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  • 1 answers

Amandeep Kumar 7 years, 1 month ago

Watch a video by aman dhatarwal .. How to study maths in last 4 months
  • 2 answers

Dhruv Bansal 7 years, 1 month ago

if limit is given...then first check in which range it is positive and in which range it is negative then make its two parts positive -negative then solve it

Shankar Das Bamniya 7 years, 1 month ago

_ cos x
  • 2 answers

Honey 8 7 years, 1 month ago

Type the question

Amandeep Kumar 7 years, 1 month ago

I don't have Rd sharma plz question type kar do
  • 1 answers

Aakash Sir 7 years, 1 month ago

SinA+sinB
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Abhay Agrahari 7 years, 1 month ago

π/2 logπ/2
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Dhruv G 7 years, 1 month ago

Int (1-sinx)/(1-cosx)•dx......➡in numerator sinx can be written as 2sinx/2•cosx/2......and in denominator 1-cosx can be written as 2sin^2 x/2.......➡final form: int (1-sinx/2•cosx/2)/(2sin^2x/2)•dx.......➡break lcm...➡use identity 1/sinx=cscx and cosx/sinx=cotx....➡finally you will have this form: int (1/2•csc^2 x/2-cotx/2)•dx........➡ integrate nd ur final ans➡ -1/2•cot x/2+logsinx/2+C....................(where cscx=cosecx)?
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Sandeep Singh 7 years, 1 month ago

Just cool down and bileve in ur self do quality study, not quantity what ever u prepared just do ur best in it

Sanjeet Yadav 7 years, 1 month ago

Now syllabus it's up-to end so give maximum time to self study. I suggest you should try to overcome to your weak hold.
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Priyanka Balhara 7 years, 1 month ago

First diff.power 1.2sin(x^2) Second diff fun. 2then=2sin(x^2)cos(x^2) Third diff. X^2 3=2sin(x^2)cos(x^2)2x 4th siplify (Sin2x)^2(x)

Mohammad Javed 7 years, 1 month ago

Cos2x=1-2Sin'2x ?use this formula
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Priyanka Malik 7 years, 1 month ago

absinx
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Himanshu Kain 7 years, 1 month ago

May i know the method of solving it

Deepak Soni 7 years, 1 month ago

X/2+sin2x/4
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Aisha Gupta 7 years, 1 month ago

For integratin sin fñ frinm first principle u have to use the formula f( a+h) + f( a+2h)+f(a+3h).....................f(a+nh) after solving use the standered formula of sina+ sin(a+b) + sin(a+2b) ..................+sin(a+nb)=[sin nb/2(sina+nb/2)]/sinb/2 U will get the required answer
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Priyanka Malik 7 years, 1 month ago

A^2+B^2 + 2AB

Abhay Singh Tomar 7 years, 1 month ago

Very tough question

Mithra Mithra 7 years, 1 month ago

I think for this toughest question, i have to call Ramanujan ?

Amandeep Kumar 7 years, 1 month ago

This is the toughest questions I have ever seen in my life..?

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