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Lakshmi Kumari 7 years, 1 month ago

1+t^2/1+t^4 dt = t^2 (1/t^2+1)/t^4 (1/t^4+1) ------------1 Put y=t-1/t = y^2=(t-1/t)^2 y^2=t^2+1/t^2-2----------a Dy/dt=1+1/t^2 Dy=1+1/t^2dt -----------2 Put 2 in 1 & a in 1 =Dy/y^2+2 from eq-a = 1/root2 tan inverse(y/root2) + c after that put value of y then the answer will complete : wkt tan inversex=1/1+x^2 Plzz write it in you note book for better understand how i wrote this dont take it orally plzz write it in your noteboom and then understand this one Thank you ....
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Lakshmi Kumari 7 years, 1 month ago

This is not possible how to solve integer This is only a no. Which can assume not to solve Any query give message or send ...
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Rahul Sehlangia 7 years, 1 month ago

[tanx+1+√2tanx]+c

Prashant Sangwan 7 years, 1 month ago

No answer bro
  • 1 answers

Lakshmi Kumari 7 years, 1 month ago

Put cosx=1-tan square x/2/1-tan square x/2 and sinx = 2tan x/2/1+tan square x/2 Then put t=tanx/2 Differentiate and put the value and inetgrate If any problem to solve this question ask again and tell me to solve this ok
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Tarun Goswami 7 years, 1 month ago

No easy way for maths

Ayush Parija 7 years, 1 month ago

Pratice
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Amandeep Kumar 7 years, 1 month ago

1+ x^2 = t
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Amandeep Kumar 7 years, 1 month ago

Ans is x

Dhruv Bansal 7 years, 1 month ago

Sin2x/2 -2cos^x
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Dhruv Bansal 7 years, 1 month ago

independent events- P(A intersection B)=P(A).P(B)

Ashutosh Kumar 7 years, 1 month ago

P(A intersection B) =PA.PB
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Samyak Jain 7 years, 1 month ago

2i +5j -4k dot product witn 3i +2j +4k is 0 thats why lines are prrpndclr
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Amandeep Kumar 7 years, 1 month ago

Sayad integrate Karna ho

Drake Verma 7 years, 1 month ago

What we have to find it in this question?Post detail fully so that u can get a appropriate ans
  • 2 answers

Ritu Yadav 7 years, 1 month ago

0

Yogita Ingle 7 years, 1 month ago

000

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Papa . 7 years, 1 month ago

Vectors which posses same magnitude and direction
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Anand Raj 7 years, 1 month ago

Yes
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G K 7 years, 1 month ago

Completing the square se krlo
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