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  • 2 answers

Kuldeep Nagar 4 years, 5 months ago

Practice is must for this

Dhivyasree Mohan 4 years, 5 months ago

Practice daily 10-15 equations...u will get thorough in organic chemistry
  • 2 answers

Shivani Thakur 4 years, 5 months ago

It give large value for a small amount of mass.

Hey Kriti 4 years, 5 months ago

because it contains concentration in terms of molarity
  • 2 answers

Devil ? 4 years, 5 months ago

X2Y3

Hey Kriti 4 years, 5 months ago

No. Of atoms present in element Y = a No. Of octahedral voids = a No. Of atoms present in X = a*⅔ Ratio = x:y = a*⅔*3:a*3 = 2:3 The formula of the compound = x2y3.
  • 1 answers

Sia ? 4 years, 5 months ago

Chemical formulas tell you how many atoms of each element are in a compound, and empirical formulas tell you the simplest or most reduced ratio of elements in a compound. If a compound's chemical formula cannot be reduced any more, then the empirical formula is the same as the chemical formula.
  • 4 answers

Mr. Badmash 4 years, 5 months ago

You can prepare one chapter by own. And practical knowledge is must . Because they first ask from practical then from theory if you can't answer properly

Dhruv .. 4 years, 5 months ago

Just offer something fantasy to your external?

Lakshya Sharma 4 years, 5 months ago

Simple bro do 1 chapter . They will ask from that chapter...

Kavya S 4 years, 5 months ago

In my scl for practicals questions are from, 1.thorough with the experiment 2.requirements needed 3.reason for the color and observations,etc U should be thorough in each experiment in and out
  • 2 answers

Mr. Badmash 4 years, 5 months ago

What you want to ask????

Sia ? 4 years, 5 months ago

Please ask question with complete information.

  • 2 answers

Kavya S 4 years, 5 months ago

Thank u kanishca?

Kanishca Ar 4 years, 5 months ago

Day 1..practice all. The naming reaxn and bookback exercise... Day 2 go through all the numericals from solid state electrochemistry chemical kinetics and solutions.. Its better if u start with bookback Day 3..focus on conceptual and application based qn with d and fitness block elements and coordination compounds.. Learn to name.. Compound U have to spent more tym on p. Block.. Day 4 repeat..(I mean.. Concentrate everything) Day 5..repeat... More Practise u do.. The more u become comfortable with your chapters V have our xam on 18th and s.. U could achieve more marks.. Practise daily man I hope this helps...
  • 4 answers

Har Har Mahadev 🙏 4 years, 5 months ago

I think that exam will not postponed.

Hey Kriti 4 years, 5 months ago

I want the exam should be online ??

Kavya S 4 years, 5 months ago

I want the exam to be postponed

Jass . 4 years, 5 months ago

I don't think so that exam will be postponed.
  • 2 answers

Sia ? 4 years, 5 months ago

The well-defined short-range order is a consequence of the chemical bonding between atoms, which is responsible for holding the solid together.

Shraddha Verma 4 years, 4 months ago

As the particles are notvarranged in a definite pattern for a long time
  • 2 answers

Gautam Kumar Gautam Kumar 4 years, 5 months ago

C-Cch3=C-C-Cch3.ch3-C

P....... ........ 4 years, 5 months ago

In example (1) the longest chain consists of six carbons, so the root name of this compound will be hexene. Three methyl substituents (colored red) are present. Numbering the six-carbon chain begins at the end nearest the double bond (the left end), so the methyl groups are located on carbons 2 & 5. The IUPAC name is therefore: 2,5,5-trimethyl-2-hexene.
  • 2 answers

Shraddha Verma 4 years, 4 months ago

It is the smallest unit of a crystal which when repeated gives the whole crystal

Deepsan Basnett 4 years, 5 months ago

Three dimensional arrangement of points (atoms, molecules or ion ) in space is called lattice.
  • 1 answers

Sia ? 4 years, 5 months ago

The molar conductivity is defined as the conducting power of all the ions that are formed by dissolving a mole of electrolyte in a solution.
Molar conductance is dependent on the concentration of the electrolyte. When the solution is dilute the number of ions available per unit volume reduces, resulting in the reduction of the conductivity.

  • The molar conductivity of both weak and strong electrolytes increases with a decrease in concentration or dilution.
  • The molar conductivity is the conductivity offered by one mole of ions.
  • Even after dilution, we are still considering the same unit mole of ions.
  • But however, the increased dilution results in the dissociation of more electrolytes into ions and effectively increasing the number of active ions in the solution.
  • These active ions impart more conductivity.
  • 1 answers

Sia ? 4 years, 5 months ago

The formula of an oxo-anion of manganese (Mn) in which it shows the oxidation state equal to its group number is {tex}MnO_4^{-}{/tex}. Here, oxidation state of Mn is +7 which is same as is its group number.

  • 5 answers

I A 4 years, 5 months ago

Yes

Paridarshan Sahoo 4 years, 5 months ago

101% out of 100%

Abhi Yaduvanshi 4 years, 5 months ago

Yes bro?????

Sonam Dwivedi 4 years, 5 months ago

Ofcourse yes ☺

Vicky D 4 years, 5 months ago

Yes,if you read line by line and with all example and ouestion ?. All the best ?
  • 1 answers

Technical Mind 4 years, 5 months ago

Specific log values are given in exams. Values used in NCERT can be memorised for better results. Needless to mention, they will be given in CBSE exams
  • 3 answers

Kanishca Ar 4 years, 5 months ago

V use chloro when chlorine is present as a counter ion.. Outside the bracket.. In most cases v won't get this.(potassium mostly) . Chlorido when it is a ligand

Mr. Badmash 4 years, 5 months ago

We use chloro in organic chemistry and chlorido in coordination compound

Rock ×Himanshu 4 years, 5 months ago

Hamara mann ??
  • 1 answers

Sia ? 4 years, 5 months ago

There is sharp increase in the number of ions in the solution. Hence, the molar conductivity of a weak electrolyte rises steeply at low concentration. (ii) Strong electrolytes: The molar conductivity of a strong electrolyte decreases slightly with the increase in concentration.

  • 3 answers

Abhi Yaduvanshi 4 years, 5 months ago

Liquids and gases are fluids because they have tendency to flow ,i.e, their molecules can flow from one place to another easily

Royal Thakur ? 4 years, 5 months ago

Pk bro ....?

Rajandeep Kaur 4 years, 5 months ago

Liquids and gases are categorised as fluids because of their ability to flow. Fluidity in these states are due to the fact that molecules are free to move.
  • 1 answers

Aniket Singh 4 years, 5 months ago

1. Nittogen is diatomic while other group members are tetratomic. 2. N2 shows least catenation properties but other members show catenation property. 3. N2 have maximum covalency '4'
  • 2 answers

Aniket Singh 4 years, 5 months ago

By sodium nitroprusside test

P....... ........ 4 years, 5 months ago

Presence of ketonic group is confirmed. Dissolve a small quantity of sodium nitroprusside in about 1 ml of distilled water in a clean test tube and then add a small quantity of the given compound. Shake the test tube well and add sodium hydroxide solution dropwise. Red colouration.
  • 5 answers

Kavya S 4 years, 5 months ago

Use pradeep's chemistry

Prashant Sher Yadavanshi 4 years, 5 months ago

Complete all back exercises and examples of ncert book. Make notes

Ajay Rao 4 years, 5 months ago

By studying ??

Jyoti Dhatterwal 4 years, 5 months ago

Attend classes regularly, make notes, study chemistry with full energy and heartily.

Priyanshu Kumar Sahu 4 years, 5 months ago

Understand 100% chemistry You don't have to gain 90% in chemistry
  • 0 answers
  • 1 answers

P....... ........ 4 years, 5 months ago

Depending upon the dissolution of the solute in the solvent, solutions can be categorized into supersaturated solution, unsaturated and saturated solutions.
  • 5 answers

Bobby Nishad 4 years, 5 months ago

ABC

Satyam Jaiswal 4 years, 5 months ago

According to me Nootan's publication books are best

Sony Chauhan 4 years, 5 months ago

Arihant is best

Sabhyata Pandey 4 years, 5 months ago

Arihant ?

Komal Yogi 4 years, 5 months ago

I think pradeep would be a good book
  • 3 answers
I can't send you photo otherwise i explain you in detail
Because in strong ligand pairing of electron gets start and one unpaired electron is left in Co2^+ and hence it loose this electron and get easily oxidised to form Co3^+

Abhi Yaduvanshi 4 years, 5 months ago

Give reason ?

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