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  • 3 answers

Abhinav Sharma 7 years, 6 months ago

Since i=√-1 Multiply both sides by root √i=√√-1 √i=-1

Pooja Sharma 7 years, 6 months ago

√-1

Riya Chaurasiya 7 years, 6 months ago

I think -1 may be not confirm
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  • 3 answers

Amit Kumar 7 years, 6 months ago

0

H!Mαη$Hμ Ұαδαυ ✔️ 7 years, 6 months ago

Zero

Satendra Singh 7 years, 6 months ago

If we differentiate w r t x then answer is 0 coz it is constant
  • 2 answers

Abhinav Sharma 7 years, 6 months ago

Any 1 method works here and preferably the row transformations to get the inverse of a given matrix Although column transformations are equally appreciated

Amit Kumar 7 years, 6 months ago

Row or column
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  • 1 answers

Shreeparna Talukdar 7 years, 6 months ago

[-1,1]
  • 1 answers

Science Student 7 years, 6 months ago

First of all first differentiation is the slope of tangent. Second differentiation is the rate of change of the slope of tangent w.r.t x.
  • 1 answers

Rishabh Sahu 7 years, 6 months ago

Ncert.
  • 1 answers

Aisha Gupta 7 years, 6 months ago

Let x-3= t. => x=t+3 d(x-3)/dx=dt/dx =>1=dt/dx =>dt=dx. now Int (t+3)dt/t =int(1+3/t) dt = t+3logt =(x-3)+3log(x-3)
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  • 1 answers

Abhinav Sharma 7 years, 6 months ago

First Find A^2 , then find A^3 and if required find A^4 then by seeing the result generalize the result for A^100 That's it.
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Vivek Mandal 7 years, 6 months ago

Didnt get it

Rahul Ajmera 7 years, 6 months ago

(1-x/1+x)×(1-x)(1)-(1+x)(-1)/(1-x^2) =(1-x)/(1+x)×(-2x) /(1^2-x^2) =(1-x)/(1+x)×(2x)/(1-x)(1+x) =(2x/1+x^2). (Hence Prove)
  • 1 answers

Aisha Gupta 7 years, 6 months ago

=int(2sec²x-3tanx.secx)dx = 2int sec²xdx-3int tanx.secxdx =2tanx-3secx+c
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Science Student 7 years, 6 months ago

Numbers which can be represented on a number line are real like √2, 5.6666.... etc. And those cannot are imaginary like negative roots.

Jeetu Sharma 7 years, 6 months ago

Thats not a fair answer for this

Adil Faiz 7 years, 6 months ago

All negative root no. are called complex no. And all other are called real no.
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  • 1 answers

Anupam Shekhar 7 years, 6 months ago

(1+log(logx)) (1+logx)
  • 1 answers

Achal Bajpai 7 years, 6 months ago

Cos(a)cos(b)+sin(a)sin(b)
  • 3 answers

Chirag P 7 years, 6 months ago

It will be conducted in the last week of feb most probably

Chirag P 7 years, 6 months ago

Yes it is true

Gud Luck ? 7 years, 6 months ago

No.. How can it be?

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