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  • 3 answers

Bhawani Tanwar 8 years, 3 months ago

HC verma

Divya Kumari 8 years, 3 months ago

HC verma

Rajnish Kumar 8 years, 3 months ago

Sl simplfied for questions and concepts both
  • 1 answers

Sahdev Sharma 8 years, 3 months ago

Mass of the shell, M = 40 kg

Speed of the shell, u = 72 km/h = 20 m/s

Initial momentum of the shell, Pi = Mu = (40)(20) = 800 kg-m/s

After it breaks, the masses of the parts are 15 kg and 25 kg. The 15 kg piece stops. Let the speed of the other piece be ‘v’.

So, total momentum after breaking apart, Pf = (15)(0) + (25)(v) = 25v

Now, by law of conservation of momentum,

Pf = Pi

=> 25v = 800

=> v = {tex}800\over 25{/tex} = 32 m/s

This is the speed of the other piece.

  • 1 answers

Harsh Rajput 8 years, 3 months ago

Kisi bhi point par jab net force 0 lagta h to usse equibrillium kahte h.
  • 1 answers

Shivaditya Pandey 8 years, 3 months ago

No.. Never can speed of a body be negative.
  • 1 answers

Ankit Kumar 8 years, 3 months ago

2sinx.cosx
  • 1 answers

Tarun Kumar 8 years, 3 months ago

Path of the projectile
  • 2 answers

Swarnali Mondal 8 years, 3 months ago

Kicking of football

Bhawani Tanwar 8 years, 3 months ago

When we hit or punch a wall.
  • 0 answers
  • 1 answers

Swarnali Mondal 8 years, 3 months ago

Bomb dropped from an aeroplane is an example of horizontal projectile. Javelin throwing is an example of oblique projectile.
  • 1 answers

Rudranshu Mishra 8 years, 3 months ago

It is difficult to walk on sand becoz when we push d sand with r feet it doesn't react back with d same force becoz d particles of sand r very loosely arranged therefore it gets spread..and can't generate d lift up which is needed by which we can move easily.
  • 0 answers
  • 1 answers

Amar Kumar 8 years, 3 months ago

In case of an accident, the high momentum of fast moving vehicle reduced to zero in a very short interval. Due to this a large force or impact is occured and it may be possible that we get an injury or bone may be broken.

  • 1 answers

Sahdev Sharma 8 years, 3 months ago

Let {tex}\theta {/tex} be the angle between the two vectors A and B such that, |A| = |B|.

Therefore, {tex}R ^2 = A ^2 + B ^2 + 2AB cos\theta{/tex}

{tex}=> A^2 = A ^2 + A ^2 + 2AAcos\theta{/tex}

[{tex}\because {/tex} |A| = |B| = |R|]

{tex}=> A^ 2 = 2A^ 2 + 2A ^2 cos\theta {/tex}

{tex}=> cos\theta ={ -1\over 2}\\ => \theta = 120^°{/tex}

  • 1 answers

Arnav Singh 8 years, 3 months ago

The unit which does not depend upon another unit for its measurement is known as fundamental unit
  • 0 answers
  • 3 answers

Pranav Choudhary 8 years, 3 months ago

R= P+Q

Pranav Choudhary 8 years, 3 months ago

When two vectors p and Q are added they give the the resultant vector

Pranav Choudhary 8 years, 3 months ago

R=root under a^2+b^2+cos thita
  • 1 answers

Swarnali Mondal 8 years, 3 months ago

K. E. = 1/2 mv^2 Multiplying 2m on both the sides, we get 2mK.E =1/2mv^2×2m 2mK.E = m^2v^2 mv = root under 2mK.E.
  • 1 answers

Shubham Singh 8 years, 3 months ago

it is external force exerted by body on the object

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