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  • 3 answers

Avinash Parmar 6 years, 2 months ago

-log|cosx| +C

Isha Raj 6 years, 2 months ago

log |secx| +c

Vishakha Dhiman 6 years, 2 months ago

Put tanx=t^2
  • 2 answers

Harsha Vella 6 years, 2 months ago

Sin^2x/2

Neha Choudhary 6 years, 2 months ago

Convert it into 1+cos2x/2 then solve it
  • 0 answers
  • 1 answers

Neha Choudhary 6 years, 2 months ago

Let tan inverse x be y so x is equal to tany and then solve
  • 3 answers

Muskan Jangra 6 years, 2 months ago

Do every question of mis. Carefully

Muskan Jangra 6 years, 2 months ago

Kyuki hamara math ka exam ho gaya hai Isliye pata hai

Muskan Jangra 6 years, 2 months ago

From limits and mis. Ex.
  • 1 answers

Muskan Jangra 6 years, 2 months ago

Add and subtract the matrices. This question has four or five parts .
  • 1 answers

Pooja Bhakar 6 years, 2 months ago

This can be written as 1+1/x^4-1 .Now solve these two parts different different . I hope this answer will help you.........
  • 2 answers

Muskan Jangra 6 years, 2 months ago

Yes he is right

Sandeep Tyagi Sandeep Tyagi 6 years, 2 months ago

Learn formulas of each chapter comes in your exam and 1 or 2 questions on each formula
  • 3 answers

Neha Choudhary 6 years, 2 months ago

2sina cosb =sin(a+b) cos(a-b )

Abhinandan Choudhary 6 years, 2 months ago

1/2£2sin2x cos3x dx ; £-represent integration =1/2£sin5x+cos(-x) dx {*2sinA.cosB=sin(A+B)+cos(A-B) =1/2£sin5x dx+1/2£cos(-x)dx =1/2 cos5x/5 +1/2sinx

Nitin Tomar 6 years, 2 months ago

Divide and multiply it by 2 then open formulae. 2sinA cosB.
  • 6 answers

Avinash Parmar 6 years, 2 months ago

5

Neha Choudhary 6 years, 2 months ago

5

Muskan Jangra 6 years, 2 months ago

d/dx(5x)=5d/dx(x)=5×1=5

Tanu Chauhan 6 years, 2 months ago

5

Sandeep Tyagi Sandeep Tyagi 6 years, 2 months ago

5

Moni Sheoran@2#3% 6 years, 2 months ago

5
  • 4 answers

Neha Choudhary 6 years, 2 months ago

3×3 ;4×4

Muskan Jangra 6 years, 2 months ago

3×3and4×4

Moni Sheoran@2#3% 6 years, 2 months ago

order of ab is 3x3 & order of ba is 4x4......

Pooja Bhakar 6 years, 2 months ago

Order of ab is 3×3 and order of ba is 4×4....
  • 2 answers

Pooja Bhakar 6 years, 2 months ago

Sin4x(2Sin4xCos4x)dx = 2Sin^2 4x Cos4x dx now put sin4x =t so that cos4x dx =4dt we get 8t^2dt now you can solve it easily after solving put the value of t in answer.......

Dolly ?️ 6 years, 2 months ago

Sin4x(2sin4x.cos4x) 2.sin^2(4x).cos4x 2{(1-cos2(4x))÷2}.cos4x Cos4x - cos8x.cos4x 1/2{2cos4x-2cos8x.Cos4x} 1/2{2cos4x - cos12x - cos4x} 1/2{cos4x - cos12x} 1/2{sin4x/4 -sin12x/12}
  • 2 answers

Sumit Jangra 6 years, 2 months ago

Take 1+x^3= y -------(1) Then differentiate with respect to x,hence find dy/dx Then, break x^5 into x^3 and x^2 Now put value of x^3 from eq 1 And solve with respect to y.

Sumit Jangra 6 years, 2 months ago

Solved this
  • 1 answers

Moni Sheoran@2#3% 6 years, 2 months ago

from cbse champion (mtg) book last 10 sample papers...
  • 2 answers

Pooja Bhakar 6 years, 2 months ago

To get 95 percent in mathematics or other subjects you must concentrate on study

Moni Sheoran@2#3% 6 years, 2 months ago

practice & concentration....
  • 5 answers

Moni Sheoran@2#3% 6 years, 2 months ago

1

Dolly ?️ 6 years, 2 months ago

1

Sivabrat Mohanty Sir 6 years, 2 months ago

Using limit...get e=2.718

Garvit Chaurasiya 6 years, 3 months ago

Sorry it will be 1

Garvit Chaurasiya 6 years, 3 months ago

Not define
  • 2 answers

Laxmi Kant Singh 6 years, 2 months ago

1/2(2/5 log (2+tanx/2 upon 2-tanx/2))

Pooja Bhakar 6 years, 3 months ago

Firstly we put cosx=cos^2 x/2-sin^2 x/2 and sinx = 2sinx/2cosx/2 then dividing numerator and denominator by cos^2 x/2 then we get the result in form of sec and tan after that put tanx/2=t so that 1/2sec^2 x/2dx=dt i.e. sec^2 x/2 = 2dt then solve it by partially method . I hope this answer will help you...
  • 5 answers

Vikas Semwal 6 years, 3 months ago

No in recent time I also think so, but for better result do RD Sharma, it help to practice one type of question for many times

😜Arnav Arya🙃 6 years, 3 months ago

No any other book is not required for integration

Pankaj Kumar 6 years, 3 months ago

Yeah it is done to be with ncert but for practice we need a no. Of questions so i refer for an extra book too

Sandeep Tyagi Sandeep Tyagi 6 years, 3 months ago

Practice ke liye rs karo

Prashant Singh 6 years, 3 months ago

Haa phale aache se ncert kar lo ji uske baad rsa ka question bana lena lekin phale ncert ko karo
  • 4 answers

Muskan Jangra 6 years, 2 months ago

I have a short trick to learn this. If you want please reply

Muskan Jangra 6 years, 2 months ago

Please sin cos tan ki value yaad kar lo very imp.

Sandeep Tyagi Sandeep Tyagi 6 years, 3 months ago

Root 3 upon 2

Neha Choudhary 6 years, 3 months ago

Root 3 divided by 2
  • 5 answers

Muskan Jangra 6 years, 2 months ago

No it is important

Moni Sheoran@2#3% 6 years, 2 months ago

no

Div¥@N$Hi P@M@® 6 years, 3 months ago

Noo

Sandeep Tyagi Sandeep Tyagi 6 years, 3 months ago

No

Neha Choudhary 6 years, 3 months ago

No
  • 3 answers

Avinash Parmar 6 years, 2 months ago

Sin inverse is equal to theta

Sangam Martand 6 years, 2 months ago

Let sin inverse is equal to z

Neha Choudhary 6 years, 3 months ago

Let sin inverse x be y than solve
  • 4 answers

Avinash Parmar 6 years, 2 months ago

-log |cosx| +C

Moni Sheoran@2#3% 6 years, 2 months ago

log lsecxl + c

Surya Kant 6 years, 3 months ago

Integrate tanx = log| secx | +C

Kumar Vishal Behera 6 years, 3 months ago

Take sinx/cosx.dx Take cosx=t and then -sinx.dx=dt So it will be -dt/t. Integrate it as i can't write whole answer here. If Any doubts ask.
  • 4 answers

Moni Sheoran@2#3% 6 years, 2 months ago

also take help from elements...

Khuskaran Sidhu 6 years, 3 months ago

Ofcourse

Shruti Kamal 6 years, 3 months ago

And for maths do not depend in ncert ,solve r.d sharma and r.s aggarwal

Shruti Kamal 6 years, 3 months ago

Ya but also go with previous question papers and read ncert throughly
  • 1 answers

Pooja Bhakar 6 years, 3 months ago

Put x=tan¢ .......(1) Y=sin^-1(2tan¢/1+tan^2¢) sin^-1(sin2¢) 2¢ ......(2) from eq.(1) ¢=tan^-1 Put this value in eq. (2) 2tan^-1......Ans
  • 0 answers

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