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  • 1 answers

Abhinav Thakur 7 years ago

10
  • 1 answers
Go to File Manager in your Mobile -> Then Click Android -> Click Data -> Open MyCBSEguide folder ->... Then Delete What You Don't Want. ☺️
  • 1 answers

Jag Shukl 7 years ago

Vedantu previous year question paper for cbse class 12th math.....
Cgv
  • 1 answers

Amarjeet Singh 7 years ago

Can u explain it
  • 1 answers
1/2a log(a+x/a-x)
  • 3 answers

E S 7 years ago

-2x/√(1-x^2)

Rishabh Thakur 7 years ago

1/root(1-x2)

 

Rishabh Thakur 7 years ago

x2

  • 1 answers

Rupali Agrawal 7 years ago

What to do with it differentiation or integration ? Differentiation: 1/x Integration: by ilate rule
  • 2 answers

Sanoj S Nair 7 years ago

Yaaaa thats it
Graphs in functions And types of relation
  • 2 answers

Priyanka Malik 7 years ago

Using variable separable.... dy=sin inverse x dx......integrating both sides......y=x sin inverse x + root (1-x^2)/2

Roshan Patel 7 years ago

1/(1-x^2)^1/2
  • 2 answers
Sin-1(sinx-cosx)

O Singh 7 years ago

Put sin2x=1-(sinx-cosx)^2 and then substitute sinx - cos x as t . U will get √ 1-t^2 in denominator and then solve it.
  • 1 answers

Rupali Agrawal 7 years ago

Rationalise: (1/1+sinx)(1-sinx/1-sinx) =(1-sinx)(1-sin^2 x) =(1-sinx)(cos^2 x) =(sec^2 x - tanxsecx) = integration of sec2x is tanx and tanxsecx is secx now put the value of limits and u'll get ur answer.
  • 2 answers

Priyanka Malik 7 years ago

× and ÷ by 2.....in numerator use 2sinx=sinx+sinx...and then add and subt cosx....separate the denominator upon sinx+cosx and sinx-cosx......and then solve..........

Priyanka Malik 7 years ago

Change in terms of sinx and cosx.......in denominator open sin^3x+cos^3x=*(sinx+cosx
  • 1 answers
What ' denotes???
  • 1 answers

Ashutosh Kumar 7 years ago

Add some previous years papers and latest sample papers
  • 3 answers

Hari Haran 7 years ago

Cos o`is 1

E S 7 years, 1 month ago

1

Rahul Jat 7 years, 1 month ago

70

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