CBSE > Class 12 > Mathematics | CBSE Board | Homework Help

One thing u can do... write all formula 30 times.... truly i am saying... otherwisr keep a challenge or bet with ur friend for what ever u want... that u will learn all formula perfectly and write them otherwise.. i will write it 100 times... i kept this challenge with my sir and won the bet

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Aradhya Agarwal 6 years, 2 months ago

Same here

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Harsh Mishra 6 years, 2 months ago

Bhai, pata chal jaye toh mujhe bhee bata dena........

2Thank You

ANSWER

Application of derivatives aur integration me kya difference hai?

Posted by Ritish Manhas 6 years, 2 months ago

CBSE > Class 12 > Mathematics

0 answers

ANSWER

Sin 1/2

Posted by Ritish Manhas 6 years, 2 months ago

CBSE > Class 12 > Mathematics

3 answers

S.... ????☺ 6 years, 2 months ago

Sin^-1(π/6)

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Miss Mor 6 years, 2 months ago

Deepak jindal your answer is wrong sin 30° is 1/2 not sin 1/2

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Deepak Jindal 6 years, 2 months ago

Sin 30°

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ANSWER

Derivative of 1+cos theta

Posted by Ayush Dutta 6 years, 2 months ago

CBSE > Class 12 > Mathematics

7 answers

Ajay Sharma 6 years, 2 months ago

-sin theta

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Shiva Kumar 6 years, 2 months ago

Q 1+cos theta Ans,... 0-sin theta = -sin theta

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Sayasha Singh 6 years, 2 months ago

-Sin theta

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Khushi Gupta 6 years, 2 months ago

-sin theta

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Akash Narayanaswamy 6 years, 2 months ago

-sin theta

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Dolly ?️ 6 years, 2 months ago

-sin theta

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Piyush R 6 years, 2 months ago

-sin theta

2Thank You

ANSWER

how much time should I devote to maths everyday as i m quite weak in this subject?

Posted by Clash With . 6 years, 2 months ago

CBSE > Class 12 > Mathematics

5 answers

Akash Narayanaswamy 6 years, 2 months ago

?☺?????

0Thank You

Miss Mor 6 years, 2 months ago

Actually i prefer u dont fix time...u should fix topics...ki aj muje ye topic clear krna h...then u go deeply into that...day by day ur maths will be strong

3Thank You

Řøhăň Řąjpůť ✌️✊ 6 years, 2 months ago

if u are weak in maths give 3 hours a day daily.

1Thank You

Priya Dharshini ? 6 years, 2 months ago

Practice max 30 to 40 questions everyday... try to complete within 2 hrs.. it will be better.... take u have 5 hrs for self study.. 2 hrd for maths, 2 hrs for chemistry and physics... then do ur english and all the fifth subjects... h.w not in self study...

4Thank You

S.... ????☺ 6 years, 2 months ago

Maximum 3-4 hour in a day but do daily practice

1Thank You

ANSWER

What is composition of function

Posted by Ankit Kumar 6 years, 2 months ago

CBSE > Class 12 > Mathematics

2 answers

Miss Mor 6 years, 2 months ago

Composition of function means ek fn ko dusre ki terms me define krna....ye GOF or FOG composition fn hote hain

1Thank You

Priya Priya 6 years, 2 months ago

Composition of function basically means mixing of two or more than two functions . They can be mixed(composite) by applying certain operations like addition , subtraction, division , multiplicatuon etc

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ANSWER

Cos2°

Posted by Vansh Verma 6 years, 2 months ago

CBSE > Class 12 > Mathematics

1 answers

Prashant Maurya 6 years, 2 months ago

x=cos^1 2°

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ANSWER

6.5

Posted by Chandan Kumar 6 years, 2 months ago

CBSE > Class 12 > Mathematics

1 answers

Priya Dharshini ? 6 years, 2 months ago

It is there in this app..

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ANSWER

If (e^y-e^-y)/2 = x then show that dy/dx=1/√(1+x^2)

Posted by Jagdeep Singh Kohli 6 years, 2 months ago

CBSE > Class 12 > Mathematics

1 answers

Miss Mor 6 years, 2 months ago

Use 1/y instead e^-y and diff wrt y

1Thank You

ANSWER

Chapter 7 exercise 7.6

Posted by Sk Wasim Raja 6 years, 2 months ago

CBSE > Class 12 > Mathematics

1 answers

Sia ? 6 years, 2 months ago

Check here : https://mycbseguide.com/ncert-solutions.html

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ANSWER

Chapter 7 ex-7.6 question 15

Posted by Sk Wasim Raja 6 years, 2 months ago

CBSE > Class 12 > Mathematics

2 answers

Sandeep Tyagi Sandeep Tyagi 6 years, 2 months ago

Take logx as a first function and x square +1 ii function then integrate it by product rule

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Sia ? 6 years, 2 months ago

Check here : https://mycbseguide.com/ncert-solutions.html

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ANSWER

If cos^-1(x/a)+cos^-1(y/b)=@ Then prove that x^2/a^2 +y^2/b^2 - 2xy/ab=sin^2 (@)

Posted by Dolly ?️ 6 years, 2 months ago

CBSE > Class 12 > Mathematics

3 answers

Sia ? 6 years, 2 months ago

Given, {tex}{\cos ^{ - 1}}\frac{x}{a} + {\cos ^{ - 1}}\frac{y}{b} = a{/tex}
{tex}\left[ {\because {{\cos }^{ - 1}}x + {{\cos }^{ - 1}}y} \right. \left. { = {{\cos }^{ - 1}}\left( {xy - \sqrt {1 - {x^2}} \sqrt {1 - {y^2}} } \right)} \right]{/tex}
{tex}\Rightarrow {\cos ^{ - 1}}\left[ {\frac{x}{a}.\frac{y}{b} - \sqrt {1 - \frac{{{x^2}}}{{{a^2}}}} .\sqrt {1 - \frac{{{y^2}}}{{{b^2}}}} } \right] = a{/tex}
{tex}\Rightarrow\frac{{xy}}{{ab}} - \sqrt {1 - \frac{{{x^2}}}{{{a^2}}}} \cdot \sqrt {1 - \frac{{{y^2}}}{{{b^2}}}} = \cos a{/tex}
{tex}\Rightarrow \frac{{xy}}{{ab}} - \cos a = \sqrt {1 - \frac{{{x^2}}}{{{a^2}}}} \sqrt {1 - \frac{{{y^2}}}{{{b^2}}}}{/tex}
On squaring both side, we get
{tex}\Rightarrow{\left( {\frac{{xy}}{{ab}} - \cos a } \right)^2} = {\left( {\sqrt {1 - \frac{{{x^2}}}{{{a^2}}}} \sqrt {1 - \frac{{{y^2}}}{{{b^2}}}} } \right)^2}{/tex}
{tex}\Rightarrow \frac{{{x^2}{y^2}}}{{{a^2}{b^2}}} + {\cos ^2}a - 2.\frac{{xy}}{{ab}}.\cos a = \left( {1 - \frac{{{x^2}}}{{{a^2}}}} \right)\left( {1 - \frac{{{y^2}}}{{{b^2}}}} \right){/tex}
{tex}\Rightarrow\frac{{{x^2}{y^2}}}{{{a^2}{b^2}}} + {\cos ^2}a - 2\frac{{xy}}{{ab}}\cos a = 1 - \frac{{{y^2}}}{{{b^2}}} - \frac{{{x^2}}}{{{a^2}}} + \frac{{{x^2}{y^2}}}{{{a^2}{b^2}}}{/tex}
{tex}\Rightarrow\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} - 2\frac{{xy}}{{ab}}\cos a = 1 - {\cos ^2}a{/tex}
{tex}\Rightarrow\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} - 2\frac{{xy}}{{ab}}\cos a = {\sin ^2}a{/tex}

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Dolly ?️ 6 years, 2 months ago

Yes, you are right.

0Thank You

Miss Mor 6 years, 2 months ago

Ques is incomplete i guess...bcz in to prove 2xy/ab doesn't occur but 2 costhetaxy/ab comes as solution

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ANSWER

Sec[tan^-1(y/2)], find its value

Posted by Dolly ?️ 6 years, 2 months ago

CBSE > Class 12 > Mathematics

2 answers

Sia ? 6 years, 2 months ago

Let {tex}{\tan ^{ - 1}}\frac{y}{2} = \theta{/tex}, where {tex}\theta \in \left( { - \frac{\pi }{2},\;\frac{\pi }{2}} \right){/tex}. So, {tex}\tan \theta = \frac{y}{2}{/tex}, which gives {tex}\sec \theta = \frac{{\sqrt {4 + {y^2}} }}{2}{/tex}.

Therefore, {tex}\sec \left( {{{\tan }^{ - 1}}\frac{y}{2}} \right) = \sec \theta = \frac{{\sqrt {4 + {y^2}} }}{2}{/tex}.

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Miss Mor 6 years, 2 months ago

Value is under the root 4+y^2 by 2

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ANSWER

Find the value of : 4tan^-1(1/5) - tan^-1(1/239) ?

Posted by Dolly ?️ 6 years, 2 months ago

CBSE > Class 12 > Mathematics

1 answers

Sia ? 6 years, 2 months ago

We have, {tex}4{\tan ^{ - 1}}\frac{1}{5} - {\tan ^{ - 1}}\frac{1}{{239}}{/tex}
{tex}= 2.2{\tan ^{ - 1}}\frac{1}{5} - {\tan ^{ - 1}}\frac{1}{{239}}{/tex}
{tex}= 2\left[ {{{\tan }^{ - 1}}\frac{{\frac{2}{5}}}{{1 - {{\left( {\frac{1}{5}} \right)}^2}}}} \right] - {\tan ^{ - 1}}\frac{1}{{239}}{/tex} {tex}\left[ {\because 2{{\tan }^{ - 1}}x = {{\tan }^{ - 1}}\left( {\frac{{2x}}{{1 - {x^2}}}} \right)} \right]{/tex}
{tex} = 2.\left[ {{{\tan }^{ - 1}}\left( {\frac{{\frac{2}{5}}}{{1 - \frac{1}{{25}}}}} \right)} \right] - {\tan ^{ - 1}}\frac{1}{{239}}{/tex}
{tex} = 2.\left[ {{{\tan }^{ - 1}}\left( {\frac{{\frac{2}{5}}}{{\frac{{24}}{{25}}}}} \right)} \right] - {\tan ^{ - 1}}\frac{1}{{239}}{/tex}
{tex}= 2{\tan ^{ - 1}}\frac{5}{{12}} - ta{n^{ - 1}}\frac{1}{{239}}{/tex}
{tex}= {\tan ^{ - 1}}\frac{{2.\frac{5}{{12}}}}{{1 - {{\left( {\frac{5}{{12}}} \right)}^2}}} - {\tan ^{ - 1}}\frac{1}{{239}}{/tex} {tex}\left[ {\because 2{{\tan }^{ - 1}}x = {{\tan }^{ - 1}}\left( {\frac{{2x}}{{1 - {x^2}}}} \right)} \right]{/tex}
{tex} = {\tan ^{ - 1}}\left( {\frac{{\frac{5}{6}}}{{1 - \frac{{25}}{{144}}}}} \right) - {\tan ^{ - 1}}\frac{1}{{239}}{/tex}
{tex} = {\tan ^{ - 1}}\left( {\frac{{144 \times 5}}{{119 \times 6}}} \right) - {\tan ^{ - 1}}\frac{1}{{239}}{/tex}
{tex} = {\tan ^{ - 1}}\left( {\frac{{120}}{{199}}} \right) - {\tan ^{ - 1}}\frac{1}{{239}}{/tex}
{tex} = {\tan ^{ - 1}}\left( {\frac{{\frac{{120}}{{119}} - \frac{1}{{239}}}}{{1 + \frac{{120}}{{119}} \cdot \frac{1}{{239}}}}} \right){/tex}{tex}\left[ {\because \;{{\tan }^{ - 1}}x - {{\tan }^{ - 1}}y = {{\tan }^{ - 1}}\left( {\frac{{x - y}}{{1 + xy}}} \right)} \right]{/tex}
{tex} = {\tan ^{ - 1}}\left( {\frac{{120 \times 239 - 119}}{{119 \times 239 \times 120}}} \right){/tex}
{tex} = {\tan ^{ - 1}}\left[ {\frac{{28680 - 119}}{{28441 + 120}}} \right] = {\tan ^{ - 1}}\frac{{28561}}{{28561}}{/tex}
{tex}= {\tan ^{ - 1}}(1) = {\tan ^{ - 1}}\left( {\tan \frac{\pi }{4}} \right) = \frac{\pi }{4}{/tex}

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ANSWER

value of matrix

Posted by Abhishek Kumar 6 years, 2 months ago

CBSE > Class 12 > Mathematics

1 answers

Komal Garg 6 years, 2 months ago

No value

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ANSWER

Which is grater, tan(1)or tan^-1(1)?

Posted by Dolly ?️ 6 years, 2 months ago

CBSE > Class 12 > Mathematics

1 answers

Rajat Barwar 6 years, 2 months ago

According to value tan inverse 1 is π/4= nearly 0.78 and tan(1) is greater than 1 by graph of tan... Hope it may help you..

3Thank You

ANSWER

Construct a 3×2 matrix whose element is given by aij=½|i-3j|. Only find a21 and a21 Thank u

Posted by Ashutosh Chauhan 6 years, 2 months ago

CBSE > Class 12 > Mathematics

3 answers

Miss Mor 6 years, 2 months ago

A22= 2

0Thank You

Ashutosh Chauhan 6 years, 2 months ago

Aman And. Is ½ and 2

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Ashutosh Chauhan 6 years, 2 months ago

Mistake a22 find

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ANSWER

Completeing square method use in integration

Posted by Sumit Siwach 6 years, 2 months ago

CBSE > Class 12 > Mathematics

2 answers

Sandeep Tyagi Sandeep Tyagi 6 years, 2 months ago

Yes in special integration

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Priya Pandey 6 years, 2 months ago

Yes in special integration it is use

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ANSWER

Intigration of root over a^2+b^2

Posted by Arun Yadav 6 years, 2 months ago

CBSE > Class 12 > Mathematics

1 answers

Dolly ?️ 6 years, 2 months ago

X. Root(a^2+b^2)

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ANSWER

Ncert is sufficient book for board exam... yes or no what we prefer a book for exam

Posted by Samyak Jain 6 years, 2 months ago

CBSE > Class 12 > Mathematics

6 answers

Miss Mor 6 years, 2 months ago

Best is Elements i think...bcz it covers ncert, exampler, and sample papers from cbse. And paper is set from there books only. No nee to do any other book if u do elements of mathematics eith examples in it

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Priya Pandey 6 years, 2 months ago

Yes but for 100 it's not enough,i refer rd sharma

1Thank You

Priya Dharshini ? 6 years, 2 months ago

Refer oswall sample papers rd sharma, al arora, arihant... then only u can score 90+ in these subjects... according to me hardly u get 60% from ncert exact questions but remaininh would be ncert based conceptual questions..

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Priya Dharshini ? 6 years, 2 months ago

See for chemistry it is almost okay with ncert... (full book each line with each question) but for physics and maths u need to refer guides...

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Řøhăň Řąjpůť ✌️✊ 6 years, 2 months ago

no for maths ncert is must but not sufficient do maximum questions from Rd sharma .

1Thank You

Ɽøⱨł₮ ₲Ʉ₱₮₳ 6 years, 2 months ago

Phy is enough but maths for RD sharma CHE for ModernABC+

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ANSWER

Find the equation of tangent and normal to the curve x^2/3 + y^2/3 = 2 at the point (1 1).