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  • 1 answers
Of course dear. Many questions have been asked from misc. exercises. They are the most important part of NCERT
  • 2 answers

Khuskaran Sidhu 6 years ago

Yah‼ in many of questions, there r 2 same options in online tests & the option we choose, usually go wrong

Prachi Kumari 6 years ago

*4/5 is given two times *so both should be true
  • 1 answers

Hidden Black 6 years ago

Substitute since as t and then solve using partial fraction
  • 1 answers

Divya .. 6 years ago

Answer will be zero
  • 1 answers

David Billa 6 years ago

x+tanx dy/dx= 1+sec^2x d^2y/dx^2 = 0+2sec^2xtanx cos^2x×2sec^2xtanx-2x+2tanx+2x =0
  • 1 answers

Sumera Sumera 6 years ago

Find dy/dx and then make y in terms of y/x, if it is possible then it is clearly homogeneous eq.n or make degree of numerator same as denominator
  • 1 answers

Khuskaran Sidhu 6 years ago

There is no need
  • 2 answers

Unnati Mishra 6 years ago

How??

Yuvraj Singh 6 years ago

tanx - secx + C
  • 1 answers
dx/dO=secO.tanO dy/dO=sec^2O dy/dx =dy.dO/dO.dx =sec^2O/secO.tanO =secO/tanO =(1/cosO).(cosO/sinO) =1/sinO =cosecO
  • 1 answers

Gaurav Seth 6 years ago

Let the unit vector is a in XY-plane

So a = xi + yj .............1

where unit vector in the direction of x-axis is i and in y-axis is j

Now given that a makes an angle of 30 with x-axis

So a.i = |a|*|i|*cos 30

=> a.i = 1*1*√3/2   (since a and i are unit vector so |a| = 1, |i| = 1 )

=> a.i = √3/2

=> (xi + yj + 0k).(1i + 0j + 0k) = √3/2

=> x = √3/2                           (i.i = j.j = k.k = 1)

Again since a makes an angle of 30 with x-axis then a makes an angle of 60 with y-axis

So a.j = |a|*|j|*cos60

=>(xi + yj + 0k).(0i + 1j + 0k) = 1/2

=> y = 1/2

Now put value of x and y in equation 1, we get

a = (√3/2)i + (1/2)j

So unit vector is (√3/2)i + (1/2)j

  • 2 answers

Prakhar Mishra 6 years ago

11

Prakhar Mishra 6 years ago

10
  • 1 answers

Dolly ?️ 6 years ago

Log5. 5^sinx .cosx

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