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  • 2 answers

Atrey Shah 3 years, 9 months ago

tan‐1(x+y/1-xy) if x×y<1

Bhumika Agrawal 3 years, 9 months ago

Tan^-1 (x + y)/(1 - xy)
  • 1 answers

Bhumika Agrawal 3 years, 9 months ago

Btana kya h
  • 1 answers

Bhumika Agrawal 3 years, 9 months ago

In which experiment
  • 0 answers
  • 0 answers
  • 0 answers
  • 1 answers

Bhumika Agrawal 3 years, 9 months ago

Taking RHS sin^2 (x/2)+cos^2 (x/2)+2sin (x/2)cos (x/2)=1+sin2y {Let x/2=y, sin^2 y + cos^2 y=1, 2 sin y cos y=sin2} put the value of y 1+sin2 (x/2) = 1+sinx
  • 1 answers

Bhumika Agrawal 3 years, 9 months ago

For (0,4) the value of z=16
  • 2 answers

Bhumika Agrawal 3 years, 9 months ago

6 x^(-2/5) - (7/2) x^(5/2) + 16 x^(2/3)

. . 3 years, 9 months ago

f(x)= 10x^3/5 - x^7/2+6x^8/3-3 dy/dx= 30/5 x^(-2/5) -7/2x^(5/2)+16x^5/3
  • 2 answers

Bhumika Agrawal 3 years, 9 months ago

2sin(xy).cos (xy).(x dy/dx+ y)

Neelam Baghel 3 years, 9 months ago

Find the derivatives
  • 1 answers

Bhumika Agrawal 3 years, 9 months ago

Yes or shops pr bhi aagye
  • 1 answers

Bhumika Agrawal 3 years, 9 months ago

Krna kya h
  • 2 answers

Bhumika Agrawal 3 years, 9 months ago

Yes ask

Raghav Kumar 3 years, 9 months ago

What help u need
  • 1 answers

Bhumika Agrawal 3 years, 9 months ago

Which question
  • 3 answers

Bhumika Agrawal 3 years, 9 months ago

This is not reflexive. This is not symmetric. This is transitive

Bhumika Agrawal 3 years, 9 months ago

1 ka mtlb

Ronak Patidar Patidar 3 years, 9 months ago

1
  • 1 answers

Bhumika Agrawal 3 years, 9 months ago

In which lab manual
  • 3 answers

Bhumika Agrawal 3 years, 9 months ago

Image of ( x , y)  in  line  y = x   is  ( y , x) Hence image of ( 1, 2)  in line y = x  is  ( 2 , 1) and graph  y = 2ˣ    becomes   x = 2^y2y taking log both sides => log x  = log  2^y2y => log x = y log 2 => log x / log 2 = y => y = log x / log 2 => y = log₂x Image of ordered pair (1,2) on the graph of y=2^x in y=x is (2 , 1) It lies on the graph of y= log₂x

Haigriv Patel 3 years, 9 months ago

Image of ( x , y)  in  line  y = x   is  ( y , x) Hence image of ( 1, 2)  in line y = x  is  ( 2 , 1) and graph  y = 2ˣ    becomes   x = 2^y2y taking log both sides => log x  = log  2^y2y => log x = y log 2 => log x / log 2 = y => y = log x / log 2 => y = log₂x Image of ordered pair (1,2) on the graph of y=2^x in y=x is (2 , 1) It lies on the graph of y= log₂x

Haigriv Patel 3 years, 9 months ago

Image of ( x , y) in line y = x is ( y , x) Hence image of ( 1, 2) in line y = x is ( 2 , 1) and graph y = 2ˣ becomes x = 2^y2 y taking log both sides => log x = log 2^y2 y => log x = y log 2 => log x / log 2 = y => y = log x / log 2 => y = log₂x Image of ordered pair (1,2) on the graph of y=2^x in y=x is (2 , 1) It lies on the graph of y= log₂x
  • 1 answers

Bhumika Agrawal 3 years, 9 months ago

LHL lim x tends to 2 f (x) lim x tends to 2 2x+3 2×2+3=7 RHL lim x tends to 2 f (x) lim x tends to 2 2x-3 2×2-3=1 f (2) 2x+3 2×2+3=7 LHL is not equal to RHL is not equal to f (x)
  • 2 answers

Raveena Jakhu 3 years, 9 months ago

What are you write

Bhumika Agrawal 3 years, 9 months ago

Ye kya likha h

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