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  • 1 answers

Jagpreet Singh Bhatia 7 years, 5 months ago

X square-5x+8=2x-5 X cube +7x+9=3x square +7
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  • 1 answers

Rishabh Sahu 7 years, 5 months ago

Parametric differentiation dz/dm = (dz/dt)/(dm/dt) take z as sinx ,m as cosx and t as x . So x is tne parameter. So you get dz/dm as (cosx)/(-sinx) (ie after differentiating numerator z and denominator as m with respect to x separately then carry out division. You get - cotx as the answer.
  • 1 answers

Kusum Rani 7 years, 5 months ago

See ncert exampler
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  • 3 answers

Pragya Singh 7 years, 5 months ago

-1/x^2 it is the correct one.

Prabjeet Singh 7 years, 5 months ago

{tex}y=\cfrac {1}{x}{/tex}

{tex}\cfrac {d}{dx} (y)=\cfrac {d}{dx} \bigg( \cfrac{1}{x} \bigg){/tex}

{tex}\cfrac {d}{dx} (y)=\cfrac {d}{dx} (x^{-1}){/tex}

{tex}\cfrac {dy}{dx} = -1(x)^{-1-1}{/tex}

{tex}\cfrac {dy}{dx} = -x^{-2}{/tex}

{tex}\cfrac {dy}{dx} = - \cfrac {1}{x^2}{/tex}

Siddharth Prajapati 7 years, 5 months ago

-1/x
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Hina Sagar 7 years, 5 months ago

Toh
  • 1 answers

Siddharth Prajapati 7 years, 5 months ago

Arrangement of elements in a row and column
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Jagpreet Singh Bhatia 7 years, 5 months ago

First convert it into tan inverse term than put formula Tan inverse x + Tan inverse y and hence solved
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Aisha Gupta 7 years, 5 months ago

It is an higher art of QNSSC were Q stanfs for quantity N for no S stand for set further S stand for space & finally C stands for complexity
  • 1 answers

Kriti Chhetri 7 years, 5 months ago

Use chain rule to differentiate 7sin^6 xcosxcos(sin^7x) i hope this is the answer. Still you cam check it wether its correct or not.
  • 1 answers

Kriti Chhetri 7 years, 5 months ago

A inverse = - 9 12 - 5 secnd row - 2 3 - 2 third row - 4 4 1. [R1->R1-R2] then [R2->R2-2R1] then [R2-2R3] then R1->R1+3R2&R3->R3-4R2 then R1->R1+R3...... And you will get the answer as i mentioned above.
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Rishabh Sahu 7 years, 5 months ago

Prabjeet can you please describe how to type maths in this way without using coding? I will be very grateful.

Prabjeet Singh 7 years, 5 months ago

{tex}{\int \cfrac{(x^2-1)}{(x^2+4)} dx}={\int \cfrac{(x^2+4)-5}{(x^2+4)}dx }{/tex}

{tex}={\int \cfrac{x^2+4}{x^2+4}dx} -5{\int \cfrac {1}{x^2+4}dx}{/tex}

{tex}={\int dx} -5{\int \cfrac {1}{x^2+2^2} dx}{/tex}

{tex}={x-5 \times \cfrac {1}{2}tan^{-1}\cfrac{x}{2}}+c{/tex}

{tex}={x-\cfrac {5}{2} tan^{-1} \cfrac {x}{2} +c}{/tex}

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Vishwajeet Raj 7 years, 5 months ago

D

Vishwajeet Raj 7 years, 5 months ago

Gfd
  • 2 answers

Subhash Bazzad 7 years, 5 months ago

Now cp>sp then how there is profit?

Aarav Raj 7 years, 5 months ago

Profit ????

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