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Convert 5 newton to cgs unit

Posted by Nirbhav Sekhri 1 year, 11 months ago

CBSE > Class 11 > Physics

3 answers

Avishka - 1 year, 10 months ago

1N=10^5dyne 5 N=5*10^5 dyne

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Tika Ram 1 year, 11 months ago

50^5

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Naman Gupta 1 year, 11 months ago

We know that Newton is in MKS while Dyne is in CGS N2 = N1 U1/ U2 N1 5 N2 x U1 Mks U2 Cgs Putting it 5* kg m sec-2/ g Cm sec-2 (Sec cut) N2= 5* kg/g* m/Cm 5 *1000g/g *100cm/cm 5*1000*100 500000 5*10power5

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Class 11th chapter units and measurement notes

Posted by Vivek Kumar 1 year, 11 months ago

CBSE > Class 11 > Physics

2 answers

Shinjini Ghosh 1 year, 11 months ago

I think reading ncert for now is enough

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Chahat Kumar 1 year, 11 months ago

Notes please

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oxygen freeze at -216C the farnite equvalent of this lemp

Posted by Hrudananda Nayak 1 year, 11 months ago

CBSE > Class 11 > Physics

1 answers

Hrudananda Nayak 1 year, 11 months ago

anw

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Expand using binomial (1+3x)^5 upto the term having x^3

Posted by Diksha Sharma 1 year, 11 months ago

CBSE > Class 11 > Physics

2 answers

Anshika Saini 1 year, 11 months ago

Axha

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Krishna Chaudhary 2 years ago

YE thoDa Hard LaGg rHa Haii 😅... AnsWer bTa doH Bss

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Posted by Bhavishya Singh 2 years ago

CBSE > Class 11 > Physics

1 answers

Swastik Singh 2 years ago

Welcome

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4.0m ______cm

Posted by Pooja Verma😚🥰😉😘👩‍🏫‍ 2 years ago

CBSE > Class 11 > Physics

5 answers

Pari Jain 1 year, 11 months ago

400cm

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Aadil Reshie 1 year, 11 months ago

Four hundred centi meters

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Astha Patel 2 years ago

400 cm

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Swastik Singh 2 years ago

400 cm

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Kartik Kushwaha 2 years ago

400 cm

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A wire of 10 m and diameter 2mm hanging vertically is loaded by 6.28kg mass . If it elongates by 1mm find young modulus

Posted by Jacks Jacks 2 years ago

CBSE > Class 11 > Physics

2 answers

Jagdish Shukla 1 year, 11 months ago

Answer is 5

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Ayush Singh 2 years ago

Sghcuedyeydydhtwydhbdhehh hdf.fgsygdeur hdyydfufurufduydfhdhddhhddhhdhdhddhdhdhdudhudeyeuueeye6eydyhhnctirudhhdfjdhhddhdhdhdhhhdhhddhddxhcggfyjghigryre

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Why current remains same after passing through a resister

Posted by Harshita Sharma 2 years ago

CBSE > Class 11 > Physics

1 answers

Arnav Gupta 2 years ago

Because resistors are conductors

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Does the function sin w.t-cos w.t represent simple harmonic motion.if yes mention the time period.

Posted by Shobhit Srivastava 2 years ago

CBSE > Class 11 > Physics

0 answers

ANSWER

What is order of magnitude

Posted by Aditya Raj 2 years ago

CBSE > Class 11 > Physics

0 answers

ANSWER

Angular movementum is

Posted by Aanchal Kumari 2 years ago

CBSE > Class 11 > Physics

3 answers

Aashna Meena 1 year, 10 months ago

nh/2π

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Kripa Shankar Gupta 2 years ago

Torque

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Jupile Chenoha 2 years ago

hhhhhhi

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Which of the following is incorrect about non uniform circular motion

Posted by Vanshika Mathur 2 years ago

CBSE > Class 11 > Physics

0 answers

ANSWER

Explain Newton's formula for speed of sound in air

Posted by Ayush Diwakar 2 years ago

CBSE > Class 11 > Physics

1 answers

Preeti Dabral 2 years ago

According to Newton the change in pressure & volume in air is an isothermal process.
Therefore he calculated,v =√(p/p) on substituting the require value he found, the velocity of sound was not in close agreement with the observation value. Then Laplace pointed out the error in Newton’s formula. According to Laplace the change in pressure and volume is an adiabatic process. So he calculated the value of sound as, v =√(yr/p) on putting require value he found velocity of sound as 332m/s very closed to observed theory.

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A stone of mass 2kg is projected upwards with kinetic energy of 98J. The height at which the kinetic energy of the body becomes half of it's original value will be

Posted by Ruchi Yadav 2 years ago

CBSE > Class 11 > Physics

1 answers

Preeti Dabral 2 years ago

Solution is given below:

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A car starts from rest and accelerates at t m/s at t=4 a ball is dropped out of a window by a person sitting in the car .what is the velocity and acceleration of ball at t=6?

Posted by Krishnapriya Nair 2 years ago

CBSE > Class 11 > Physics

0 answers

ANSWER

Derivation of time period of loaded spring

Posted by Monisha Malgotra 2 years ago

CBSE > Class 11 > Physics

1 answers

Preeti Dabral 2 years ago

You need to know the equation of motion. The force for the pendulum is given by F=−kx. Newtons equation tell you F=ma=mx¨. So you need to solve

mx¨=−kx.(1)

You know that the solution will be of oscillatory form. So you set x=Acos(2πt/T) and you want to obtain T. Plugging this ansatz into the equation (1), you obtain

−m(2π)2T2Acos(2πt/T)=−kAcos(2πt/T).

You see that the equation is fulfilled if

m(2π)2T2=k.

Solving for T, you obtain the result.

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ANSWER

When an external force is not applied to the system its total momentum

Posted by Ruhi Deshmukh 2 years ago

CBSE > Class 11 > Physics

1 answers

𝕷𝖊𝖌𝖊𝖓𝖉 🏆 🍑 🎀 𝒜𝓁☯𝓃𝑒 𝑅𝒶𝓈𝒽𝒾 🎀 🍑 2 years ago

If no external forces acts on a system of particles then the momentum of the system remains conserved.

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The number of significants in 501.040 is

Posted by Khush Dandiwal 2 years, 1 month ago

CBSE > Class 11 > Physics

4 answers

Preeti Dabral 2 years, 1 month ago

0Thank You

Shinjini Ghosh 1 year, 11 months ago

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Harsh Maurya 2 years ago

Ans=6

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M.S.Bhati Bhati 2 years ago

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On the basis of dimensional consideration write the formula for speed of transfer way on a string and in a solid

Posted by Harshita Mehta 2 years, 1 month ago

CBSE > Class 11 > Physics

1 answers

Preeti Dabral 2 years, 1 month ago

Speed of a transverse wave on a stretched string. The wave velocity through a medium depends on its inertial and elastic properties. So the transverse wave through a stretched string is determined by two factors:

Tension T in the string is a measure in the string. Without tension no can propagate in the string. of elasticity disturbance Dimensions of T = [Force] = [MLT²]
Mass per unit length or linear mass density m of the string so that the string can store kinetic energy.
Dimensions of $m=\frac{[\text { Mass }]}{[\text { Length }]}=\left[\mathrm{ML}^{-1}\right]$
Now, dimensions of ratio $\frac{T}{m}=\frac{\left[\mathrm{MLT}^{-2}\right]}{\left[\mathrm{ML}^{-1}\right]}=\left[\mathrm{L}^{2} \mathrm{~T}^{-2}\right]$
As the speed v has the dimensions [LT^-1] so we can express v in terms of T and m as $v=C \sqrt{\frac{T}{m}}$
From detailed mathematical analysis! or from experiments, the dimensionless constant C = 1. Hence the speed of transverse waves on a stretched string is given by
$v=\sqrt{\frac{T}{m}}$

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ANSWER

Define shm find experience for displacement velocity acceleration

Posted by Anshu K 2 years, 1 month ago

CBSE > Class 11 > Physics

1 answers

Preeti Dabral 2 years, 1 month ago

Simple harmonic motion is an oscillatory motion in which the particle's acceleration and force are directly proportional to its displacement from the mean location at each point. It is a special case of oscillatory motion.

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ANSWER

State and prove bernoullis theorm.

Posted by S S 2 years, 1 month ago

CBSE > Class 11 > Physics

2 answers

Preeti Dabral 2 years, 1 month ago

Bernoulli's principle states that an increase in the speed of a fluid occurs simultaneously with a decrease in static pressure or a decrease in the fluid's potential energy.
To prove Bernoulli's theorem, consider a fluid of negligible viscosity moving with laminar flow. as shown in Figure.
Let the velocity, pressure and area of the fluid cloumn be p₁, v₁ and A₁ at Q and p₂, v₂ and A₂ at R. Let the volume bounded by Q and R move to S and T where QS = L₁, and RT = L₂

If the fluid is incompressible:
The work done by the pressure difference per unit volume = gain in kinetic energy per unit volume + gain in potential energy per unit volume. Now:
A₁L₁ = A₂L₂
Work done is given by:
W = F $\times$ d = p $\times$ volume
$\Rightarrow$ W_net = p₁ - p₂
$\Rightarrow$ K.E = $\frac{1}{2}$ mv² = $\frac{1}{2}$ V $\rho$ v² = $\frac{1}{2}$ $\rho$ v² ( $\because$ V = 1)
$\Rightarrow$ K.E_gained = $\frac{1}{2} \rho\left(v_{2}^{2}-v_{1}^{2}\right)$
P₁ + $\frac{1}{2} \rho v_{1}^{2}$ + $\rho$ gh₁ = P₂ + $\frac{1}{2} \rho v_{2}^{2}$ + $\rho$ gh₂
$\therefore$ P + $\frac{1}{2} \rho v^{2}$ + $\rho$ gh = const.
For a horizontal tube
$\because$ h₁ = h₂
$\therefore$ P + $\frac{1}{2} \rho v^{2}$ = const.
Therefore, this proves Bernoulli's theorem. Here we can see that if there is an increase in velocity there must be a decrease in pressure and vice versa.