus now

Shubham Mishra 3 years, 8 months ago

K

Shubham Mishra 3 years, 8 months ago

Let x=sin thita.............................(1) Sin inverse x=thita.....................(2) RHS- sin inverse (3x-4x^3), .................( Use 1) =Sin inverse (3sin thita-4sin^3thita), =Sin inverse (sin3 thita), =3 thita ..................... (Use 2) =3sin inverse x... L.H.S
  • 2 answers

Divanshu Rawat 3 years, 8 months ago

Kuchh to simple methods se ho jaate hai but kuchh me p and c use hi karna hota hai

Vivek Chaurasia 3 years, 8 months ago

Hnn kuch question ma ha use ha means thoda bhut idea la loo permutation and combination sa kaasa solve krnga aaga.. ??
  • 2 answers

Piyush Kumar 3 years, 8 months ago

LXXXVI

Mahima Pattanayak 3 years, 8 months ago

LXXXVI
  • 1 answers

Kajal Gupta 3 years, 8 months ago

Break 5x in 3x & 2x and then use tan inverse a + tan in. b formula.

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