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  • 3 answers

Sparsh Anand 7 years, 11 months ago

It's phosphodiester bond

Vineit Kumar Gupta 7 years, 11 months ago

Sorry its peptide bond

Vineit Kumar Gupta 7 years, 11 months ago

Both DNA and RNA are nucleic acids a glycosidic bond is present between them
  • 3 answers

Muskaan Sharma 7 years, 11 months ago

Histamine is a chemical responsible for inflammation in body.

Soumya Sakshi 7 years, 11 months ago

Histamine is a chemical which is responsible for allergic response towards pollen, associated with nasal congestion at the time of cold and is also a potent vasodilator

Sparsh Anand 7 years, 11 months ago

Antibody released by body due to any allergy
  • 7 answers

Shivanshu Yadav 7 years, 11 months ago

Muskan apka kb h practical hm

Muskan Bhardwaj 7 years, 11 months ago

Shivanshu please tell Ur viva questions

Shivanshu Yadav 7 years, 11 months ago

Kk I give your question in free time hmm

Sweety Yadav 7 years, 11 months ago

Maybe upto this 29.. Not sure

Shivanshu Yadav 7 years, 11 months ago

Plz give me your date of practical and i give your important questions for practical kk

Shivanshu Yadav 7 years, 11 months ago

Some ph value put up

Sweety Yadav 7 years, 11 months ago

School time Guys
  • 11 answers

Aastha Singh 7 years, 11 months ago

And pahele se best of luck ? ?

Aastha Singh 7 years, 11 months ago

Ok please tell me about after done your viva ok

Sweety Yadav 7 years, 11 months ago

Kl physics ka h

Aastha Singh 7 years, 11 months ago

Mera 27 ko h phsics ka

Aastha Singh 7 years, 11 months ago

Kisi subject ka

Aastha Singh 7 years, 11 months ago

Anyways tmhara practical hua

Sweety Yadav 7 years, 11 months ago

Apka Kon s subject ka h

Aastha Singh 7 years, 11 months ago

Ok and thanks

Sweety Yadav 7 years, 11 months ago

Maybe he became offline.. Uska messaging time dekh k lgta h wo 11:00 se 12:00 k beech m aayega

Aastha Singh 7 years, 11 months ago

Ya sister dekha h pr kuch aur question poochne h Vineet bhai se

Sweety Yadav 7 years, 11 months ago

Kl usne btaya tha
  • 1 answers

Sweety Yadav 7 years, 11 months ago

See more chatting
  • 2 answers

Himanshu Bhandari 7 years, 11 months ago

Learn the chapter in which you are suitable and know each and every point of it. And viva contains only 4 marks the other are in your school teaches hands.

Shivanshu Yadav 7 years, 11 months ago

Which school?
  • 1 answers

Sia ? 4 years, 6 months ago

Weak field ligands induce less splitting of the crystal fields. They form complexes with high spins.

Examples: chloride ions, fluoride ions etc.

Strong field ligands result in greater splitting of the crystal field. They form complexes with low spins.

Examples: Co and cyanide ion.

  • 2 answers

Muskan Bhardwaj 7 years, 11 months ago

By making notes

Sweety Yadav 7 years, 11 months ago

By more and more practice.. Specially name rxn
  • 2 answers

Arushi Chaudhary 7 years, 11 months ago

So..the above answer is absolutely correct...but mainly..cuso4 is added to give the colour to it and pyridine is used to give foul smelling to the denatured alcohol..!!

Vanshika Lamba 7 years, 11 months ago

The alcohol that is made unfit for drinking purpose by adding copper sulphate and pyridine is called denatured alcohol
  • 0 answers
  • 2 answers

Ravi Singh 7 years, 11 months ago

Vaporization is the convertion of molecules into gas at every step of reaction And the process in which at certain temperature the energetic molecules have tendency to escape from the surface of liquid is called evaporation

Ishika Tanwani 7 years, 11 months ago

Eva.is at particular temp.and vap.is at every temp.
  • 0 answers
  • 1 answers

Abhishek Chaurasia 7 years, 11 months ago

First increase with inc in conc. then decreasing with more increase of conc. due to inc in ion ion interaction
  • 1 answers

Singh Singh 7 years, 11 months ago

Refer pardeep part2 appendix
  • 1 answers

Navjot Kaur 7 years, 11 months ago

Yes
  • 0 answers
  • 2 answers

Arushi Chaudhary 7 years, 11 months ago

If u see the structure of pcl5..which is trigonal bipyramidal.. U will see that three cl are present at equitorial positions and two cl atoms r present at axail positions and the bond length of axial bonds r longer bcz...to avoid bond pair bond pair repulsions that's why.... Oll Bonds in pcl5 r not equivalent...! I hope..u will get my point.. !

Ishika Tanwani 7 years, 11 months ago

Coz it is sp3d in which acusl nd equ.bond lenths r diff.
  • 1 answers

Ishika Tanwani 7 years, 11 months ago

An alkane with 1 Cl
  • 3 answers

Aastha Singh 7 years, 11 months ago

Okk thanks and best of luck??

Jay Maurya 7 years, 11 months ago

Tommorow 23 jan

Aastha Singh 7 years, 11 months ago

Bhai kish date ko h aap ka practical
  • 2 answers

Asim Khan 7 years, 11 months ago

I believe that atleast one month before the board exams, we are expected to cover all the main concepts and theory part. And now the question arises that what to do in the last remaining month? I would suggest you to give your last one month only and only on solving the previous year board papers and sample papers. It will help you in better understanding all the main concepts and will give you the idea about the most important part of the topic which is being asked again and again in last ten or fifteen years,etc. Moreover it will boost your speed and accuracy which is the most important tool for a topper. Thank you! Hope it helps you... Best wishes

Prajjwal Tripathi 7 years, 11 months ago

Study the major scoring part firstly...unless leaving them
  • 2 answers

Asim Khan 7 years, 11 months ago

The second ionization enthalpy for Cr and Cu are quite higher as the d5 and d10 configuration of M+ ions gets disrupted whereas, the value for Zn is correspondingly low as the ionization consists of the removal of an electron which allows the production of the stable d10 configuration. The trend in third ionization enthalpy doesn’t involve 4s orbitals and thus there is a greater difficulty for the removal of an electron from Mn2+ (d5) and Zn2+ (d10) ions. Thus, we see a marked difference between third ionization enthalpies of iron (26) and manganese (25).

Asim Khan 7 years, 11 months ago

Ionisation Enthalpy: Ionisation enthalpy is the energy required to remove the most loosely bound electron from the isolated gaseous atoms to produce a cation. Those of transition elements tend to increase from left to right in the periodic table as there is an increase in nuclear charge which accompanies the filling of the inner d orbitals. However, there are some exceptions, for example, Titanium (22) has first ionization enthalpy of 656kJ/mole whereas vanadium (23) has first ionization enthalpy of 650kJ/mole. Enthalpy Periodic table These irregular trends in the first ionization enthalpy of transition metals can be explained by considering the fact that the removal of one electron alters the relative energies of 4s and 3d orbitals. Hence, in general, we can conclude that the unipositive ions furnish dn configuration with no 4s electrons. Thus, there is a reorganization energy accompanying ionization with some gains in exchange energy as the number of electrons increases from the transference of s electrons into d orbitals. Let us analyze the general trend in the first row: First ionization enthalpies of transition elements show general trend of increase from left to right. However, in case of chromium (24), the change in the value of first ionization enthalpy is lower as there is no change in d orbital configuration whereas, zinc (30) shows a higher value as it represents an ionization from 4s level
  • 4 answers

Ankit Maurya 7 years, 11 months ago

But molecular mass of (CH3)3N is much higher than that of CH3NH2

Vikram Choudhary 7 years, 11 months ago

CH3NH2 H-bonding in water

Varun Narang 7 years, 11 months ago

CH3NH2 will have the higher boiling point as it forms hydrogen bond with water molecules whereas hydrogen bonds are absent in case of (CH3)3N as there is no hydrogen attached with nitrogen which can form the bonds.

Nikita Pandro 7 years, 11 months ago

CH3NH2 has higher boiling point than (CH3)3N because in 1degree amine 2 H are available for H bonding
  • 2 answers

Asim Khan 7 years, 11 months ago

The correct order of increasing basic nature for the bases NH3, CH3NH2 and (CH3)2NH is CH3NH2 < (CH3)2NH < NH3 CH3NH2 < NH3 < (CH3)2NH (CH3)2NH < NH3 < CH3NH2 NH3 < CH3NH2 < (CH3)2NH Answer Except the amines containing tertiary butyl group, all lower aliphatic amines are stronger bases than ammonia because of +I (inductive) effect. The alkyl groups, which are electron releasing groups, increase the electron density around the nitrogen thereby, increasing the availability of the lone pair of electrons to proton or Lewis acids and making the amine more basic. The observed order in the case of lower members is found to be as secondary > primary > tertiary. This anomalous behavior of tertiary amines is due to steric factors i.e. crowding of alkyl groups cover nitrogen atom from all sides and thus makes it unable for protonation. Thus the relative strength is in order (CH3)2NH > CH3NH2 > NH3.

Nikita Pandro 7 years, 11 months ago

3,2,1,NH3
  • 1 answers

Asim Khan 7 years, 11 months ago

It will be 2-Chloropropanamine because the third carbon will become the second carbon after the removal of the carbon of the amide group. Structure: CH3-CH(Cl)-CH2-NH2
  • 1 answers

Kajal Bhardwaj 7 years, 11 months ago

Due to ability to change oxidation state
  • 4 answers

Vikram Choudhary 7 years, 11 months ago

I can tell somehow Schiff's Base Brown ring formula Felling solution Iodoform

Sweety Yadav 7 years, 11 months ago

?????

Vineit Kumar Gupta 7 years, 11 months ago

Hahaha i will for sure tell you sweety yadav

Sweety Yadav 7 years, 11 months ago

I'm having practical on Tuesday.. Then u will tell me the question asked in u r viva
  • 1 answers

Rida Khan 7 years, 11 months ago

Movement of charge from one pole to another.

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