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Dharshika As 6 years, 10 months ago

you can get it in cbse.nic.in link
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Vansh Rastogi 6 years, 10 months ago

Learning won't help Practice more n more !
  • 1 answers

Shrey Shekhar 6 years, 10 months ago

The only way to master integration is to practice questions daily(according to your need) and learn the formulae by heart (which will automatically happen once you start practicing daily)
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Rajat Chawla 6 years, 10 months ago

Use 2πr=31.4 and after getting r use πr*r
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Priyam Sonkar 6 years, 10 months ago

Use formula 2sinxsiny
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Gaurav Seth 6 years, 10 months ago

You ll get the syllabus of respective subjects and class syllabuss in mycbseguide website or app. 

Select Board then class then subject  then syllabus.

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Akash Shahi 6 years, 10 months ago

2 se multiply, 2 se divide
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Prateek Aggarwal 6 years, 10 months ago

|adj A|=| a|*n-1 |A(adjA|=A*n×|a^n-1l
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Priyansh Kamthan 6 years, 10 months ago

180°
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Ritik Chaudhary 6 years, 10 months ago

Question is wrong.
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Mansi Gupta 6 years, 10 months ago

Cos3x=4cos^3x-3cosx
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Gaurav Seth 6 years, 10 months ago

<pre> Let ‘L’ be the fot of perpendicular AL, which divides BC in the ratio a:1 = (3a+4)/(a+1),(5a+7)/(a+1),(3a+1)/(a+1) Also D.R’s of the BC and AL are , D.R’s of BC= -1,-2,2 D.R’s of AL =((3a+4)/(a+1))-1,((5a+7)/(a+1))-0,((3a+1)/(a+1))-3 since AL is perpendicular to BC Cos90 = 0 →BC, AL are the lines with D.R’s as magnitudes 2(((3a+4)/(a+1))-1)-2(((5a+7)/(a+1))-0)+(((3a+1)/(a+1))-3)2=0 we get a=-7/4 So L=(5/3,7/3,17/3)</pre>
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Vipin Kumar 6 years, 10 months ago

✓(x+1)²√xdx=✓(x+1)²x½ ✓(x²+1+2x)x½dx = ✓x^5/2+ x½ + 2x^3/2dx 2×2/7×x^5/7 +2/3×x^3/2+ 2/5×^5/2+C

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