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Yogita Ingle 5 years, 2 months ago
Parallax is a displacement or difference in the apparent position of an object viewed along two different lines of sight, and is measured by the angle or semi-angle of inclination between those two lines. Distance between the two viewpoints is called Basis.
Measuring distance of a planet using parallax method

Similarly, α = d/D
Whereα = angular size of the planet (angle subtended by d at earth) and d is the diameter of the planet.αis angle between the direction of the telescope when two diametrically opposite points of the planet are viewed.
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Hiteswari Gadtia 5 years, 2 months ago
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Gaurav Seth 5 years, 2 months ago
|
Distance |
Displacement |
|
1. It is the length of path traversed by the object in a certain time.
2. It is a scalar quantity that is it has only the magnitude.
3. It depends on the path followed by the object.
4. It is always positive.
5. It can be more than or equal to the magnitude of displacement |
It is the distance traveled by the object in a specified direction in a certain time (that is the distance between the final and initial positions).
It is a vector quantity that is it has both the magnitude and direction.
It does not depend on the path followed by the object.
It can be positive, negative and even zero.
Its magnitude can be less than or equal to the distance |
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Yogita Ingle 5 years, 2 months ago
Given,
distance covered in 2nd s = 20 m
distance covered in 4th s = 30 m
We know,
Snth = u + a(2n - 1)/2
=> S2nd = u + a(2*2 - 1)
=> 20 = u+ 3a/2
=>20 = (2u+3a)/2
=>40 = 2u + 3a ------------- (1)
Again,
S4th = u + a(2*4 -1)/2
=>30 = u + 7a/2
=>30 = (2u + 7a)/2
=>60 = 2u + 7a --------------(2)
(1) - (2)
=>2u + 3a -2u -7a = 40 - 60
=> -4a = -20
=>a = 5
Putting the value of a in eq (1), we get,
=>2u + 3(5) = 40
=>2u = 40 -15
=>u = 25/2
Now,
S6th = u+ a(2n -1)
=>S6th = 25/2 + 5(2*6 -1)/2
=>S6th = 25/2 + 5*11/2
=>S6th = 25/2 + 55/2
=>S6th = 80/2
=>S6th = 40
Hence , distance covered in the 6th s = 40 m
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Meghna Thapar 5 years, 2 months ago
The SI unit of work is the joule (J), which is defined as the work expended by a force of one newton through a displacement of one metre. Absolute units: (i) SI System - Joule is the unit of work in SI system. ... (ii) CGS system – CGS unit of work is erg. Work done is said to be 1 erg if a force of one dyne displaces the body by 1 cm in the direction of force applied.
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Ahadul Laskar 5 years, 2 months ago
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