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Humaira .. 6 years, 4 months ago

Bcz in case of chlorobenzene due to ( - I effect) its stability increases than cyclohexyl chloride. As we know stability is inversely proportional to dipole moment so, its d. P is lower than latter one.
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Parul Singh 6 years, 4 months ago

Ch 7
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Sia ? 6 years, 4 months ago

Noble gases being monoatomic have no inter atomic forces except weak dispersion forces and therefore, they are liquefied at very low temperatures. Hence, they have low boiling points.

Sarthak Pandey 6 years, 4 months ago

Thanks sia
  • 2 answers

Sia ? 6 years, 4 months ago

The thermal stability of hydrides decreases on moving down the group. This is due to a decrease in the bond dissociation enthalpy (H-E) of hydrides on moving down the group. Therefore,

Tannu Madaan 6 years, 4 months ago

I asked boiling point
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Sia ? 6 years, 4 months ago

You can check last year papers here : https://mycbseguide.com/cbse-question-papers.html

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Sia ? 6 years, 4 months ago

The 38 elements in groups 3 through 12 of the periodic table are called transition metals.
The Transition Metals are:

  • Scandium.
  • Titanium.
  • Vanadium.
  • Chromium.
  • Manganese.
  • Iron.
  • Cobalt.
  • Nickel.
  • 5 answers

Priya Dharshini ? 6 years, 4 months ago

NOt yet sure.. but other websites states thst it will be held at our centres..

Yash Jain 6 years, 4 months ago

At school

Řøhăň Řąjpůť ✌️✊ 6 years, 4 months ago

at centre bro

White Rat Hackers ? Ceo 6 years, 4 months ago

At centers

Anurag Yadav 6 years, 4 months ago

In centres
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Gaurav Seth 6 years, 4 months ago

Powdered substances are more effective adsorbents than their crystalline forms because when a substance is powdered, its surface area increases and physisorption is directly proportional to the surface area of the adsorbent.

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Naman Chauhan 6 years, 4 months ago

Ionization enthlpy is very high and electron gain enthlpy is zero
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Yogita Ingle 6 years, 4 months ago

The negative electron gain enthalpy is more in sulphur than in oxygen because, both of them are in 16th group in which teh oxygen is 1st element which has the minimum size and sulphur has larger size due to addition of a new shell.
So, due to smaller size the inter-electronic repulsion in compact 2p-orbitals of oxygen is much more than the repulsion in 3p-orbitals of sulphur hence, the incoming new electron feels less attraction in oxygen and more attraction in sulphur due to which the addition becomes easy and so electron gain enthalpy becomes more negative in sulphur.

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Sia ? 6 years, 4 months ago

Half-life (t1/2) for a zero order reaction, {tex}t_{1 / 2}=\frac{[R]_{0}}{2 k}{/tex}

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Sahil Kumar 6 years, 4 months ago

Take concept from ncert books and show your potential from side books like HC Verma, Oswal books etc.. For better performance in physics use side books... Solve KC Sinha's for mathematics

Kiran??? Gautam 6 years, 4 months ago

Its enough

Řøhăň Řąjpůť ✌️✊ 6 years, 4 months ago

For chemistry ncert is enough but for physics ncert + refresher...
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Yogita Ingle 6 years, 4 months ago

Wurtz reaction is carried out with sodium metal which is highly reactive, hence, we have to select a solvent which will not react with the sodium metal. Thus ether becomes the best choice. Similarly the alkyl halide should also dissolve in the solvent . The sodium halide formed should be insolulbe in the solvent which can be easily removed, and alkane formed should remain in solution,  

it requires an aprotic solvent as the medium of the reaction.Dry ether proves to be a very good non-polar, aprotic solvent for this purpose. Hence dry ether is used .

eg. CH3I ----------> CH3 - CH3  (in presence of Sodium and Dry ether)

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Řøhăň Řąjpůť ✌️✊ 6 years, 4 months ago

ΔTb= (100 + 273) - (99.63 + 273) = 0.37 K >>w1 = 500 g >>Molar mass of sucrose (C12H22O11), M2= 11 × 12 + 22 × 1 + 11 × 16 = 342 g mol^ - 1 >> Kb= 0.52 K kg mol ^- 1 put all these value in the formula ➡️ΔTb=kb*1000*w2/M2*W1 by solving this u will get ur answer 121.67 g of sucrose
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Yogita Ingle 6 years, 4 months ago

Generally atomic size decreases while moving from left to right in the periodic table. But in the case of noble gases, they have comparatively higher atomic size than corresponding halogens because of the reason that vanderwaal’s radii (present in noble gases) is much larger than ionic and covalent radii (present in other elements).

Shubham Sharma 6 years, 4 months ago

halogens have higher size than noble gases due to effective nuclear charge asociated with the respective atom.
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???? S.M. Sachin ???? 6 years, 4 months ago

Because of the water of crystallization hydrated cuso4 is blue in colour and anhydrous cuso4 is colourless. S.M.

Hemant Tiwari 6 years, 4 months ago

Due to d-d transition of electron
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Akshit Tyagi 6 years, 4 months ago

M1=0.02 mol/ l, Vs1=4l , M1=n2/ Vs1. , n2=0.08 , M2= n2/ Vs2 , M2= 0.016
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Yukta Mangla 6 years, 4 months ago

Conductivity (k)= cell constant (length l/area of cross section A)/resistance (R)

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