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  • 1 answers

Sayeda Iram Ateeq 6 years, 7 months ago

The nature of the solid will be conductor.
  • 1 answers

Gaurav Seth 6 years, 7 months ago

Raoult’s law as special case of Henry’s law

  • At a given temperature liquids vaporize. At equilibrium the pressure exertedby the vapour of the liquid over the liquidphase is referred to as vapour pressure.
  • According to Raoult’s law, vapour pressure of a volatile component in a given solution ca be defined by pi = pi 0 xi
  • In an answer of a gas in a fluid one of the segments is volatile to the point that it exists as a gas and solvency is given by Henry's law which expresses that KH x
  • Comparing both the equations we get that partial pressure of the volatile component or gas is directly proportional to its mole fraction in solution. Proportionality constant KH differs from p10
  • Therefore, Raoult's law turns into a unique instance of Henry’s law in which KH get to be equivalent to p10.
  • 3 answers

Himanshu Shekhar 6 years, 7 months ago

H

Gaurav Seth 6 years, 7 months ago

We know,

Kf = Molal depression constant ( 5.12 K Kg/mol)

wB = weight of the solute 

wA = weight of the solvent 

MB = Observed molar mass of the solute.

Substituting the values we get,

Calculated molecular weight of phenol = 12 x 6 + 1 x 5 + 16 + 1

  = 94 g

The association of phenol can be represented as:

Here, x is the degree of association.

The total number of particles after association

Now,

Hence, the fraction of phenol dimerized = 73%

Gaurav Seth 6 years, 7 months ago

Question: 

Phenol associates in benzene to certain extent to form a dimer. A solution that is containing 20 x 10-3kg of phenol dissolved in 1 kg of benzene has its freezing point decreased by 0.61 K. Calculate the fraction of phenol that has dimerised.

Solution:

∆ Tf = Kf wB 1000/ wA MB

0.69 = 5.12 x 20 x 10^-3 x 10^3 / 1 x MB

MB = 5.12 x 20 / 1 x 0.69

Molecular weight of phenol = 94g

Calculated M . W / observed M . W = No. of particles after association/ No. of particles before association

94 / 148.4 = 1 - x/2  /  1

x = 0.73 per mole

Fraction of C6H5OH = 0.73 x 100 = 73%

 

  • 1 answers

Gaurav Seth 6 years, 7 months ago

Cellulose acetate, potassium ferrocyanide, etc. are used as semipermeable membrane for carrying out reverse osmosis.

  • 1 answers

Antriksh Bohara 6 years, 7 months ago

scandium is a transition metal because it is found between s and p block elements , and in crystal field five degenerate d orbitals loose thier degenracy and split into two sets t2g and eg
  • 1 answers

Mehak Sharma 6 years, 7 months ago

Moles of solute per volume of soln
  • 0 answers
  • 1 answers

Himanshu Shekhar 6 years, 7 months ago

Solomon
  • 1 answers

Gaurav Seth 6 years, 7 months ago

Since in this problem ‘k’ is not given so we have to find out.

Applying Henry’s equation,S = k P

k= S/P = 6.8 X 10-4 mol L-1  =   6.8 X 10-4 mol L-1 

                            1

 So the solubility of N2 at 0.78 atm:

S= (6.8 X 10-4 mol L-1 ) (0.78 atm) = 5.3 x10-4 M

  • 2 answers

▪▪Amrit▪▪ ❤ 6 years, 7 months ago

2 hours maximum 30 min minimum

Ravikant Sharma Pandit 6 years, 7 months ago

1:30min
  • 2 answers

Nishu Sahu 6 years, 7 months ago

It is a process of formation of fluroalkane. In this chloro or bromo alkane react with metalfloride to give fluroalkane. e.g.- CH3Cl + AgF----------->CH3F + AgCl

Vineet Garg 6 years, 7 months ago

Swartz reaction CH3Br +AgF --> CH3F + AgBr
  • 1 answers

Gursharn Kaur 6 years, 7 months ago

Given weight= 2.82 g Molar mass= 180 No. Of moles= given weight/ molar mass = 0.0157 Molality= no of moles / mass × 1000 = 0.52 mol / kg No.of moles of water = 1.67 Mole fraction if glucose = 0.0157/0.0157+1.67 Mole fraction of water= 1.67/1.67+0.0157 or 1- mole fraction of glucose
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  • 0 answers
  • 3 answers

Gursharn Kaur 6 years, 7 months ago

Difference is omly about the spins and the position of subsituent attached to aromatic compound

Yogita Ingle 6 years, 7 months ago

Ortho- describes a molecule  with substituents at the 1 and 2 positions on an aromatic compound. In other words, the substituent is adjacent or next to the primary carbon on the ring.

The symbol for ortho- is o- or 1,2-<name of compound>

Para-

Para- describes a molecule with substituents at the 1 and 4 positions on an aromatic compound. In other words, the substituent is directly opposite the primary carbon of the ring.

The symbol for para- is p- or 1,4-<name of compound>

 

Abhi Saini 6 years, 7 months ago

I. Bengnene ring 1,2 position is ortho and 1,3 positiom is meta
  • 2 answers

Gursharn Kaur 6 years, 7 months ago

Simply multiple volume by density to get the value of mass put put the value of this mass in place of the volume

Sinchana Malagond 6 years, 7 months ago

Molality is equal to 1000 into molarity / density into 1000 minus molecular mass into molarity
  • 1 answers

Shubham Prajapati 6 years, 7 months ago

I think due to +m effect ..+m/-m effect doesn't show on meta.. Only or ortho and para position
  • 5 answers

Mehak Sharma 6 years, 7 months ago

To equalize the ions

Abhi Saini 6 years, 7 months ago

Yes bacause it maintain cotinuty

Harsh Kaushik 6 years, 7 months ago

to equalise the concentration of both xinc and copper

Shubham Kumar 6 years, 7 months ago

Nbb

Yogita Ingle 6 years, 7 months ago

In the electrochemical cell a salt bridge performs the following functions:

a) It allows the flow of current by completing the circuit.
b)      It maintains electrical neutrality.

  • 2 answers

Aisha Patel 6 years, 7 months ago

Finkelstein reaction is done in which sodium iodide react with alkyl halide in presence of dry acetone which gives alkyl iodide..

Yogita Ingle 6 years, 7 months ago

Treatment of a primary alkyl halide or pseudohalide with an alkali metal halide (e.g. KF, KI) leads to replacement of the halogen via an SN2 Reaction. this us called Finkelstein Reaction.

  • 1 answers

S.....Sharma☺??? .. 6 years, 7 months ago

A plane polarized light is that in which wavelenghth of every colour is same
  • 4 answers

Mehak Sharma 6 years, 7 months ago

Free energy G=-nfe

Abhi Saini 6 years, 7 months ago

_ g

Hemant Bhardwaj 6 years, 7 months ago

Free Energy present in system that can be converted into work done

Yogita Ingle 6 years, 7 months ago

Gibbs free energy is the energy needed to create a system out of nothing in an environment at both constant pressure and constant temperature.

It is defined mathematically by the equation.  

G = H - TS

Where H = heat content, S = entropy of the system, T = absolute temperature  

  • 1 answers

S.....Sharma☺??? .. 6 years, 7 months ago

The electron loving species or we can say that the proton rich species and it having positive charge and for contain stable it want electron
  • 2 answers

Sourabh Singh 6 years, 7 months ago

If the no is not in the form 0.000 then Say 468.2 Then it can be written as 4.682*10^-2 And so we can find it separately and then multiply it with each other

Sourabh Singh 6 years, 7 months ago

For finding the value of log first of all we should take a number in the form 0.000 Lets take a number 3.456 Then see the log table present at the last page of chemistry part I Now in N find first two numbers,in this case find 34 Then see the no. In the columb headed by 5 .the no.is 5378 Now the last digit is left i.e 6 Then we will see the columb headed by no. 6 in mean difference present at right side of the log table. The no is 8. Now two find its value we have to add 5378+8=5386. So now by these steps we can find log easily
  • 1 answers

Yogita Ingle 6 years, 7 months ago

The diazonium salts (di refers to ‘two’, azo is indicative of ‘nitrogen’ and ium implies that it is cationic in nature), or diazonium compounds,  are the class of organic compounds with general formula R−N2+X where X is an organic or inorganic anion (for example, Cl, Br, BF4, etc.) and R is an alkyl or aryl group. Hence, they have two nitrogen atoms with one being charged. Benzenediazonium chloride (C6H5N2+Cl), benzenediazonium hydrogensulphate (C6H5N2+HSO4), etc. are some of the examples of the diazonium salt.

  • They are ionic in nature.
  • They are water soluble.
  • Aryl diazonium salts are colorless crystalline solids.

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