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  • 1 answers

Siddhant Singh 4 years, 2 months ago

How the solution of this question can be posted in image formate
  • 1 answers

Anurag Chaudhary 4 years, 2 months ago

Ha 1.4 or 6.4 bhi
  • 1 answers

Preeti Dabral 4 years, 2 months ago

TO DETERMINE

CALCULATION

It is given that

Now a relation from A to A is a subset of A × A

Where A × A is the Cartesian product of A and A

We we have to determine a Relation R with the below mentioned property

Now there does not exist any ( a, b) in A × A such that a - b = 10

So the Required Relation is Empty

  • 1 answers

Preeti Dabral 4 years, 3 months ago

Let {tex}{\cos ^{ - 1}}\frac{{12}}{{13}} = \theta{/tex} so that {tex}\cos \theta = \frac{{12}}{{13}}{/tex}
{tex}\therefore \sin \theta = \sqrt {1 - {{\cos }^2}\theta } = \sqrt {1 - \frac{{144}}{{169}}}{/tex}{tex}= \sqrt {\frac{{25}}{{169}}} = \frac{5}{{13}}{/tex}
Again, Let {tex}{\sin ^{ - 1}}\frac{3}{5} = \phi{/tex} so that {tex}\sin \phi = \frac{3}{5}{/tex}
{tex}\therefore \cos \phi = \sqrt {1 - {{\sin }^2}\phi } = \sqrt {1 - \frac{9}{{25}}} = \sqrt {\frac{{16}}{{25}}} = \frac{4}{5}{/tex}
Since {tex}\sin \left( {\theta + \phi } \right) = \sin \theta \cos \phi + \cos \theta \sin \phi {/tex} {tex} = \frac{5}{{13}} \times \frac{4}{5} + \frac{{12}}{{13}} \times \frac{3}{5}{/tex} 
{tex}= \frac{{20 + 36}}{{65}} = \frac{{56}}{{65}}{/tex}
{tex}\Rightarrow \theta + \phi = {\sin ^{ - 1}}\frac{{56}}{{65}}{/tex}
{tex} \Rightarrow {\cos ^{ - 1}}\frac{{12}}{{13}} + {\sin ^{ - 1}}\frac{3}{5} = {\sin ^{ - 1}}\frac{{56}}{{65}}{/tex}

  • 5 answers

Tushar Hooda 4 years, 3 months ago

I hope u will find it helpful

Tushar Hooda 4 years, 3 months ago

Order of matrix p be 2×3

Tushar Hooda 4 years, 3 months ago

Number of family members X=[ 4 2 ​ 6 2 ​ 2 4 ​ ] Daily amount of calories Y= ⎣ ⎢ ⎢ ⎡ ​ 2400 1900 1800 ​ ⎦ ⎥ ⎥ ⎤ ​ Daily amount of proteins Z= ⎣ ⎢ ⎢ ⎡ ​ 45 55 33 ​ ⎦ ⎥ ⎥ ⎤ ​ Total requirement of calories: XY=[ 4 2 ​ 6 2 ​ 2 4 ​ ] ⎣ ⎢ ⎢ ⎡ ​ 2400 1900 1800 ​ ⎦ ⎥ ⎥ ⎤ ​ =[ 24600 15800 ​ ] Total requirement of proteins XZ=[ 4 2 ​ 6 2 ​ 2 4 ​ ] ⎣ ⎢ ⎢ ⎡ ​ 45 55 33 ​ ⎦ ⎥ ⎥ ⎤ ​ =[ 576 332 ​ ]

Tushar Hooda 4 years, 3 months ago

If it is 2 children then answer is :

Tushar Hooda 4 years, 3 months ago

In 2nd line is it 2 men or children
  • 2 answers

Tushar Hooda 4 years, 3 months ago

d(e^sin(cosx) / dx = =e^sin(cosx). Cos(cosx). -sinx =-e^sin(cosx).cos(cosx). Sinx

Tushar Hooda 4 years, 3 months ago

d(e^sin(cosx) / dx = e^sin(cosx). Cos(cosx). -sinx -e^sin(cosx).cos(cosx). Sinx
  • 1 answers

Tushar Hooda 4 years, 3 months ago

tan-¹(sin(π/2) = tan-¹(1) = tan-¹(tanπ/4) = π/4 Thus, π/4 is required principal value as it lies b/w (-π/2 , π/2)
  • 1 answers

Tushar Hooda 4 years, 3 months ago

Cos(2π-π/3) = cos π/3 [ Cos(2π-x) = cosx ] Cosπ/3 = 1/2 Hence solved!!!
  • 1 answers

Ayush Kumar 4 years, 2 months ago

True
  • 1 answers

Badal Barasiya 4 years, 2 months ago

x=asin 3 t dx=a3sin 2 t(cost)dt…(1) y=bcos 3 t dy=b3cos 2 t(−sint)dt ..(2) At t= 2 Π ​ dt dx ​ =0 and hence dx dy ​ =not defined
  • 2 answers

Satyam Satyam 4 years, 2 months ago

Do you use any social media handle maybe I'll help you there

Satyam Satyam 4 years, 2 months ago

I have done it but I don't know to send it to you
  • 5 answers

?⚡Her?️⚡? 4 years, 3 months ago

I am done till dy/dx = ylogy/x now i am confused

?⚡Her?️⚡? 4 years, 3 months ago

I did it roughly now I am own confused

Shashwat Singh 4 years, 3 months ago

Nhi... Answer option (c) correct h.. But aap solution to bhejo...

?⚡Her?️⚡? 4 years, 3 months ago

Ok.. answer is 0 ..??

Shashwat Singh 4 years, 3 months ago

Ohk... bhej do solution ?
  • 3 answers

Sher Singh 4 years, 2 months ago

The relation which is reflexive, symmetric and transitive is said to be equivalence relation . For ex- parallel relation as if a is parallel to b and b is parallel to c then it will be an equivalence relation

Shubham Roy 4 years, 3 months ago

Parallel lines: a parallel to b, b parallel to c

Parthib Ghosh 4 years, 3 months ago

A Relation which is reflexive, symmetric and transitive.
  • 0 answers
??
  • 5 answers

?⚡Her?️⚡? 4 years, 3 months ago

What happened dont want to post ?

?⚡Her?️⚡? 4 years, 3 months ago

Ok but I want to check if what I am thinking is right. Don't worry I am not thinking you are wrong

?⚡Her?️⚡? 4 years, 3 months ago

File is pdf ? If other format, you can upload on google drive and then share via link or iframe

Shashwat Singh 4 years, 3 months ago

But question sahi hai... Wahi hoga ?

Shashwat Singh 4 years, 3 months ago

Nahi... vo ek file me hai.. Assignment ka question hai.. Uski link nhi send ho payegi...
???
  • 5 answers

?⚡Her?️⚡? 4 years, 3 months ago

See also y²/2ycosx will become y/2cosx check if its wrong

?⚡Her?️⚡? 4 years, 3 months ago

Ok

Shashwat Singh 4 years, 3 months ago

<a href="https://ibb.co/dgksyk0"></a>

?⚡Her?️⚡? 4 years, 3 months ago

?⚡Her?️⚡? 4 years, 3 months ago

Plz resend question or check if mine is right
  • 5 answers

Shashwat Singh 4 years, 3 months ago

Hmm... Uske baad 4x bhi hai question me..

?⚡Her?️⚡? 4 years, 3 months ago

Means only tan-1x power...... and sin-1x multiply by cosx multiply by sinxloga right?

Shashwat Singh 4 years, 3 months ago

Inverse are respect to 'x' bro... usme likhna bhul gyi... ?

?⚡Her?️⚡? 4 years, 3 months ago

Besides sin-1 of what ? You have written in bracket that means multiply. Bracket should only be for the amgle

?⚡Her?️⚡? 4 years, 3 months ago

Wrong question. tan-1 of what? That all are powers.
  • 1 answers

Sia ? 4 years, 3 months ago

Please ask question with complete information.

  • 0 answers
  • 2 answers

Maanuj Gupta 4 years, 3 months ago

1

Nandu Krishna 4 years, 3 months ago

Find double diff.

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