No products in the cart.

Ask questions which are clear, concise and easy to understand.

Ask Question
  • 1 answers

Afzal Bari 6 years, 11 months ago

Show that AB is an scalar multiple of AC
  • 1 answers

Gunjan Agarwal 7 years ago

Sec x + C
  • 1 answers

Gunjan Agarwal 7 years ago

log|sec x|+C
pnr
  • 0 answers
  • 0 answers
  • 0 answers
  • 6 answers

Deepak Jindal 7 years ago

xlogx-x+c

Deepak Sharma 7 years ago

x logx - x + C (use integrqtion by parts (1.logx) logx as 1st & one as 2nd function

Smani ... 7 years ago

xlogx-x

Satyawan Singh 7 years ago

x(logx - 1) + c

Ankit Kumar 7 years ago

1/x+C

Jatin Sharma 7 years ago

1/x+c
  • 1 answers

Saurav Kumar 7 years ago

seven
  • 4 answers

Aryan Singhania 7 years ago

Haha lol

Aryan Khatri 7 years ago

Tu fail h

Afzal Bari 7 years ago

??

Rajat Dhull 7 years ago

There can be infinite values. Aur ha esa question kahin par poocha nahi jata hai. Bina mtlb k ques. mat poocha kro.
  • 2 answers

Deepak Jindal 7 years ago

x=2

Yogita Ingle 7 years ago

1 + 3 + x = 6
4 + x = 6
x = 6 - 4
x = 2

  • 2 answers

Ashish Singh 7 years ago

using product rule

 

Ajit Kumar 7 years ago

Let sinxy=t Diffentiate Cosxy=dt/dxy dy/dx=t dt/dxy Y=t^2/2 Y=sin^2xy
  • 1 answers

S M 7 years ago

Expand and find the roots ,take them as breaking points and check whether incr or decr by putting values near breaking points if -ve then decr and vice versa
  • 1 answers
root(sin x) is not integrable, Because, there does not exist any function whose derivative is root(sin x)....
  • 1 answers

Sia ? 4 years, 8 months ago

3.99998430568

  • 0 answers
  • 1 answers
Let 1=0/0=2 Therefore, 1=0/0=2 H.P.
  • 2 answers

Liton Barman 7 years ago

Given , y=sin^2(x^2) -------(i) And we have to differentiate it with x^2. First of all, let t=x^2 So, eq(i) become y=sin^2(t) ----------(ii) And we know that cos 2a=1-2sin^2(a): =>sin^2(t)=(1/2)(1-cos 2t) So eq(ii) become y=(1/2)-(1/2)(cos2t) Now differentiating w.r.t. x^2 i.e. t : dy/dt = sin 2t => dy/d(x^2) = sin 2(x^2) : Hence, solved.... Thanks....

Jatin Sharma 7 years ago

2cosx^2sinx^2

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App