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Ask QuestionPosted by Aaron Chacko 4 years, 4 months ago
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Posted by Madhu Jha 4 years, 4 months ago
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Kavyanjali Singh 4 years, 4 months ago
Khushi Tripathi 4 years, 4 months ago
Posted by Class 12 4 years, 4 months ago
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Aaron Chacko 4 years, 4 months ago
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Gaurav Seth 4 years, 4 months ago
given that,
Two vectors p and q are the sum of 18 and resultant is 12
here,
we have,
sum of magnitude of vector = 18
so,
p + q = 18 ... (1)
and sum of both vectors I. e. resultant = 12
so,
p^-> + q^-> = 12 = R
Now,
ACCORDING TO THE FIGURE,
R² = p² + q² + 2pq cosθ
given R = 12
so,
12² = p² + q² + 2pq cosθ .... (2)
now,
here, since the resultant is perpendicular
so,
value of α = 90°
so,
tanα =
so,
tan90.=
so,
p + qcosθ = 0
qcosθ = -p
now,
putting the value of qcosθ on (2)
12² = p² + q² + 2pqcosθ
144 = p² + q² + 2p(-p)
144 = p² + q² - 2p²
q² - p² = = 144
using algebraic identity
a² - b² = (a + b)(a - b)
so,
(q + p)(q - p) = 144
now
from eqn (1)
p + q = 18
putting the values,
18(q - p) = 144
q - p = 144/18
q - p = 8 .....(3)
now,
we have,
q + p = 18 ..(1)
q - p = 8 ...(3)
adding of both equations
q + p + q - p = 18 + 8
2q = 26
q = 26/2
q = 13
now,
putting the value of q in (1)
p + q = 18
p + 13 = 18
p = 18 - 13
p = 5
q = 13
now,
putting the value of p and q on (2)
p² + q² + 2pqcosθ = 144
(5)² + (13)³ + 2(5)(13)cosθ = 144
25 + 169 + 130cosθ = 144
194 + 130cosθ = 144
130cosθ = 144 - 194
130cosθ = -50
cosθ = -50/130
cosθ = -5/13
Posted by Shashi Kumar Suman 4 years, 4 months ago
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Yogita Ingle 4 years, 4 months ago
Dynamics, branch of physical science and subdivision of mechanics that is concerned with the motion of material objects in relation to the physical factors that affect them: force, mass, momentum, energy.
Posted by Nyra Sharma 4 years, 4 months ago
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Gaurav Seth 4 years, 4 months ago
▶ Given : x = (t - 2)
At t = 0 : x = xo = (0-2)^2 = 4m
At t = 1s : x = x1 = (1-2)^2 = 1m
At t = 2s : x = x2 = (2-2)^2 = 0m
At t = 3s : x = x3 = (3-2)^2 = 1m
At t = 4s : x = x4 = (4-2)^2 = 4m
Posted by Harkomal Pannu 4 years, 4 months ago
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Yogita Ingle 4 years, 4 months ago
The given quantity is 0.007 m2.
If the number is less than one, then all zeros on the right of the decimal point (but left to the first non-zero) are insignificant. This means that here, two zeros after the decimal are not significant. Hence, only 7 is a significant figure in this quantity.
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Manish Nailwal 4 years, 4 months ago
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