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Naveen Sharma 8 years, 3 months ago
Because we need to measure very very small changes in the stars’ positions.
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Swarnali Mondal 8 years, 3 months ago
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Amar Kumar 8 years, 3 months ago
The circular shape of the tyre is the most suitable shape for faster rolling on the roads and also only point of contact between vehicle & the road.
The circle shape is the shape that provides the least rolling resistance therefore it provides the least loss of energy when converting rotational energy to linear kinetic energy.
Any shape other than a circle is going to present points that dig into the surface you are trying to traverse and require extra energy to undig.
However the circle shape does dig into a surface so resistance caused by gravity does not have to be opposed.
Posted by Abhinav Bhattacharyya 8 years, 3 months ago
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Naveen Sharma 8 years, 3 months ago
Consider the distance traveled by the body over a small time increment Δ<i>t</i>:

We can calculate the arc length <i>s</i> as both the distance traveled (distance = rate * time = <i>v</i> Δ<i>t</i>) and using the definition of a radian (arc = radius * angle in radians = <i>r</i> Δ<i>θ</i>:)

The angular velocity of the object is thus <i>v</i> / <i>r</i> (in radians per unit of time.)
The right half of the diagram is formed by putting the tails of the two <i>v</i> vectors together. Note that Δ<i>θ</i> is the same in both diagrams.

Posted by Shivam Sinha 8 years, 3 months ago
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Amar Kumar 8 years, 3 months ago
Kinematics is a branch of classical mechanics that describes the motion of points, bodies (objects), and systems of bodies (groups of objects) without considering the mass of each or the forces that caused the motion.
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Naveen Sharma 8 years, 3 months ago
it is because when we pull/push a lawn mower, we apply a force in the direction of its handle which is at an angle with the ground. So there is always a component of force normal to the ground.
Thus when we pull, we reduce the net normal acting on the ground and thus reduce the frictional force and making it easier to pull, but when we push, we add to the normal force.
Posted by Nilesh Kumar Rai 8 years, 3 months ago
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Naveen Sharma 8 years, 3 months ago
Variation in value of at higher altitude is given as, {tex}g_h = g\left ( 1-{2h\over R}\right ){/tex}
Here,gh is the value of acceleration due to gravity at height h above the surface of the Earth. Also, R is the radius of Earth.
Using it in the relation, we get,
{tex}{g\over 2} = g\left (1-{2h\over r}\right )\\=> {2h\over R} = {1\over 2}\\=> h = {R\over 4}{/tex}
Thus value of g will be its half at the height = {tex}{R\over 4}{/tex}, above the surface of the Earth, where R is the Radius of Earth.
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Rahul Sharma 8 years, 3 months ago
1Thank You