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Question: Two schools A and B decided to award prizes to their students for three values—honesty (x), punctuality y and obedience School A decided to award a total of Rs 11000 for three values to 5, 4, 3 students respectively and school B decided to award a total of Rs 10700 for three values to 4, 3 and 5 students respectively. If all together, it amounts to Rs 21700 then
i)Represent this by matrix equation and form linear equation using matrix multiplication.
ii)Is it possible to solve so obtained equations using matrices ?
iii)Which value you prefer to be rewarded ?
Answer:
Ans.
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Sahil Sama 6 years, 3 months ago
2Thank You