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Given a+b+c=0 Take dot product of this with itself (a+b+c).(a+b+c)=0 a.a+a.b+a.c+b.a+b.b+b.c+c.a+c.b+c.c=0 On solving this, we get 3 + 2(a.b+a.c+b.c)=0 Hence (a.b+b.c+c.a)=-3/2

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Satyam Suman 4 years, 6 months ago

-3/2

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Divyaman Pal 4 years, 6 months ago

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Amit Yadav 4 years, 6 months ago

-3/2

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How to gain 90%in broad examination??

Posted by Anchal Sharma 4 years, 6 months ago

CBSE > Class 12 > Mathematics

2 answers

Harsh Kankarwal 4 years, 6 months ago

Right mahima

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Mahima Pattanayak 4 years, 6 months ago

Solve all your ncert book and ncert exampler questions and if time permits solve last year sample papers too. It will help you in board examination

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How to solve fraction in power

Posted by Vibhuti Kumar 4 years, 6 months ago

CBSE > Class 12 > Mathematics

1 answers

Mahima Pattanayak 4 years, 6 months ago

Hope it helps. The base b raised to the power of n/m is equal to: bn/m = (m√b)n = m√(bn) Example: The base 2 raised to the power of 3/2 is equal to 1 divided by the base 2 raised to the power of 3: 23/2 = 2√(23) = 2.828

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3x/1+2x⁴ solve it exercise 7.4

Posted by Anchal Sharma 4 years, 6 months ago

CBSE > Class 12 > Mathematics

1 answers

Ashish Sharma 4 years, 6 months ago

Let x=t Then , 2xdx=tt xdx=tt/2 - Eqn[i] =3/2{tt/1+2t2 = 3/2{1/2(tt/t2+1/2) =3/4{tt/t2+1/underoot2) =3/4[1/(underoot2)(tan-[t/underoot2]) =3/4 (underoot2) [tan-(underoot2 t)] =3/4 x 2/(underoot2) [tan-(underoot2x2)] =3/(2underoot2) [tan- (underoot2x2)+C.

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What is the value of sin(11 1/4)° cos(11 1/4)°

Posted by Priyanshu Kaushik 4 years, 6 months ago

CBSE > Class 12 > Mathematics

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A bag contains 2 white and 1red ball. One ball is drawn at random and then put bach in the box after noting the colour of ball. The process is repeated again . If X denotes the number of red ball recorded in the two draws describe. I have of solution of this question but I don't know why here take white ball as W1 and W2

Posted by Domesh Soni 4 years, 6 months ago

CBSE > Class 12 > Mathematics

1 answers

Sia ? 4 years, 5 months ago

{tex}\text{Let 2 white ball be denoted by}~ w_1, w_{2}~ \& ~red~ ball~ by~ \mathrm{r}{/tex}
Then the sample space is
{tex}\mathrm{S}=\left\{\left(\mathrm{w}_{1}, \mathrm{w}_{1}\right),\left(\mathrm{w}_{2}, \mathrm{w}_{2}\right),\left(\mathrm{w}_{1}, \mathrm{w}_{2}\right)\right. \left(w_{2}, w_{1}\right),\left(r, w_{1}\right),\left(w_{1}, r\right) \left(r, w_{2}\right),\left(w_{2}, r\right) (r, r)\}{/tex}
Let X: Number of red balls in two draws
We can see there are 0 red, 1 red, and 2 red balls
{tex}So, X=0~ or ~X=1 ~or~ X=2{/tex}

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There are 3 categories of students in a class of 60 students A.very hard working B.regular but not so hardworking C.careless and irregular It's known that 10 students are in categoroy A 30 in categoroy B and rest in categoroy C.It is also found that probability of students of categories A unable to get good mark in final exam is 0.002 of categories B is 0.02 and of categories C is 0.20 Assume that a student selected at random was found to be the one who could not get good marks in the exam then the probability that this student is either of categories A or of categories B

Posted by Rosemary Thomas 4 years, 6 months ago

CBSE > Class 12 > Mathematics

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3sininverse x =sin inverse(3x-4x^3

Posted by ਸਹਿਜ ਸਿੰਘ 4 years, 6 months ago

CBSE > Class 12 > Mathematics

3 answers

Satyam Suman 4 years, 5 months ago

By the way this question is not in syllabus now

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Shubham Mishra 4 years, 6 months ago

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Shubham Mishra 4 years, 6 months ago

Let x=sin thita.............................(1) Sin inverse x=thita.....................(2) RHS- sin inverse (3x-4x^3), .................( Use 1) =Sin inverse (3sin thita-4sin^3thita), =Sin inverse (sin3 thita), =3 thita ..................... (Use 2) =3sin inverse x... L.H.S

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Is it necessary to use permutations and combinations formula in probability? Or can we use simple multiplication if we can?

Posted by Kajal Gupta 4 years, 6 months ago

CBSE > Class 12 > Mathematics