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  • 1 answers

Suraj Choudhury 7 years, 3 months ago

Very easy
  • 1 answers

Isha Deo 7 years, 3 months ago

15x-4x²+c
  • 0 answers
  • 0 answers
  • 1 answers

Arpajit Adhikary 7 years, 3 months ago

dx/dt= [(3sin^2(t)cos(t)(√cos(2t))) + {(sin^3(t)(sin(2t)))/(√cos(2t))}]/cos(2t) dy/dt= [(-3cos^2(t)sin(t)(√cos(2t))) + {(cos^3(t)(sin(2t)))/(√cos(2t))}]/cos(2t) dy/dx= [{-3cos^2(t)cos(2t) + sin^2(t)sin(2t)}/{3sin(t)cos(t)cos(2t) + sin(2t)sin^2(t)}]
  • 1 answers

Vishal Mehta 7 years, 3 months ago

plz ans
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  • 3 answers

Manish Sharma 7 years, 3 months ago

Miscellaneous question no. 28

Aarushi Dhiman 7 years, 3 months ago

It is trick to get (cosx+sinx)dx

Ankit Kumar 7 years, 3 months ago

Which excercise??
  • 1 answers

Naveen Takshak 7 years, 3 months ago

(Sin^4x+cos^4x+2sin^2xcos^2x-sin^2xcos^2x)/sin^4xcos^4x =1/sin^4xcos^4x -1/sinx cos2x =-2cot2x-log|cosec2x-cot2x|
  • 1 answers

Aftab Khan 7 years, 3 months ago

Approx 0.3
  • 1 answers

Sia ? 4 years, 7 months ago

  • 1 answers

Akash Rounit 7 years, 3 months ago

One upon cos square X upon one upon sin square x is equal to sin square X upon cos square x is equals to tan Square x then formula of tanx==sec square x -1,then integrate u get tanx - x +c
  • 1 answers

Ritik Yadav 7 years, 3 months ago

dy/dx= (x+2y)/(x-y) Since the degree of numerator and denominator is same,i.e. 1, then Let y=vx So dy/dx= v + x dy/dx (x+2vx)/(x-vx) = v+x dv/dx (1+2v)/(1-v) = v + x dv/dx (1+2v)/(1-v) - v = x dv/dx (1+2v-v+v^2 ) /(1-v) = x dv/dx (v^2 + v +1)/(1-v) =x dv/dx (1-v) dv/( v^2 +v+1) = dx/x So. Now you can integrate both sides and find the result...
  • 2 answers

Kanika Sharma 7 years, 3 months ago

To calculate the area of irregular figures example mountain

Goswami Ji 7 years, 3 months ago

No one practice use but used to derive formulaes
  • 2 answers

Soni Kumari 7 years, 3 months ago

Dear it's 1

Tanu Chaudhary 7 years, 3 months ago

1
  • 2 answers

Kanika Sharma 7 years, 3 months ago

1

Akash Rounit 7 years, 3 months ago

Is equal to 1
  • 1 answers

Akash Rounit 7 years, 3 months ago

1/1+2xdx =let the=1+2x dt /2=DX poot intgte 1+2x=t then obtnd I= int 1/t dt = loft +c put value of t ok ??????
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  • 2 answers

Ujjwal Chettri 7 years, 3 months ago

1÷2 [log|x+a| + (square of x)÷2 +bx+c

Ujjwal Chettri 7 years, 3 months ago

1÷2 [log|x+a| + <square of x>÷2 +bx +c
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  • 2 answers

Akash Rounit 7 years, 3 months ago

Your question is wrong broooo????

Akash Bhangi 7 years, 3 months ago

Question is some what wrong bro
  • 1 answers

Harsh Malik 7 years, 3 months ago

-2cos 2x/sin x

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