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  • 1 answers

Gaurav Seth 4 years, 10 months ago

Magnetic separation: This method is based on the magnetic and non-magnetic properties of the ore components

  1. Magnetic Separation: - This method is based on differences in magnetic properties of the ore components. If either the ore or the gangue (one of these two) is capable of being attracted by a magnetic field, then such separations are carried out (e.g., in case of iron ores). The ground ore is carried on a conveyer belt which passes over a magnetic roller.
  • 4 answers

Devil ? 4 years, 10 months ago

Due to +I Effect ...

All Rounder Mkjha 4 years, 10 months ago

Also The methyl group has electron donating effect that increase the electron density over the nitrogen. Aniline is an aromatic amine and it has a benzene ring which is electron withdrawing in nature.

Vyakhya Gupta 4 years, 10 months ago

Also The methyl group has electron donating effect that increase the electron density over the nitrogen atom makes it more basic than aniline

Yogita Ingle 4 years, 10 months ago

Aniline is an aromatic amine and it has a benzene ring which is electron withdrawing in nature. Because of this, the lone pair of electrons on nitrogen is not readily available for donation, as it is involved in the resonance. whereas methylamine is an aliphatic amine and the methyl group is electron donating in nature so the lone pair of nitrogen in methylamine is easily available for donation because  there is no resonance in methyl amine.Thus methyl amine is more basic than aniline.

  • 2 answers

Abhijeet Pratap Singh 4 years, 10 months ago

Type of organic compounds in which a carbon atom shares a double bond with an oxygen atom. Secondary suffix- 'al' Example :- methanal Comman name:-(formaldehyde) ✍️????

Yogita Ingle 4 years, 10 months ago

Aldehydes: Aldehydes are the organic compounds in which carbonyl group is attached to one hydrogen atom and one alkyl or aryl group.

  • 1 answers

Yogita Ingle 4 years, 10 months ago

i. Macromolecular sol: They are molecules of large size having high molecular masses. Due to long chain, the vander waal's forces are stronger, e.g., rubber, nylon etc. 

ii. Peptization is the process responsible for the formation of stable dispersion of colloidal particles in dispersion medium. In other words, it may be defined as a process of converting a precipitate into colloidal sol by shaking it with dispersion medium in the presence of small amount of electrolyte.
iii.  Emulsion is a fine dispersion of minute droplets of one liquid in another in which it is not soluble or miscible, e.g. milk.

  • 2 answers

Abhijeet Pratap Singh 4 years, 10 months ago

What do you mean of your's question? Kirti Please again write and tag it.✍️?

Jagdish Suthar 4 years, 10 months ago

We know that an acid is strong when it lose h+ and the remaining specie is stable then when acetic acid lose h+ then the remaining negative specie is unstable by ch3 because ch3 has +I effect it donates electron and unstablised the negative specie but formic acid have no +I group
  • 3 answers

Sanjana Dua?????❣️ 4 years, 10 months ago

Please,tell which telegram ?group?

Devil ? 4 years, 10 months ago

Which telegram group ??

Vivek Chaurasia 4 years, 10 months ago

Join telegram app
  • 2 answers

Srashtika Barode 4 years, 10 months ago

Thank you...

Nishant Pandey 4 years, 10 months ago

Excessive intake of fluoride during enamel development can lead to enamel fluorosis, a condition of the dental hard tissues in which the enamel covering of the teeth fails to crystallize properly, leading to defects that range from barely discernable markings to brown stains and surface pitting.
  • 1 answers

Meghna Thapar 4 years, 10 months ago

The reaction of aldehydes and ketones with ammonia or 1º-amines forms imine derivatives, also known as Schiff bases (compounds having a C=N function). Water is eliminated in the reaction, which is acid-catalyzed and reversible in the same sense as acetal formation. Two of the more important derivatives of ammonia are hydrazine and hydroxylamine. In strongly acidic medium ammonia derivatives being basic will react with acids and will not react with carbonyl compound. In basic medium, OH will attack carbonyl group. Hence pH of a reaction should be carefully controlled.

  • 1 answers

Yogita Ingle 4 years, 10 months ago

Iodoform test is used to check the presence of carbonyl compounds with the structure R-CO-CH3 or alcohols with the structure R-CH(OH)-CH3 in a given unknown substance.

When Iodine and sodium hydroxide are added to a compound that contains either a methyl ketone or a secondary alcohol with a methyl group in the alpha position, a pale yellow precipitate of iodoform or triiodomethane is formed. It can be used to identify aldehydes or ketones. If an aldehyde gives a positive iodoform test, then it must be acetaldehyde since it is the only aldehyde with a CH3C=O group. Given below are a few example reactions for positive iodoform tests.

  • 2 answers

Sneha Kakadiya 4 years, 10 months ago

The Hofmann Elimination is an elimination reaction of alkylammonium salts that forms C-C double bonds [pi bonds]. ... In contrast with most elimination reactions that yield alkenes, which follow the Zaitsev (Saytzeff) rule, the Hofmann elimination tends to provide the less substituted alkene

Yogita Ingle 4 years, 10 months ago

Dehydrohalogenation of secondary- and tertiary-alkyl halides involves removal of the ?-hydrogen from the carbon that has the smallest number of hydrogens. This is Saytzeff rule.

According to this rule, major product is the most substituted alkene i.e., major product is obtained by elimination of H from that ?-carbon which has the least number of hydrogen. Product of the reaction in this case is known as Saytzeff product.         

(ii) Hofmann rule : According to this rule, major product is always least substituted alkene i.e., major product is formed from ?-carbon which has maximum number of hydrogen. Product of the reaction in this case is known as Hofmann product.            

Dehydrohalogenation of secondary- and tertiary-alkyl halides involves removal of the ?-hydrogen from the carbon that has the smallest number of hydrogens. This is satzeff rule.

  • 1 answers

Vishal Raj 4 years, 10 months ago

Benzene
  • 1 answers

Sanjana Dua?????❣️ 4 years, 10 months ago

Propionitrile + hydroxyl ion
  • 1 answers

Yogita Ingle 4 years, 10 months ago

SN1 SN2
The rate of reaction is unimolecular. The rate of reaction is bimolecular
It is a two-step mechanism It is only a one-step mechanism
Carbocation is formed as an intermediate part of the reaction. No carbocation is formed during the reaction.
There is no partial bond formed with the carbon during this reaction. Carbon forms a partial bond with the nucleophile and the leaving group.
There are many steps in this reaction which start with the removal of the group while attacking the nucleophile. The process takes place in only one cycle, with a single intermediate stage.
  • 3 answers

Yogita Ingle 4 years, 10 months ago

Schottky defect is a type of point defect or imperfection in solids which is caused by a vacant position that is generated in a crystal lattice due to the atoms or ions moving out from the interior to the surface of the crystal.

A Frenkel defect is another form of a point defect which is created when an atom or cation leaves its original place in the lattice structure to create a vacancy while occupying another interstitial position within the solid crystal.

Yogita Ingle 4 years, 10 months ago

In Schottky defect the difference in size between cation and anion is small. Frenkel defect contains ionic crystals where the anion is larger than the cation. Both anion and cation leave the solid crystal. Usually the smaller ion cation leaves its original lattice structure. Atoms permanently leave the crystal.

Sahil Kumar 4 years, 10 months ago

Definition is already printed in the Ncert book, rather our defintions is comparatively same as ncert textbook, but the result of meaning come out same!
  • 1 answers

Yogita Ingle 4 years, 10 months ago

Aqueous NaOH or aqueous KOH.

  • 1 answers

Yogita Ingle 4 years, 10 months ago

According to the valence bond theory, Electrons in a molecule occupy atomic orbitals rather than molecular orbitals. The atomic orbitals overlap on the bond formation and the larger the overlap the stronger the bond. The metal bonding is essentially covalent in origin and metallic structure involves resonance of electron-pair bonds between each atom and its neighbors.

  • 4 answers

Baliyan ? 4 years, 10 months ago

Ha ? smj gi.... thanku ?

Abhijeet Pratap Singh 4 years, 10 months ago

Isme sodium aur mg most affordable element hai aur easily available hote hai is wjh se ye agent ka work krte hai. Shmjhi mrs ki ab bhi ni.thoda cool hoke thinking kro aa jayega smjh me . Accha gd night ???????

Baliyan ? 4 years, 10 months ago

Yo tho thk h....prrr ish question m in agent m s kon sa h ..ar kyu? Yu batana

Abhijeet Pratap Singh 4 years, 10 months ago

Salt as well as H2s Use as an intermediate process to produce a solution. Yrr kuch confusion hoga to ask me on any time ,"understand"???
  • 5 answers

Deepak Baranwal 4 years, 10 months ago

Yes, 0.2 is the correct answer.

Sourabh Sharma 4 years, 10 months ago

0.2 is the correct answer

Tanya ?? 4 years, 10 months ago

Haa...agar 1 ko 5 se divide krege to 0.2 aaega ...apka answer bhi thik h?

Hariom Pandit 4 years, 10 months ago

Finally mera ans.. 1 by 5 aa rha ha Mole fraction nikalna tha

Tanya ?? 4 years, 10 months ago

Mera to 0.2 aaya h...I think ye thik h ....so,the answer is 0.2g/mol.
  • 1 answers

Arjit Kumar 4 years, 10 months ago

Movement of dispersion medium under influence of electric field
  • 2 answers

Rounik Roy 4 years, 10 months ago

Take help from books ???

Shashikant ? 4 years, 10 months ago

Easy qns..solve by yourself
  • 2 answers

Shashikant ? 4 years, 10 months ago

Read Ncert

Meghna Thapar 4 years, 10 months ago

Calcium chloride is strongly hygroscopic (absorbs water from its surroundings), so it removes moisture from the air, making it dryer. This results in water in the substance to be dried to evaporate into the drier air, and this cycle repeats until the system reaches an equilibrium. Anhydrous calcium chloride is an inorganic salt that easily forms hydrates which promotes its use for removing water from any organic solution.

  • 1 answers

Yogita Ingle 4 years, 10 months ago

Sulphur sol and gold sol are Lyophobic sols and are unstable and are build to colloidal size from small particles by the Condensation method by Chemical reactions.

 Oxidation sulphur sol is prepared by passing H2S into SO2

  1.  H2S + SO2 → S (sol) + H2

  2. Reduction of AuCl3 with formaldehyde gives gold sol.

    AuCl3+ HCHO + 3H2O → Au (sol) + 3HCOOH + 6HCl
  • 2 answers

Shubham Shankar 4 years, 10 months ago

Thanks for sharing

Aaditya Kushwah 4 years, 10 months ago

CH2(OH)C(Br)=C(CH3)CH3 PICRIC ACID IS. 2,4,6-tri nitro phenol
  • 2 answers

Yogita Ingle 4 years, 10 months ago

Transition elements (also known as transition metals) are elements that have partially filled d orbitals. IUPAC defines transition elements as an element having a d subshell that is partially filled with electrons, or an element that has the ability to form stable cations with an incompletely filled d orbital.

In general, any element which corresponds to the d-block of the modern periodic table (which consists of groups 3-12) is considered to be a transition element. Even the f-block elements comprising the lanthanides and the actinides can be considered as transition metals.

However, since the f-block elements have incompletely filled f-orbitals, they are often referred to as inner transition elements or inner transition metals. An illustration detailing the position of transition metals on the periodic table along with their general electronic configurations is provided below.

Mohit Singh 4 years, 10 months ago

Home work
  • 1 answers

Meghna Thapar 4 years, 10 months ago

A block of the periodic table is a set of elements unified by the orbitals their valence electrons or vacancies lie in. The term appears to have been first used by Charles Janet. Each block is named after its characteristic orbital: s-block, p-block, d-block, and f-block.

The block names (s, p, d, and f) are derived from the spectroscopic notation for the value of an electron's azimuthal quantum number: shape (0), principal (1), diffuse (2), or fundamental (3). Succeeding notations proceed in alphabetical order, as g, h, etc.

  • 1 answers

Meghna Thapar 4 years, 10 months ago

Transition metals share many similar properties including: They can form many compounds with different oxidation states. They can form compounds with different colors. They are metals and conduct electricity. Properties of transition elements include:

  • have large charge/radius ratio;
  • are hard and have high densities;
  • have high melting and boiling points;
  • form compounds which are often paramagnetic;
  • show variable oxidation states;
  • form coloured ions and compounds;
  • form compounds with profound catalytic activity;

Subsequently, question is, why do all metals have similar properties? The reason that that elements in the same 'group' have similar chemical properties is because they have the same number of valence electrons. Iron when reacting in chemical reactions loses electrons from its 4s orbital instead of its d orbital.

  • 1 answers

Yogita Ingle 4 years, 10 months ago

As discussed earlier, the elements zinc, cadmium, and mercury are not considered transition elements since their electronic configurations are different from other transition metals. However, the rest of the d-block elements are somewhat similar in properties and this similarity can be observed along each specific row of the periodic table. These properties of the transition elements are listed below.

  • These elements form coloured compounds and ions. This colour is explained by the d-d transition of electrons.
  • There is a relatively low gap in energy between the possible oxidation states of these elements. The transition elements, therefore, exhibit many oxidation states.
  • Many paramagnetic compounds are formed by these elements, because of the unpaired electrons in the d orbital.
  • A large variety of ligands can bind themselves to these elements. Due to this, a wide variety of stable complexes are formed by transition elements.
  • These elements have a large ratio of charge to the radius.
  • Transition metals tend to be hard and they have relatively high densities when compared to other elements.
  • The boiling points and the melting points of these elements are high, due to the participation of the delocalized d electrons in metallic bonding.
  • This metallic bonding of the delocalized d electrons also causes the transition elements to be good conductors of electricity.
  • 1 answers

Yogita Ingle 4 years, 10 months ago

Zn, Cd, Hg are not regarded as transition element Because they have the completely filled d-sub-shell with outer electronic configuration (n-1)d10ns2

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