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Ask QuestionPosted by Lochan Soni 8 years, 7 months ago
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Posted by Lochan Soni 8 years, 7 months ago
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Naveen Sharma 8 years, 7 months ago
Ans. The diameter of the Milky Way galaxy is about 9.5 x 1017 Km
Posted by Lochan Soni 8 years, 7 months ago
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Naveen Sharma 8 years, 7 months ago
Ans. We know v = u + at
so a is velocity and b is accelaration.
So dimension of a = dimension of velocity = [M0L1T-1]
Dimension of b = dimension of accelaration = [M0L1T-2]
Posted by Lochan Soni 8 years, 7 months ago
- 1 answers
Posted by Lochan Soni 8 years, 7 months ago
- 1 answers
Posted by Lochan Soni 8 years, 7 months ago
- 1 answers
Naveen Sharma 8 years, 7 months ago
Ans. Mass of body = 22.42 g
Volume of body = 4.7 cc
Density = {tex}{mass\over volume } = {22.42\over 4.7}{/tex} = 4.77021 g/cm3
Error in measurement of mass = 0.01 g
So Mass = 22.42 - 0.01 = 22.41 g
Error in measurement of Volume = 0.1 cc
So Volume = 4.7 - 0.1 = 4.6 cc
Now Density = {tex}{mass\over volume } = {22.41\over 4.6}{/tex} = 4.87174 g/cm3
Error in Density = 4.87174 - 4.77021 = 0.10153 g/cm3
%/ error = {tex}{0.10153\over 4.77021}\times 100{/tex}
= {tex}0.02128 \times 100 = 2.128 \% = 2.1\%{/tex}
Posted by Lochan Soni 8 years, 7 months ago
- 1 answers
Posted by Lochan Soni 8 years, 7 months ago
- 2 answers
Arun Soni 8 years, 5 months ago
{tex} \eqalign{ & Here,\theta = 1\min = \frac{1}{{60}} \times \frac{\pi }{{180}} \cr & \ r = \frac{l}{\theta } \cr & l = 2 \times 6400 \times {10^3}m \cr &\Rightarrow r = \frac{{2 \times 6400 \times {{10}^3} \times 60 \times 180}}{\pi } \approx 4.4 \times {10^{10}}m \cr & 1A.U = 1.5 \times {10^{11}}m \cr &\Rightarrow r = \frac{{4.4 \times {{10}^{10}}}}{{1.5 \times {{10}^{11}}}} \approx 0.29AU \cr}{/tex}
Arun Soni 8 years, 5 months ago
{tex} \eqalign{ & Here,\theta = 1\min = \frac{1}{{60}} \times \frac{\pi }{{180}} \cr & \Rightarrow r = \frac{l}{\theta } \cr & l = 2 \times 6400 \times {10^3}m \cr & \Rightarrow r = \frac{{2 \times 6400 \times {{10}^3} \times 60 \times 180}}{\pi } \approx 4.4 \times {10^{10}}m \cr & 1A.U = 1.5 \times {10^{11}}m \cr &\Rightarrow r = \frac{{4.4 \times {{10}^{10}}}}{{1.5 \times {{10}^{11}}}} \approx 0.29AU \cr}{/tex}
Posted by Lochan Soni 8 years, 7 months ago
- 1 answers
Payal Singh 8 years, 7 months ago
Frequency is associated with this dimensional equation.
Frequency = {tex}1\over Time \space Period {/tex}
Posted by Lochan Soni 8 years, 7 months ago
- 1 answers
Payal Singh 8 years, 7 months ago
Principle of homogenity of dimensions states that “For an equation to be dimansionally correct, the dimensions of each term on LHS must be equal to the dimensions of each term on RHS.”
Posted by Lochan Soni 8 years, 7 months ago
- 1 answers
Payal Singh 8 years, 7 months ago
A proton has positive charge of 1, that is, equal but opposite to the charge of an electron.
Posted by Lochan Soni 8 years, 7 months ago
- 1 answers
Payal Singh 8 years, 7 months ago
Three physical quantities having same dimensions can be Work, Kinetic Energy and Potential Energy as all of them have dimensions [M1L2T-2].
Posted by Lochan Soni 8 years, 7 months ago
- 1 answers
Govind Singh 7 years, 10 months ago
{tex}Radius = \frac{{1.933}}{2} = 0.9665 = 0.966cm{/tex}
Posted by Lochan Soni 8 years, 7 months ago
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Payal Singh 8 years, 7 months ago
One parsec is the distance at which one astronomical unit subtends an angle of one arcsecond. A parsec is equal to about 3.26 light-years (31 trillion kilometres or 19 trillion miles) in length.
Posted by Lochan Soni 8 years, 7 months ago
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Posted by Lochan Soni 8 years, 7 months ago
- 1 answers
Payal Singh 8 years, 7 months ago
Side of cube = 7.203m
Surface area of cube = {tex}6\times (side)^2{/tex}
= {tex}6\times 7.203\times 7.203{/tex}
= {tex}6\times 51.883209{/tex}
= 311.299254
= 311.299
Posted by Lochan Soni 8 years, 7 months ago
- 1 answers
Payal Singh 8 years, 7 months ago
The dimensions of gravitational constant : {tex}L^3M^{-1}T^{-2}{/tex}
Posted by Lochan Soni 8 years, 7 months ago
- 1 answers
Payal Singh 8 years, 7 months ago
The most accurate measure is 0.005 mm. This is because the value has been measured up to three decimal places unlike the other two values. This means that 0.005 mm is actually closer to the value being measured than the other values as compared to the values that they represent.
You can also check the same by writtng all these in scientific notation.
Posted by Lochan Soni 8 years, 7 months ago
- 1 answers
Payal Singh 8 years, 7 months ago
1 hour = 3600s
1 Km = 1000 m
distance covered in 3600 seconds = 72000m
Distance covered in 1 second = {tex}{72000\over 3600 } = 20m{/tex}
So it is 20m/s
Posted by Lochan Soni 8 years, 7 months ago
- 1 answers
Payal Singh 8 years, 7 months ago
% error in measuring radius dr = 0.3%
Volume of sphere V = {tex}{4\over 3}\pi r^3{/tex}
Differentiate w.r.t to r, we get
{tex}{dV\over dr} = 4\pi r^2{/tex}
{tex}dV = 4\pi r^2dr{/tex}
% error in measuring Volume = {tex}{dV\over V}\times 100{/tex}
={tex}{4\pi r^2dr\over 4\pi r^2}\times 3\times 100 {/tex}
= {tex}3dr\times 100{/tex}
= {tex}3\times 0.3\times 100\over 100{/tex}= 0.9%
Posted by Lochan Soni 8 years, 7 months ago
- 1 answers
Arun Soni 8 years, 5 months ago
{tex}\eqalign{ & Given{\text{ D = 1}}{\text{.496}} \times {\text{1}}{{\text{0}}^{11}}m \cr & \theta = {19^ \circ }{20^{''}} = {(\frac{{1920}}{{60 \times 60}})^{^ \circ }} = {0.53^{^ \circ }} \cr & {\text{converting it to radian}} \cr & {\text{0}}{\text{.53}} \times \frac{\pi }{{180}} = 0.53 \times \frac{{3.142}}{{180}} = 0.0093{\text{ rad}} \cr & As{\text{ }}\theta {\text{ is too small, we can assume triangle as right angle triangle}} \cr & {\text{we know d = D tan}}\theta \cr & {\text{As }}\theta {\text{ is small we can take tan}}\theta \approx \theta \cr & \Rightarrow {\text{d = D}}\theta \cr & \therefore d = 1.496 \times {10^{11}} \times 0.0093 = 1.39 \times {10^9}{\text{ m}} \cr} {/tex}
Posted by Lochan Soni 8 years, 7 months ago
- 1 answers
Posted by Lochan Soni 8 years, 7 months ago
- 1 answers
Shweta Choudhary 8 years, 7 months ago
Light year is the unit of length used to express astronomical distance .
Posted by Lochan Soni 8 years, 7 months ago
- 1 answers
Payal Singh 8 years, 7 months ago
Radius of sphere = 11.24 cm
Surface area of sphere = {tex}4\pi r^2{/tex}
={tex}{4\times 22\times 11.24 \times 11.24\over 7} = {1588.24}cm^2{/tex}
Posted by Lochan Soni 8 years, 7 months ago
- 1 answers
Posted by Lochan Soni 8 years, 7 months ago
- 1 answers
Shweta Choudhary 8 years, 7 months ago
Atomic mass unit is defined as the mass equal to exactly one -twelfth (1/12th) of the mass of an atom of carbon- 12.
Posted by Lochan Soni 8 years, 7 months ago
- 1 answers
Arun Soni 8 years, 5 months ago
The least count error is the error associated with the resolution of the instrument.
For example, a metre rod can measure length accurately up to 0.1 cm, whereas vernier callipers can measure length accurately up to 0.01 cm
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Rupender Singh 8 years, 7 months ago
1 joule = 10000000 erg
2Thank You